結果
| 問題 |
No.952 危険な火薬庫
|
| コンテスト | |
| ユーザー |
emthrm
|
| 提出日時 | 2019-12-16 14:12:55 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 263 ms / 2,000 ms |
| コード長 | 4,255 bytes |
| コンパイル時間 | 1,359 ms |
| コンパイル使用メモリ | 129,084 KB |
| 最終ジャッジ日時 | 2025-01-08 11:46:41 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 23 |
ソースコード
#include <algorithm>
#include <bitset>
#include <cassert>
#include <cctype>
#include <chrono>
#define _USE_MATH_DEFINES
#include <cmath>
#include <cstring>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;
#define FOR(i,m,n) for(int i=(m);i<(n);++i)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(),(v).end()
const int INF = 0x3f3f3f3f;
const long long LINF = 0x3f3f3f3f3f3f3f3fLL;
const double EPS = 1e-8;
const int MOD = 1000000007;
// const int MOD = 998244353;
const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};
// const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1},
// dx[] = {0, -1, -1, -1, 0, 1, 1, 1};
struct IOSetup {
IOSetup() {
cin.tie(nullptr);
ios_base::sync_with_stdio(false);
cout << fixed << setprecision(20);
cerr << fixed << setprecision(10);
}
} iosetup;
/*-------------------------------------------------*/
template <typename T>
struct CHT {
using Line = pair<T, T>;
CHT(bool is_minimized = true) : is_minimized(is_minimized) {}
void add(T a, T b) {
Line now(a, b);
if (deq.empty()) {
deq.emplace_back(now);
} else if (deq.back().first <= a) {
if (deq.back().first == a) {
if (is_minimized) {
if (b >= deq.back().second) return;
deq.pop_back();
} else {
if (b <= deq.back().second) return;
deq.pop_back();
}
}
while (deq.size() >= 2 && !is_necessary(deq[deq.size() - 2], deq.back(), now)) deq.pop_back();
deq.emplace_back(now);
} else {
if (deq.front().first == a) {
if (is_minimized) {
if (b >= deq.front().second) return;
deq.pop_front();
} else {
if (b <= deq.front().second) return;
deq.pop_front();
}
}
while (deq.size() >= 2 && !is_necessary(now, deq[0], deq[1])) deq.pop_front();
deq.emplace_front(now);
}
}
T query(T x) {
int lb = -1, ub = deq.size() - 1;
while (ub - lb > 1) {
int mid = (lb + ub) >> 1;
if (is_minimized) {
(f(deq[mid], x) < f(deq[mid + 1], x) ? ub : lb) = mid;
} else {
(f(deq[mid], x) > f(deq[mid + 1], x) ? ub : lb) = mid;
}
}
return f(deq[ub], x);
}
T monotone_inc_query(T x) {
if (is_minimized) {
while (deq.size() >= 2 && f(deq[deq.size() - 2], x) <= f(deq.back(), x)) deq.pop_back();
return f(deq.back(), x);
} else {
while (deq.size() >= 2 && f(deq[0], x) <= f(deq[1], x)) deq.pop_front();
return f(deq.front(), x);
}
}
T monotone_dec_query(T x) {
if (is_minimized) {
while (deq.size() >= 2 && f(deq[0], x) >= f(deq[1], x)) deq.pop_front();
return f(deq.front(), x);
} else {
while (deq.size() >= 2 && f(deq[deq.size() - 2], x) >= f(deq.back(), x)) deq.pop_back();
return f(deq.back(), x);
}
}
private:
bool is_minimized;
deque<Line> deq;
using Real = long double;
bool is_necessary(const Line &l1, const Line &l2, const Line &l3) {
Real lhs = static_cast<Real>(l3.second - l2.second) / (l2.first - l3.first);
Real rhs = static_cast<Real>(l2.second - l1.second) / (l1.first - l2.first);
// T lhs = (l1.first - l2.first) * (l3.second - l2.second);
// T rhs = (l2.first - l3.first) * (l2.second - l1.second);
return is_minimized ? lhs < rhs : lhs > rhs;
}
T f(const Line &l, T x) { return l.first * x + l.second; }
};
int main() {
int n; cin >> n;
vector<long long> a(n + 1, 0); FOR(i, 1, n + 1) cin >> a[i];
FOR(i, 2, n + 1) a[i] += a[i - 1];
vector<vector<long long> > dp(n + 2, vector<long long>(n + 1, -LINF));
dp[0][0] = 0;
FOR(i, 1, n + 2) dp[i][i - 1] = (a[i - 1] - a[0]) * (a[i - 1] - a[0]);
FOR(i, 1, n + 1) {
CHT<long long> cht;
for (int k = 0; i + k <= n; ++k) {
cht.add(-a[i + k] * 2, dp[i + k][k] + a[i + k] * a[i + k]);
dp[i + k + 1][k] = cht.monotone_inc_query(a[i + k]) + a[i + k] * a[i + k];
}
}
FOR(j, 1, n + 1) cout << dp[n + 1][j] << '\n';
return 0;
}
emthrm