結果
問題 | No.980 Fibonacci Convolution Hard |
ユーザー | はまやんはまやん |
提出日時 | 2020-02-01 09:56:10 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
MLE
|
実行時間 | - |
コード長 | 7,098 bytes |
コンパイル時間 | 3,394 ms |
コンパイル使用メモリ | 238,656 KB |
実行使用メモリ | 816,252 KB |
最終ジャッジ日時 | 2024-09-18 19:46:16 |
合計ジャッジ時間 | 10,294 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | MLE | - |
testcase_01 | -- | - |
testcase_02 | -- | - |
testcase_03 | -- | - |
testcase_04 | -- | - |
testcase_05 | -- | - |
testcase_06 | -- | - |
testcase_07 | -- | - |
testcase_08 | -- | - |
testcase_09 | -- | - |
testcase_10 | -- | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
ソースコード
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #define all(x) (x).begin(),(x).end() //#pragma GCC optimize ("-O3") using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); } typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60; template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; } template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; } //--------------------------------------------------------------------------------------------------- template<typename T, T MOD = 1000000007> struct Mint { static constexpr T mod = MOD; T v; Mint() :v(0) {} Mint(signed v) :v(v) {} Mint(long long t) { v = t % MOD; if (v < 0) v += MOD; } Mint pow(long long k) { Mint res(1), tmp(v); while (k) { if (k & 1) res *= tmp; tmp *= tmp; k >>= 1; } return res; } static Mint add_identity() { return Mint(0); } static Mint mul_identity() { return Mint(1); } Mint inv() { return pow(MOD - 2); } Mint& operator+=(Mint a) { v += a.v; if (v >= MOD)v -= MOD; return *this; } Mint& operator-=(Mint a) { v += MOD - a.v; if (v >= MOD)v -= MOD; return *this; } Mint& operator*=(Mint a) { v = 1LL * v * a.v % MOD; return *this; } Mint& operator/=(Mint a) { return (*this) *= a.inv(); } Mint operator+(Mint a) const { return Mint(v) += a; } Mint operator-(Mint a) const { return Mint(v) -= a; } Mint operator*(Mint a) const { return Mint(v) *= a; } Mint operator/(Mint a) const { return Mint(v) /= a; } Mint operator-() const { return v ? Mint(MOD - v) : Mint(v); } bool operator==(const Mint a)const { return v == a.v; } bool operator!=(const Mint a)const { return v != a.v; } bool operator <(const Mint a)const { return v < a.v; } static Mint comb(long long n, int k) { Mint num(1), dom(1); for (int i = 0; i < k; i++) { num *= Mint(n - i); dom *= Mint(i + 1); } return num / dom; } }; template<typename T, T MOD> constexpr T Mint<T, MOD>::mod; template<typename T, T MOD> ostream& operator<<(ostream& os, Mint<T, MOD> m) { os << m.v; return os; } constexpr int bmds(int x) { const int v[] = { 1012924417, 924844033, 998244353, 897581057, 645922817 }; return v[x]; } constexpr int brts(int x) { const int v[] = { 5, 5, 3, 3, 3 }; return v[x]; } template<int X> struct NTT { static constexpr int md = bmds(X); static constexpr int rt = brts(X); using M = Mint<int, md>; vector< vector<M> > rts, rrts; void ensure_base(int n) { if ((int)rts.size() >= n) return; rts.resize(n); rrts.resize(n); for (int i = 1; i < n; i <<= 1) { if (!rts[i].empty()) continue; M w = M(rt).pow((md - 1) / (i << 1)); M rw = w.inv(); rts[i].resize(i); rrts[i].resize(i); rts[i][0] = M(1); rrts[i][0] = M(1); for (int k = 1; k < i; k++) { rts[i][k] = rts[i][k - 1] * w; rrts[i][k] = rrts[i][k - 1] * rw; } } } void ntt(vector<M>& as, bool f) { int n = as.size(); assert((n & (n - 1)) == 0); ensure_base(n); for (int i = 0, j = 1; j + 1 < n; j++) { for (int k = n >> 1; k > (i ^= k); k >>= 1); if (i > j) swap(as[i], as[j]); } for (int i = 1; i < n; i <<= 1) { for (int j = 0; j < n; j += i * 2) { for (int k = 0; k < i; k++) { M z = as[i + j + k] * (f ? rrts[i][k] : rts[i][k]); as[i + j + k] = as[j + k] - z; as[j + k] += z; } } } if (f) { M tmp = M(n).inv(); for (int i = 0; i < n; i++) as[i] *= tmp; } } vector<M> multiply(vector<M> as, vector<M> bs) { int need = as.size() + bs.size() - 1; int sz = 1; while (sz < need) sz <<= 1; as.resize(sz, M(0)); bs.resize(sz, M(0)); ntt(as, 0); ntt(bs, 0); for (int i = 0; i < sz; i++) as[i] *= bs[i]; ntt(as, 1); as.resize(need); return as; } vector<int> multiply(vector<int> as, vector<int> bs) { vector<M> am(as.size()), bm(bs.size()); for (int i = 0; i < (int)am.size(); i++) am[i] = M(as[i]); for (int i = 0; i < (int)bm.size(); i++) bm[i] = M(bs[i]); vector<M> cm = multiply(am, bm); vector<int> cs(cm.size()); for (int i = 0; i < (int)cs.size(); i++) cs[i] = cm[i].v; return cs; } }; template<int X> constexpr int NTT<X>::md; template<int X> constexpr int NTT<X>::rt; struct Garner { using ll = long long; static NTT<0> ntt0; static NTT<1> ntt1; static NTT<2> ntt2; static constexpr int pow(int a, int b, int md) { int res = 1; a = a % md; while (b) { if (b & 1) res = (ll)res * a % md; a = (ll)a * a % md; b >>= 1; } return res; } static constexpr int inv(int x, int md) { return pow(x, md - 2, md); } inline void garner(int& c0, int c1, int c2, int m01, int MOD) { static constexpr int r01 = inv(ntt0.md, ntt1.md); static constexpr int r02 = inv(ntt0.md, ntt2.md); static constexpr int r12 = inv(ntt1.md, ntt2.md); c1 = (ll)(c1 - c0) * r01 % ntt1.md; if (c1 < 0) c1 += ntt1.md; c2 = (ll)(c2 - c0) * r02 % ntt2.md; c2 = (ll)(c2 - c1) * r12 % ntt2.md; if (c2 < 0) c2 += ntt2.md; c0 %= MOD; c0 += (ll)c1 * ntt0.md % MOD; if (c0 >= MOD) c0 -= MOD; c0 += (ll)c2 * m01 % MOD; if (c0 >= MOD) c0 -= MOD; } inline void garner(vector< vector<int> >& cs, int MOD) { int m01 = (ll)ntt0.md * ntt1.md % MOD; int sz = cs[0].size(); for (int i = 0; i < sz; i++) garner(cs[0][i], cs[1][i], cs[2][i], m01, MOD); } vector<int> multiply(vector<int> as, vector<int> bs, int MOD = 1000000007) { vector< vector<int> > cs(3); cs[0] = ntt0.multiply(as, bs); cs[1] = ntt1.multiply(as, bs); cs[2] = ntt2.multiply(as, bs); size_t sz = as.size() + bs.size() - 1; for (auto& v : cs) v.resize(sz); garner(cs, MOD); return cs[0]; } }; NTT<0> Garner::ntt0; NTT<1> Garner::ntt1; NTT<2> Garner::ntt2; /*--------------------------------------------------------------------------------------------------- ∧_∧ ∧_∧ (´<_` ) Welcome to My Coding Space! ( ´_ゝ`) / ⌒i @hamayanhamayan0 / \ | | / / ̄ ̄ ̄ ̄/ | __(__ニつ/ _/ .| .|____ \/____/ (u ⊃ ---------------------------------------------------------------------------------------------------*/ int p, Q; int mo = 1000000007; //--------------------------------------------------------------------------------------------------- void _main() { cin >> p; Garner ntt; vector<int> v1(2010101, 0), v2(2010101, 0); v1[2] = 1; rep(i, 3, 2010101) v1[i] = (1LL * v1[i - 1] * p + v1[i - 2]) % 1000000007; rep(i, 0, 2010101) v2[i] = v1[i]; auto v3 = ntt.multiply(v1, v2); cin >> Q; rep(_, 0, Q) { int q; cin >> q; printf("%d\n", v3[q]); } }