結果
問題 | No.979 Longest Divisor Sequence |
ユーザー | chakku |
提出日時 | 2020-01-31 23:08:54 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,288 bytes |
コンパイル時間 | 2,066 ms |
コンパイル使用メモリ | 184,724 KB |
実行使用メモリ | 28,160 KB |
最終ジャッジ日時 | 2024-09-17 10:22:15 |
合計ジャッジ時間 | 3,636 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 5 ms
6,812 KB |
testcase_01 | AC | 4 ms
6,940 KB |
testcase_02 | AC | 5 ms
6,940 KB |
testcase_03 | AC | 4 ms
6,940 KB |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | AC | 5 ms
6,940 KB |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | AC | 499 ms
28,160 KB |
testcase_14 | WA | - |
testcase_15 | WA | - |
ソースコード
#include <bits/stdc++.h> using namespace std; /*{{{*/ //template #define rep(i,n) for(int i=0;i<(int)(n);i++) #define rrep(i,n) for(int i=(n)-1;i>=0;i--) constexpr int INF = numeric_limits<int>::max()/2; constexpr long long LINF = numeric_limits<long long>::max()/3; #define pb push_back #define eb emplace_back #define fi first #define se second #define all(v) (v).begin(),(v).end() #define sz(x) (int)(x).size() #define debug(x) cerr<<#x<<":"<<x<<endl #define debug2(x,y) cerr<<#x<<","<<#y":"<<x<<","<<y<<endl //struct fin{ fin(){ cin.tie(0); ios::sync_with_stdio(false); } } fin_; struct Double{ double d; explicit Double(double x) : d(x){} }; ostream& operator<<(ostream& os,const Double x){ os << fixed << setprecision(20) << x.d; return os; } template<typename T> ostream& operator<<(ostream& os,const vector<T>& vec){ os << "["; for(const auto& v : vec){ os << v << ","; } os << "]"; return os; } template<typename T,typename U> ostream& operator<<(ostream& os, const map<T,U>& mp){ os << "{"; for(auto& p : mp){ os << p << ","; } os << "}"; return os; } template<typename T,typename U> ostream& operator<<(ostream& os,const pair<T,U>& p){ os << "(" << p.first << ","<< p.second <<")"; return os; } template<typename T> ostream& operator<<(ostream& os,const set<T>& st){ os<<"{"; for(T v:st) os<<v<<","; os <<"}"; return os; } template<typename T,typename U> inline void chmax(T &x,U y){ if(y>x) x = y; } template<typename T,typename U> inline void chmin(T &x,U y){ if(y<x) x = y; } using ll = long long; using ull = unsigned long long; using pii = std::pair<int,int>; using vi = std::vector<int>; typedef vector<vi> vvi; ll gcd(ll a,ll b){ if(b==0) return a; else return gcd(b,a%b); } constexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n - 1); } //constexpr double eps = 1e-14; constexpr double eps = 1e-10; constexpr ll mod = 1e9+7; const int dx[]={1,0,-1,0} ,dy[] = {0,1,0,-1}; /*}}}*/ const int max_n = 300005; vector<ll> prime(ll n){ vector<ll> primes; vector<bool> p(n+1,true); p[0] = p[1] = false; for(ll i=2;i<=n;i++){ if(!p[i]) continue; if(p[i]) primes.push_back(i); for(ll j=2;i*j<=n;j++) p[i*j]=false; } return primes; } template<typename T> int LongestCommonSubsequence(const T& s, const T& t){ int n = s.size(); int m = t.size(); vector<vector<int>> dp(n+1,vector<int>(m+1,0)); for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ if(s[i] == t[j]){ dp[i+1][j+1] = dp[i][j]+1; }else{ dp[i+1][j+1] = max(dp[i+1][j],dp[i][j+1]); } } } return dp[n][m]; } int main(){ int n; cin >> n; vector<int> a(n); rep(i,n) cin >> a[i]; vector<ll> ps = prime(max_n); map<int,vector<int>> vs; for(auto p : ps){ if(p*p > max_n) continue; ll val = p; while(val < max_n){ vs[p].emplace_back(val); val *= p; } } ll ans = 1; for(auto p : ps){ if(!vs.count(p)) continue; ll len = LongestCommonSubsequence(vs[p],a); ans = max(ans,len); } cout << ans << endl; //for(auto p : ps){ // if(!vs.count(p)) continue; // cout << p << " " << vs[p] << endl; //} //cout << ps << endl; }