結果
問題 | No.992 最長増加部分列の数え上げ |
ユーザー | NyaanNyaan |
提出日時 | 2020-02-14 22:27:14 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 132 ms / 2,000 ms |
コード長 | 7,243 bytes |
コンパイル時間 | 2,091 ms |
コンパイル使用メモリ | 181,856 KB |
実行使用メモリ | 20,352 KB |
最終ジャッジ日時 | 2024-10-06 12:52:16 |
合計ジャッジ時間 | 7,466 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 2 ms
5,248 KB |
testcase_04 | AC | 49 ms
10,112 KB |
testcase_05 | AC | 35 ms
8,064 KB |
testcase_06 | AC | 59 ms
11,264 KB |
testcase_07 | AC | 44 ms
9,472 KB |
testcase_08 | AC | 23 ms
6,528 KB |
testcase_09 | AC | 45 ms
9,600 KB |
testcase_10 | AC | 59 ms
11,136 KB |
testcase_11 | AC | 75 ms
13,184 KB |
testcase_12 | AC | 16 ms
5,376 KB |
testcase_13 | AC | 42 ms
9,344 KB |
testcase_14 | AC | 42 ms
9,344 KB |
testcase_15 | AC | 17 ms
5,504 KB |
testcase_16 | AC | 118 ms
18,816 KB |
testcase_17 | AC | 23 ms
6,528 KB |
testcase_18 | AC | 41 ms
9,216 KB |
testcase_19 | AC | 74 ms
13,056 KB |
testcase_20 | AC | 129 ms
20,224 KB |
testcase_21 | AC | 129 ms
20,352 KB |
testcase_22 | AC | 129 ms
20,224 KB |
testcase_23 | AC | 130 ms
20,352 KB |
testcase_24 | AC | 132 ms
20,224 KB |
testcase_25 | AC | 131 ms
20,352 KB |
testcase_26 | AC | 131 ms
20,352 KB |
testcase_27 | AC | 130 ms
20,352 KB |
testcase_28 | AC | 129 ms
20,224 KB |
testcase_29 | AC | 130 ms
20,352 KB |
testcase_30 | AC | 101 ms
19,408 KB |
testcase_31 | AC | 102 ms
19,400 KB |
testcase_32 | AC | 103 ms
19,400 KB |
testcase_33 | AC | 101 ms
19,524 KB |
testcase_34 | AC | 99 ms
19,404 KB |
testcase_35 | AC | 106 ms
20,032 KB |
testcase_36 | AC | 106 ms
19,904 KB |
testcase_37 | AC | 107 ms
20,032 KB |
testcase_38 | AC | 106 ms
19,912 KB |
testcase_39 | AC | 106 ms
20,032 KB |
testcase_40 | AC | 102 ms
19,404 KB |
testcase_41 | AC | 103 ms
19,412 KB |
testcase_42 | AC | 103 ms
19,284 KB |
testcase_43 | AC | 104 ms
19,152 KB |
testcase_44 | AC | 103 ms
19,408 KB |
ソースコード
#include <bits/stdc++.h> #define pb push_back #define eb emplace_back #define fi first #define se second #define rep(i,N) for(long long i = 0; i < (long long)(N); i++) #define repr(i,N) for(long long i = (long long)(N) - 1; i >= 0; i--) #define rep1(i,N) for(long long i = 1; i <= (long long)(N) ; i++) #define repr1(i,N) for(long long i = (N) ; (long long)(i) > 0 ; i--) #define each(x,v) for(auto& x : v) #define all(v) (v).begin(),(v).end() #define sz(v) ((int)(v).size()) #define ini(...) int __VA_ARGS__; in(__VA_ARGS__) #define inl(...) long long __VA_ARGS__; in(__VA_ARGS__) #define ins(...) string __VA_ARGS__; in(__VA_ARGS__) using namespace std; void solve(); using ll = long long; template<class T = ll> using V = vector<T>; using vi = V<int>; using vl = V<>; using vvi = V< V<int> >; constexpr int inf = 1001001001; constexpr ll infLL = (1LL << 61) - 1; struct IoSetupNya {IoSetupNya() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); cerr << fixed << setprecision(7);} } iosetupnya; template<typename T, typename U> inline bool amin(T &x, U y) { return (y < x) ? (x = y, true) : false; } template<typename T, typename U> inline bool amax(T &x, U y) { return (x < y) ? (x = y, true) : false; } template<typename T, typename U> ostream& operator <<(ostream& os, const pair<T, U> &p) { os << p.first << " " << p.second; return os; } template<typename T, typename U> istream& operator >>(istream& is, pair<T, U> &p) { is >> p.first >> p.second; return is; } template<typename T> ostream& operator <<(ostream& os, const vector<T> &v) { int s = (int)v.size(); rep(i,s) os << (i ? " " : "") << v[i]; return os; } template<typename T> istream& operator >>(istream& is, vector<T> &v) { for(auto &x : v) is >> x; return is; } void in(){} template <typename T,class... U> void in(T &t,U &...u){ cin >> t; in(u...);} void out(){cout << "\n";} template <typename T,class... U> void out(const T &t,const U &...u){ cout << t; if(sizeof...(u)) cout << " "; out(u...);} template<typename T>void die(T x){out(x); exit(0);} #ifdef NyaanDebug #include "NyaanDebug.h" #define trc(...) do { cerr << #__VA_ARGS__ << " = "; dbg_out(__VA_ARGS__);} while(0) #define trca(v,N) do { cerr << #v << " = "; array_out(v , N);cout << endl;} while(0) #else #define trc(...) #define trca(...) int main(){solve();} #endif #define inc(...) char __VA_ARGS__; in(__VA_ARGS__) #define in2(N,s,t) rep(i,N){in(s[i] , t[i]);} #define in3(N,s,t,u) rep(i,N){in(s[i] , t[i] , u[i]);} using vd = V<double>; using vs = V<string>; using vvl = V< V<> >; template<typename T>using heap = priority_queue< T , V<T> , greater<T> >; //using P = pair<ll,char>; using vp = V<P>; constexpr int MOD = /**/ 1000000007; //*/ 998244353; ////////////////// template<class T> struct compress{ vector<T> xs; compress(const vector<T>& v){ xs.reserve(v.size()); for(T x : v) xs.push_back(x); sort(xs.begin(),xs.end()); xs.erase(unique(xs.begin(),xs.end()) , xs.end()); } int get(const T& x){ return lower_bound(xs.begin(),xs.end(),x) - xs.begin(); } int size(){ return xs.size(); } T& operator[](int i){ return xs[i]; } }; // セグ木 template<typename T,typename F> struct ST{ int size; vector<T> seg; const F func; const T UNIT; ST(int N,F func , T UNIT): func(func) , UNIT(UNIT) { size = 1; while(size < N) size <<= 1; seg.assign(2 * size, UNIT); } ST(const vector<T> &v,F func , T UNIT) : func(func) , UNIT(UNIT){ // initialize int N = (int)v.size(); size = 1; while(size < N) size <<= 1; seg.assign(2 * size , UNIT); // set for(int i = 0; i < N; i++){ seg[i + size] = v[i]; } build(); } void set(int k, T x){ seg[k + size] = x; } void build(){ for(int k = size-1; k > 0; k--){ seg[k] = func(seg[2 * k] , seg[2 * k + 1] ); } } void update(int k, T x){ k += size; seg[k] = x; while(k >>= 1){ seg[k] = func( seg[2 * k] , seg[2 * k + 1] ); } } void add(int k , T x){ k += size; seg[k] += x; while(k >>= 1){ seg[k] = func(seg[2 * k] , seg[2 * k + 1] ); } } // 半開区間[a,b)へのクエリ T query(int a, int b){ T L = UNIT, R = UNIT; for(a+=size,b+=size; a<b; a>>=1,b>>=1){ if(a & 1) L = func(L,seg[a++]); if(b & 1) R = func(seg[--b],R); } return func(L, R); } T operator[](const int &k) const{ return seg[k + size]; } }; template< int mod > struct ModInt { int x; ModInt() : x(0) {} ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {} ModInt &operator+=(const ModInt &p) { if((x += p.x) >= mod) x -= mod; return *this; } ModInt &operator-=(const ModInt &p) { if((x += mod - p.x) >= mod) x -= mod; return *this; } ModInt &operator*=(const ModInt &p) { x = (int) (1LL * x * p.x % mod); return *this; } ModInt &operator/=(const ModInt &p) { *this *= p.inverse(); return *this; } ModInt operator-() const { return ModInt(-x); } ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; } ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; } ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; } ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; } bool operator==(const ModInt &p) const { return x == p.x; } bool operator!=(const ModInt &p) const { return x != p.x; } ModInt inverse() const { int a = x, b = mod, u = 1, v = 0, t; while(b > 0) { t = a / b; swap(a -= t * b, b); swap(u -= t * v, v); } return ModInt(u); } ModInt pow(int64_t n) const { ModInt ret(1), mul(x); while(n > 0) { if(n & 1) ret *= mul; mul *= mul; n >>= 1; } return ret; } friend ostream &operator<<(ostream &os, const ModInt &p) { return os << p.x; } friend istream &operator>>(istream &is, ModInt &a) { int64_t t; is >> t; a = ModInt< mod >(t); return (is); } static int get_mod() { return mod; } }; using modint = ModInt< MOD >; using vm = vector<modint>; void solve(){ ini(N); vi a(N); in(a); compress<int> zip(a); rep(i , N) a[i] = zip.get(a[i]); auto fm = [&](int a,int b){return max(a,b);}; ST<int,decltype(fm)> seg(zip.size() + 1 , fm , 0); using P = pair<int,modint>; vector<vector<P>> dp(N + 1); each(x , dp) x.emplace_back(inf , 0); rep(i , N){ int cur = seg.query(0 , a[i]); seg.update(a[i] , cur + 1); modint nxt; if(cur == 0) { nxt = 1; }else{ nxt = dp[cur].back().second; // にぶたん int ng = 0 , ok = sz(dp[cur]) - 1; while(ng + 1 < ok){ int med = (ng + ok) / 2; if(dp[cur][med].first < a[i]) ok = med; else ng = med; } // idx = okより右側がok // -> 一番後ろの累積からngの累積を引いたもの nxt -= dp[cur][ng].second; } // pb if(dp[cur + 1].back().first == a[i]) dp[cur + 1].back().second += nxt; else{ nxt += dp[cur + 1].back().second; dp[cur + 1].emplace_back(a[i] , nxt); } } out(dp[seg.query(0 , zip.size())].back().second); }