結果
問題 | No.435 占い(Extra) |
ユーザー | kei |
提出日時 | 2020-01-05 23:26:32 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
MLE
|
実行時間 | - |
コード長 | 3,100 bytes |
コンパイル時間 | 1,642 ms |
コンパイル使用メモリ | 168,048 KB |
実行使用メモリ | 81,792 KB |
最終ジャッジ日時 | 2024-10-08 12:30:36 |
合計ジャッジ時間 | 34,383 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | MLE | - |
testcase_01 | MLE | - |
testcase_02 | MLE | - |
testcase_03 | MLE | - |
testcase_04 | MLE | - |
testcase_05 | MLE | - |
testcase_06 | MLE | - |
testcase_07 | MLE | - |
testcase_08 | MLE | - |
testcase_09 | MLE | - |
testcase_10 | MLE | - |
testcase_11 | MLE | - |
testcase_12 | MLE | - |
testcase_13 | MLE | - |
testcase_14 | MLE | - |
testcase_15 | MLE | - |
testcase_16 | MLE | - |
testcase_17 | MLE | - |
testcase_18 | MLE | - |
testcase_19 | MLE | - |
testcase_20 | TLE | - |
testcase_21 | MLE | - |
testcase_22 | MLE | - |
testcase_23 | MLE | - |
testcase_24 | MLE | - |
testcase_25 | MLE | - |
testcase_26 | TLE | - |
testcase_27 | MLE | - |
testcase_28 | MLE | - |
testcase_29 | MLE | - |
testcase_30 | TLE | - |
testcase_31 | MLE | - |
testcase_32 | MLE | - |
testcase_33 | MLE | - |
testcase_34 | MLE | - |
testcase_35 | MLE | - |
コンパイルメッセージ
main.cpp: In function 'void init_primes()': main.cpp:40:23: warning: iteration 9999998 invokes undefined behavior [-Waggressive-loop-optimizations] 40 | if(!divprime[i]){ | ~~~~~~~~~~^ main.cpp:39:21: note: within this loop 39 | for(ll i = 2; i <= MAX_PRIME;i++){ | ~~^~~~~~~~~~~~
ソースコード
#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; const int INF = 1e9; const ll LINF = 1e18; inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; } inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; } template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; } template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; } template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; } template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; } /* <url:https://yukicoder.me/problems/no/434> 問題文============================================================ ================================================================= 解説============================================================= ================================================================ */ ll mul(ll a,ll b){ ll res = 0; ll exp = a; while(b){ if(b&1){ res += exp; } exp <<= 1; b >>= 1; } return res; } const int MAX_PRIME = 1e7; int_fast16_t divprime[MAX_PRIME]; void init_primes(){ for(ll i = 2; i <= MAX_PRIME;i++){ if(!divprime[i]){ for(ll j = mul(i,i); j <= MAX_PRIME;j+=i){ divprime[j]=(int_fast16_t)i; } } } } const ll MOD = 9; // a^b % MOD; ll powmod(ll a,ll b) {ll res=1;a%=MOD; for(;b;b>>=1){if(b&1)res=res*a%MOD;a=a*a%MOD;}return res;} template<class Type> Type solve(Type res = Type()){ init_primes(); int T; cin >> T; while(T--){ ll N,X,A,B,M; cin >> N >> X >> A >> B >> M; ll ans = 0; int_fast16_t num[10] = {}; int Xmod10 = X%10; for(int i = 0; i < N;i++){ if(num[3] < 2){ ll x = 1; for(int j = 2; j < 9;j++) x *= powmod(j,num[j]); ans += mul(x,Xmod10);// x*(X%10); }else{ ans += mul(9,Xmod10);// 9*(X%10); } if(i < N-1){ ll x = N-1-i; ll y = 1+i; while(divprime[x]){ num[divprime[x]%9]++; x /= divprime[x];} num[x%9]++; while(divprime[y]){ num[divprime[y]%9]--; y /= divprime[y];} num[y%9]--; } X = ((X^A)+B)%M; } while(ans>=10) ans = ans%10+ans/10; cout << ans << endl; } return res; } int main(void) { cin.tie(0); ios::sync_with_stdio(false); solve<ll>(0); //cout << fixed << setprecision(12) << solve<ll>() << endl; return 0; }