結果
| 問題 |
No.66 輝け☆全国たこやき杯
|
| コンテスト | |
| ユーザー |
heno239
|
| 提出日時 | 2020-01-25 16:58:32 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 7 ms / 5,000 ms |
| コード長 | 3,285 bytes |
| コンパイル時間 | 1,268 ms |
| コンパイル使用メモリ | 118,312 KB |
| 実行使用メモリ | 5,376 KB |
| 最終ジャッジ日時 | 2024-09-14 04:08:49 |
| 合計ジャッジ時間 | 1,778 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 10 |
ソースコード
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
#include<complex>
using namespace std;
//#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
const ll mod = 1000000007;
const ll INF = (1e+18) + 7;
typedef pair<int, int>P;
#define stop char nyaa;cin>>nyaa;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-6;
const ld pi = acos(-1.0);
//typedef vector<vector<ll>> mat;
typedef vector<int> vec;
ll mod_pow(ll a, ll n) {
ll res = 1;
while (n) {
if (n & 1)res = res * a%mod;
a = a * a%mod; n >>= 1;
}
return res;
}
struct modint {
ll n;
modint() :n(0) { ; }
modint(ll m) :n(m) {
if (n >= mod)n %= mod;
else if (n < 0)n = (n%mod + mod) % mod;
}
operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
modint operator+=(modint &a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint &a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint &a, modint b) { a.n = ((ll)a.n*b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, int n) {
if (n == 0)return modint(1);
modint res = (a*a) ^ (n / 2);
if (n % 2)res = res * a;
return res;
}
//ll inv(ll a, ll p) {
// return (a == 1 ? 1 : (1 - p * inv(p%a, a)) / a + p);
//}
//modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
int dx[4] = { 1,0,-1,0 };
int dy[4] = { 0,1,0,-1 };
ld dp[1024][11];
int n;
ld s[1024];
LDP calc(int le, int ri) {
ld pl = s[le] * s[le];
ld pr = s[ri] * s[ri];
return { pl / (pl + pr),pr / (pl + pr) };
}
using speP = pair<int,ld>;
vector<speP> merge(vector<speP> &a, vector<speP> &b) {
int len = a.size();
vector<speP> res(2 * len);
rep(i, len)res[i].first = a[i].first;
rep(i, len)res[i + len].first = b[i].first;
rep(i, len) {
rep(j, len) {
ld p = a[i].second * b[j].second;
LDP q = calc(a[i].first, b[j].first);
res[i].second += p * q.first;
res[j+len].second += p * q.second;
}
}
return res;
}
void solve() {
cin >> n;
rep(i, (1 << n)) {
cin >> s[i];
}
vector<vector<speP>> v;
rep(i, (1 << n)) {
v.push_back({ {i,1} });
}
rep(i, n) {
vector<vector<speP>> nex;
int len = v.size();
rep(j, len / 2) {
nex.push_back(merge(v[2 * j], v[2 * j + 1]));
}
swap(v, nex);
}
cout << v[0][0].second << endl;
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(7);
//init();
//int t; cin >> t; rep(i, t)solve();
//while (cin >> n, n)solve();
solve();
stop
return 0;
}
heno239