結果
問題 | No.913 木の燃やし方 |
ユーザー | square1001 |
提出日時 | 2020-02-13 21:48:38 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,184 bytes |
コンパイル時間 | 1,500 ms |
コンパイル使用メモリ | 108,800 KB |
実行使用メモリ | 18,072 KB |
最終ジャッジ日時 | 2024-10-06 06:29:16 |
合計ジャッジ時間 | 13,449 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,820 KB |
testcase_01 | AC | 2 ms
6,816 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 5 ms
6,820 KB |
testcase_04 | AC | 5 ms
6,820 KB |
testcase_05 | AC | 6 ms
6,820 KB |
testcase_06 | AC | 4 ms
6,820 KB |
testcase_07 | AC | 3 ms
6,816 KB |
testcase_08 | AC | 304 ms
17,448 KB |
testcase_09 | AC | 291 ms
15,912 KB |
testcase_10 | AC | 285 ms
16,812 KB |
testcase_11 | WA | - |
testcase_12 | AC | 312 ms
18,004 KB |
testcase_13 | AC | 328 ms
17,568 KB |
testcase_14 | AC | 310 ms
15,808 KB |
testcase_15 | AC | 316 ms
16,944 KB |
testcase_16 | AC | 232 ms
17,492 KB |
testcase_17 | AC | 216 ms
15,932 KB |
testcase_18 | AC | 215 ms
17,020 KB |
testcase_19 | AC | 234 ms
17,116 KB |
testcase_20 | AC | 228 ms
18,004 KB |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | AC | 244 ms
16,388 KB |
testcase_25 | AC | 222 ms
17,892 KB |
testcase_26 | AC | 334 ms
16,488 KB |
testcase_27 | AC | 295 ms
17,084 KB |
testcase_28 | AC | 311 ms
17,216 KB |
testcase_29 | AC | 302 ms
17,876 KB |
testcase_30 | AC | 302 ms
17,880 KB |
testcase_31 | AC | 281 ms
17,200 KB |
testcase_32 | AC | 280 ms
17,268 KB |
testcase_33 | AC | 284 ms
18,032 KB |
testcase_34 | AC | 264 ms
17,080 KB |
testcase_35 | AC | 258 ms
17,916 KB |
testcase_36 | AC | 233 ms
17,880 KB |
ソースコード
#include <set> #include <deque> #include <vector> #include <iostream> #include <algorithm> using namespace std; const long long inf = 1LL << 62; vector<long long> subsolve(int N, vector<long long> A) { A.insert(A.begin(), 0); for (int i = 0; i < N; ++i) { A[i + 1] += A[i]; } // minimize (A[i] - A[j]) + (i - j)^2 = (A[i] + i * i) + (-A[j] + j * j) - 2 * j * i for each i vector<long long> intercept(N + 1), slope(N + 1); for (int i = 0; i <= N; ++i) { intercept[i] = -A[i] + 1LL * i * i; slope[i] = -2 * i; } int mid = (N + 1) / 2; vector<long long> seq(N, inf); deque<int> que; for (int i = 0; i < mid; ++i) { while (que.size() >= 2) { int pa = que[que.size() - 2]; int pb = que[que.size() - 1]; long double cra = -(long double)(intercept[pa] - intercept[i]) * (i - pb); long double crb = -(long double)(intercept[pb] - intercept[i]) * (i - pa); if (cra > crb) que.pop_back(); else break; } que.push_back(i); while (que.size() >= 2) { int pa = que[0]; int pb = que[1]; long long va = 1LL * slope[pa] * (i + 1) + intercept[pa]; long long vb = 1LL * slope[pb] * (i + 1) + intercept[pb]; if (va > vb) que.pop_front(); else break; } } for (int i = mid; i <= N; ++i) { seq[i - 1] = que[0]; while (que.size() >= 2) { int pa = que[que.size() - 2]; int pb = que[que.size() - 1]; long double cra = -(long double)(intercept[pa] - intercept[i]) * (i - pb); long double crb = -(long double)(intercept[pb] - intercept[i]) * (i - pa); if (cra > crb) que.pop_back(); else break; } while (que.size() >= 2) { int pa = que[0]; int pb = que[1]; long long va = 1LL * slope[pa] * (i + 1) + intercept[pa]; long long vb = 1LL * slope[pb] * (i + 1) + intercept[pb]; if (va > vb) que.pop_front(); else break; } } for (int i = 0; i < N; ++i) { if (seq[i] != inf) { seq[i] = A[i + 1] - A[seq[i]] + 1LL * (i + 1 - seq[i]) * (i + 1 - seq[i]); } } for (int i = N - 2; i >= mid - 1; --i) { seq[i] = min(seq[i], seq[i + 1]); } return seq; } vector<long long> solve(int N, vector<long long> A) { if (N == 1) return vector<long long>({ A[0] + 1 }); int mid = N / 2; vector<long long> res1 = subsolve(N, A); reverse(A.begin(), A.end()); vector<long long> res2 = subsolve(N, A); reverse(res2.begin(), res2.end()); for (int i = 0; i < N; ++i) { res1[i] = min(res1[i], res2[i]); } reverse(A.begin(), A.end()); vector<long long> res3 = solve(mid, vector<long long>(A.begin(), A.begin() + mid)); vector<long long> res4 = solve(N - mid, vector<long long>(A.begin() + mid, A.end())); for (int i = 0; i < mid; ++i) { res1[i] = min(res1[i], res3[i]); } for (int i = mid; i < N; ++i) { res1[i] = min(res1[i], res4[i - mid]); } return res1; } vector<long long> solve_easy(int N, vector<long long> A) { vector<long long> ans(N, 1LL << 62); for (int i = 0; i < N; ++i) { for (int j = i + 1; j <= N; ++j) { long long sum = 1LL * (j - i) * (j - i); for (int k = i; k < j; ++k) { sum += A[k]; } for (int k = i; k < j; ++k) { ans[k] = min(ans[k], sum); } } } return ans; } #include <random> #include <string> using namespace std; mt19937 mt(1910182301); int rand_rng(int l, int r) { uniform_int_distribution<int> p(l, r - 1); return p(mt); } string stringify(vector<long long> A) { string res = "["; for (int i = 0; i < A.size(); ++i) { if (i) res += ", "; res += to_string(A[i]); } res += "]"; return res; } int main() { cin.tie(0); ios_base::sync_with_stdio(false); int N; cin >> N; vector<long long> A(N); for (int i = 0; i < N; ++i) cin >> A[i]; vector<long long> ans = solve(N, A); for (int i = 0; i < N; ++i) { cout << ans[i] << '\n'; } /* int N = 3; for (int i = 1; i <= 10000; ++i) { vector<long long> A(N); for (int j = 0; j < N; ++j) { A[j] = rand_rng(-6, 7); } vector<long long> res1 = solve(N, A); vector<long long> res2 = solve_easy(N, A); if (res1 != res2) { cout << "Case #" << i << ":" << endl; cout << "N = " << N << ", A = " << stringify(A) << endl; cout << "Returns: " << stringify(res1) << endl; cout << "Answer: " << stringify(res2) << endl; cout << endl; } } */ return 0; }