結果
| 問題 |
No.145 yukiover
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2020-02-07 19:27:52 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 957 bytes |
| コンパイル時間 | 544 ms |
| コンパイル使用メモリ | 68,756 KB |
| 実行使用メモリ | 6,948 KB |
| 最終ジャッジ日時 | 2024-09-25 07:25:39 |
| 合計ジャッジ時間 | 1,386 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 WA * 2 |
| other | AC * 4 WA * 16 |
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/string:50,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/locale_classes.h:40,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/ios_base.h:41,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ios:42,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:38,
from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/iostream:39,
from main.cpp:1:
In function 'constexpr const _Tp& std::min(const _Tp&, const _Tp&) [with _Tp = int]',
inlined from 'int main()' at main.cpp:29:18:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:235:15: warning: iteration 3 invokes undefined behavior [-Waggressive-loop-optimizations]
235 | if (__b < __a)
| ~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:28:21: note: within this loop
28 | for(int i = 2; 9 > i; i+=2){
| ~~^~~
ソースコード
#include <iostream>
#include <algorithm>
using namespace std;
int dta[9];// z y x~v u t~l k j i h~a
int main(){
char yuki[4] = {'y','u','k','i'};
int n;cin>>n;
string s;cin>>s;
for(int i = 0; s.size() > i; i++){
int ok = false;
for(int j = 0; 8 > j; j+=2){
if(s[i] > yuki[j/2]){
ok = true;
dta[j]++;
break;
}else if(s[i] == yuki[j/2]){
ok = true;
dta[j+1]++;
break;
}
}
if(!ok){
dta[8]++;
}
}
reverse(dta,dta+9);
int tans = (dta[1]>dta[0]?dta[0]+(dta[1]-dta[0])/2:dta[1]);
for(int i = 2; 9 > i; i+=2){
int ans = min(dta[i],dta[i+1]);
//cout << i << " " << i+1 << ":" << dta[i] << " " << dta[i+1] << endl;
if(dta[i+1] > dta[i]){
dta[i+1] -= dta[i];
ans += min(dta[i+1],tans);
if(dta[i+1] > tans){
dta[i+1]-= tans;
ans += dta[i+1]/=2;
}
}
tans = ans;
}
cout << tans + dta[8] << endl;
}