結果
問題 | No.314 ケンケンパ |
ユーザー |
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提出日時 | 2020-01-22 23:53:00 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 84 ms / 1,000 ms |
コード長 | 6,794 bytes |
コンパイル時間 | 1,423 ms |
コンパイル使用メモリ | 128,260 KB |
実行使用メモリ | 57,748 KB |
最終ジャッジ日時 | 2024-07-17 22:11:03 |
合計ジャッジ時間 | 2,591 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 17 |
ソースコード
#include<iostream>#include<fstream>#include<bitset>#include<string>#include<vector>#include<algorithm>#include<cmath>#include<map>#include<set>#include<iomanip>#include<queue>#include<stack>#include<numeric>#include<utility>#include<regex>#include<climits>void Init() {std::cin.tie(0); std::ios::sync_with_stdio(false);struct Init_caller { Init_caller() { Init(); } }caller;}#define int LL#define rep(i,n) for(LL (i)=0;(i)<(n);(i)++)#define all(a) (a).begin(),(a).end()#define check() cout<<"! ! !"#define endl "\n"#define _y() cout<<"Yes"<<endl#define _Y() cout<<"YES"<<endl#define _n() cout<<"No"<<endl#define _N() cout<<"NO"<<endl#define INT_INF INT_MAX#define INF LLONG_MAX#define MOD (1000000000+7)using namespace std;using LL = long long;using st = string;using vi = vector<int>;using vvi = vector<vi>;using vvvi = vector<vvi>;using vd = vector<double>;using vvd = vector<vd>;using vvvd = vector<vvd>;using vc = vector<char>;using vvc = vector<vc>;using vs = vector<st>;using vb = vector<bool>;using vvb = vector<vb>;using vvvb = vector<vvb>;using qi = queue<int>;using qc = queue<char>;using qs = queue<st>;using si = stack<int>;using sc = stack<char>;using ss = stack<st>;using pi = pair<int, int>;using ppi = pair<pi, int>;using mii = map<int, int>;using mpii = map<pi, int>;using mib = map<int, bool>;using mci = map<char, int>;using msb = map<st, bool>;using vpi = vector<pi>;using vppi = vector<ppi>;using spi = stack<pi>;using qpi = queue<pi>;//4,2,8,6,1,7,3,9,5int dx[] = { -1,0,0,1,-1,-1,1,1,0 };int dy[] = { 0,1,-1,0,1,-1,1,-1,0 };template<typename T>istream &operator>>(istream &in, vector<T> &v) {rep(i, v.size()) {in >> v[i];}return in;}template<typename T,typename U>istream &operator>>(istream&in, vector<pair<T, U>> &p) {rep(i, p.size()) {in >> p[i].first >> p[i].second;}return in;}template<typename T>ostream &operator<<(ostream &out, vector<T> &v) {out << "{";rep(i, v.size()) {out << v[i] << ",";}out << "}" << endl;return out;}template<typename T, typename U>ostream &operator<<(ostream&out, vector<pair<T, U>> &p) {rep(i, p.size()) {out << "{" << p[i].first << "," << p[i].second << "}" << endl;}return out;}void y_n(bool p) {p ? _y() : _n();}void Y_N(bool p) {p ? _Y() : _N();}template<typename T>pair<T,int> vmax(vector<T> v) {int n = v.size();int MAX = 0;int pos = 0;rep(i, n) {if (MAX < v[i])pos = i;MAX = max(MAX, v[i]);}return { MAX,pos };}template<typename T>pair<T, int> vmin(vector<T> v) {int n = v.size();int MIN = INF;int pos = 0;rep(i, n) {if (MIN > v[i])pos = i;MIN = min(MIN, v[i]);}return { MIN,pos };}template<typename T>T vsum(vector<T> v) {int n = v.size();T sum = 0;rep(i, n) {sum += v[i];}return sum;}int gcd(int a, int b) {if (b == 0) {swap(a, b);}int r;while ((r = a % b) != 0) {a = b;b = r;}return b;}int lcm(int a, int b) {return (a / gcd(a, b) * b);}bool is_square(int n) {if ((int)sqrt(n)*(int)sqrt(n) == n) {return true;}else {return false;}}bool is_prime(int n) {if (n <= 1) {return true;}else {for (int i = 2; i*i <= n; i++) {if (n % i == 0) {return false;}}}return true;}void dec_num(int n, vi &v) {int a = 2;v.push_back(1);v.push_back(n);while (a*a <= n) {if (n%a == 0) {v.push_back(a);v.push_back(n / a);}a++;}sort(all(v));}void dec_prime(int n, vi &v) {//v.push_back(1);int a = 2;while (a*a <= n) {if (n % a == 0) {v.push_back(a);n /= a;}else {a++;}}v.push_back(n);}//nの素因数分解の指数表示void dec_prime_e(int n, map<int, int> &m) {for (int i = 2; i*i <= n; i++) {if (n%i == 0) {int e = 0;while (n%i == 0) {e++;n /= i;}m[i] += e;}}if (n != 1)m[n]++;}//指数部のみの列挙/*for (auto j : m) {p.push_back(j.second);}*/int sieve_prime(int a, int b) {if (a > b)swap(a, b);vb s(b + 1, true);int cnt_a = 0, cnt_b = 0;for (int i = 2; i <= b; i++) {for (int j = 2; i*j <= b; j++) {s[i*j] = false;}}for (int i = 2; i <= b; i++) {if (s[i]) {//cout << i << " ";if (i < a) {cnt_a++;}cnt_b++;}}return cnt_b - cnt_a;}int factorial(int n) {int a = 1, ret = 1;while (a < n) {a++;ret *= a;//ret %= MOD;}return ret;}int bit_count(int n) {int k = log2(n) + 1;int ret = 0;rep(i, k) {if (n&(1 << i))ret++;}return ret;}const int COMBMAX = 4000;int comb[COMBMAX + 5][COMBMAX + 5];void init_comb() {comb[0][0] = 1;rep(i, COMBMAX) {rep(j, i + 1) {comb[i + 1][j] += comb[i][j];comb[i + 1][j] %= MOD;comb[i + 1][j + 1] += comb[i][j];comb[i + 1][j + 1] %= MOD;}}}int combination(int n, int k) {if (k<0 || k>n)return 0;else return comb[n][k];}const int COMBMODMAX = 5000000;int fac[COMBMODMAX + 5], facinv[COMBMODMAX + 5], inv[COMBMODMAX + 5];void init_comb_mod() {fac[0] = fac[1] = 1;facinv[0] = facinv[1] = 1;inv[1] = 1;for (int i = 2; i < COMBMODMAX; i++) {fac[i] = fac[i - 1] * i%MOD;inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;facinv[i] = facinv[i - 1] * inv[i] % MOD;}}//nCk (mod p)int comb_mod(int n, int k) {if (n < k)return 0;if (n < 0 || k < 0)return 0;return fac[n] * (facinv[k] * facinv[n - k] % MOD) % MOD;}//x^n (mod p)int pow_mod(int x, int n, int p) {if (n == 0)return 1;int res = pow_mod(x*x%p, n / 2, p);if (n % 2 == 1)res = res * x % p;return res;}class UF {public:vi par;vi rank;UF(int n) {par.resize(n, -1);rank.resize(n, 0);}int root(int x) {if (par[x] == -1)return x;return par[x] = root(par[x]);}//xの集合の位数int order(int x) {return -par[root(x)];}//xとyを併合void unite(int x, int y) {x = root(x);y = root(y);if (x == y) {return;}if (rank[x] < rank[y]) {par[x] = y;}else {par[y] = x;if (rank[x] == rank[y])rank[x]++;}}//xとyが同じ集合にあるかbool is_same(int x, int y) {return root(x) == root(y);}};struct edge {int to;int cost;};using ve = vector<edge>;using vve = vector<ve>;/*****************************************************************************/signed main() {int n;cin >> n;vvi dp(n + 2, vi(3, 0));dp[1][1] = 1;for(int i=1;i<n;i++) {rep(j, 3) {if (j == 0) {(dp[i + 1][1] += dp[i][0]) %= MOD;}else if (j == 1) {(dp[i + 1][2] += dp[i][1]) %= MOD;(dp[i + 1][0] += dp[i][1]) %= MOD;}else {(dp[i + 1][0] += dp[i][2]) %= MOD;}}}int ans = 0;rep(i, 3) {(ans += dp[n][i]) %= MOD;}cout << ans;}