結果
問題 | No.952 危険な火薬庫 |
ユーザー | 👑 emthrm |
提出日時 | 2019-12-16 14:12:55 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 263 ms / 2,000 ms |
コード長 | 4,255 bytes |
コンパイル時間 | 1,359 ms |
コンパイル使用メモリ | 129,084 KB |
最終ジャッジ日時 | 2025-01-08 11:46:41 |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
#include <algorithm> #include <bitset> #include <cassert> #include <cctype> #include <chrono> #define _USE_MATH_DEFINES #include <cmath> #include <cstring> #include <ctime> #include <deque> #include <functional> #include <iomanip> #include <iostream> #include <iterator> #include <map> #include <numeric> #include <queue> #include <set> #include <sstream> #include <stack> #include <string> #include <tuple> #include <utility> #include <vector> using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() const int INF = 0x3f3f3f3f; const long long LINF = 0x3f3f3f3f3f3f3f3fLL; const double EPS = 1e-8; const int MOD = 1000000007; // const int MOD = 998244353; const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; // const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1}, // dx[] = {0, -1, -1, -1, 0, 1, 1, 1}; struct IOSetup { IOSetup() { cin.tie(nullptr); ios_base::sync_with_stdio(false); cout << fixed << setprecision(20); cerr << fixed << setprecision(10); } } iosetup; /*-------------------------------------------------*/ template <typename T> struct CHT { using Line = pair<T, T>; CHT(bool is_minimized = true) : is_minimized(is_minimized) {} void add(T a, T b) { Line now(a, b); if (deq.empty()) { deq.emplace_back(now); } else if (deq.back().first <= a) { if (deq.back().first == a) { if (is_minimized) { if (b >= deq.back().second) return; deq.pop_back(); } else { if (b <= deq.back().second) return; deq.pop_back(); } } while (deq.size() >= 2 && !is_necessary(deq[deq.size() - 2], deq.back(), now)) deq.pop_back(); deq.emplace_back(now); } else { if (deq.front().first == a) { if (is_minimized) { if (b >= deq.front().second) return; deq.pop_front(); } else { if (b <= deq.front().second) return; deq.pop_front(); } } while (deq.size() >= 2 && !is_necessary(now, deq[0], deq[1])) deq.pop_front(); deq.emplace_front(now); } } T query(T x) { int lb = -1, ub = deq.size() - 1; while (ub - lb > 1) { int mid = (lb + ub) >> 1; if (is_minimized) { (f(deq[mid], x) < f(deq[mid + 1], x) ? ub : lb) = mid; } else { (f(deq[mid], x) > f(deq[mid + 1], x) ? ub : lb) = mid; } } return f(deq[ub], x); } T monotone_inc_query(T x) { if (is_minimized) { while (deq.size() >= 2 && f(deq[deq.size() - 2], x) <= f(deq.back(), x)) deq.pop_back(); return f(deq.back(), x); } else { while (deq.size() >= 2 && f(deq[0], x) <= f(deq[1], x)) deq.pop_front(); return f(deq.front(), x); } } T monotone_dec_query(T x) { if (is_minimized) { while (deq.size() >= 2 && f(deq[0], x) >= f(deq[1], x)) deq.pop_front(); return f(deq.front(), x); } else { while (deq.size() >= 2 && f(deq[deq.size() - 2], x) >= f(deq.back(), x)) deq.pop_back(); return f(deq.back(), x); } } private: bool is_minimized; deque<Line> deq; using Real = long double; bool is_necessary(const Line &l1, const Line &l2, const Line &l3) { Real lhs = static_cast<Real>(l3.second - l2.second) / (l2.first - l3.first); Real rhs = static_cast<Real>(l2.second - l1.second) / (l1.first - l2.first); // T lhs = (l1.first - l2.first) * (l3.second - l2.second); // T rhs = (l2.first - l3.first) * (l2.second - l1.second); return is_minimized ? lhs < rhs : lhs > rhs; } T f(const Line &l, T x) { return l.first * x + l.second; } }; int main() { int n; cin >> n; vector<long long> a(n + 1, 0); FOR(i, 1, n + 1) cin >> a[i]; FOR(i, 2, n + 1) a[i] += a[i - 1]; vector<vector<long long> > dp(n + 2, vector<long long>(n + 1, -LINF)); dp[0][0] = 0; FOR(i, 1, n + 2) dp[i][i - 1] = (a[i - 1] - a[0]) * (a[i - 1] - a[0]); FOR(i, 1, n + 1) { CHT<long long> cht; for (int k = 0; i + k <= n; ++k) { cht.add(-a[i + k] * 2, dp[i + k][k] + a[i + k] * a[i + k]); dp[i + k + 1][k] = cht.monotone_inc_query(a[i + k]) + a[i + k] * a[i + k]; } } FOR(j, 1, n + 1) cout << dp[n + 1][j] << '\n'; return 0; }