結果
問題 | No.66 輝け☆全国たこやき杯 |
ユーザー | heno239 |
提出日時 | 2020-01-25 16:58:32 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 7 ms / 5,000 ms |
コード長 | 3,285 bytes |
コンパイル時間 | 1,268 ms |
コンパイル使用メモリ | 118,312 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-14 04:08:49 |
合計ジャッジ時間 | 1,778 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 10 |
ソースコード
#include<iostream> #include<string> #include<cstdio> #include<vector> #include<cmath> #include<algorithm> #include<functional> #include<iomanip> #include<queue> #include<ciso646> #include<random> #include<map> #include<set> #include<bitset> #include<stack> #include<unordered_map> #include<utility> #include<cassert> #include<complex> using namespace std; //#define int long long typedef long long ll; typedef unsigned long long ul; typedef unsigned int ui; const ll mod = 1000000007; const ll INF = (1e+18) + 7; typedef pair<int, int>P; #define stop char nyaa;cin>>nyaa; #define rep(i,n) for(int i=0;i<n;i++) #define per(i,n) for(int i=n-1;i>=0;i--) #define Rep(i,sta,n) for(int i=sta;i<n;i++) #define rep1(i,n) for(int i=1;i<=n;i++) #define per1(i,n) for(int i=n;i>=1;i--) #define Rep1(i,sta,n) for(int i=sta;i<=n;i++) #define all(v) (v).begin(),(v).end() typedef pair<ll, ll> LP; typedef long double ld; typedef pair<ld, ld> LDP; const ld eps = 1e-6; const ld pi = acos(-1.0); //typedef vector<vector<ll>> mat; typedef vector<int> vec; ll mod_pow(ll a, ll n) { ll res = 1; while (n) { if (n & 1)res = res * a%mod; a = a * a%mod; n >>= 1; } return res; } struct modint { ll n; modint() :n(0) { ; } modint(ll m) :n(m) { if (n >= mod)n %= mod; else if (n < 0)n = (n%mod + mod) % mod; } operator int() { return n; } }; bool operator==(modint a, modint b) { return a.n == b.n; } modint operator+=(modint &a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; } modint operator-=(modint &a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; } modint operator*=(modint &a, modint b) { a.n = ((ll)a.n*b.n) % mod; return a; } modint operator+(modint a, modint b) { return a += b; } modint operator-(modint a, modint b) { return a -= b; } modint operator*(modint a, modint b) { return a *= b; } modint operator^(modint a, int n) { if (n == 0)return modint(1); modint res = (a*a) ^ (n / 2); if (n % 2)res = res * a; return res; } //ll inv(ll a, ll p) { // return (a == 1 ? 1 : (1 - p * inv(p%a, a)) / a + p); //} //modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); } int dx[4] = { 1,0,-1,0 }; int dy[4] = { 0,1,0,-1 }; ld dp[1024][11]; int n; ld s[1024]; LDP calc(int le, int ri) { ld pl = s[le] * s[le]; ld pr = s[ri] * s[ri]; return { pl / (pl + pr),pr / (pl + pr) }; } using speP = pair<int,ld>; vector<speP> merge(vector<speP> &a, vector<speP> &b) { int len = a.size(); vector<speP> res(2 * len); rep(i, len)res[i].first = a[i].first; rep(i, len)res[i + len].first = b[i].first; rep(i, len) { rep(j, len) { ld p = a[i].second * b[j].second; LDP q = calc(a[i].first, b[j].first); res[i].second += p * q.first; res[j+len].second += p * q.second; } } return res; } void solve() { cin >> n; rep(i, (1 << n)) { cin >> s[i]; } vector<vector<speP>> v; rep(i, (1 << n)) { v.push_back({ {i,1} }); } rep(i, n) { vector<vector<speP>> nex; int len = v.size(); rep(j, len / 2) { nex.push_back(merge(v[2 * j], v[2 * j + 1])); } swap(v, nex); } cout << v[0][0].second << endl; } signed main() { ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(7); //init(); //int t; cin >> t; rep(i, t)solve(); //while (cin >> n, n)solve(); solve(); stop return 0; }