結果

問題 No.992 最長増加部分列の数え上げ
ユーザー はまやんはまやんはまやんはまやん
提出日時 2020-02-14 23:46:08
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 4,490 bytes
コンパイル時間 2,561 ms
コンパイル使用メモリ 213,056 KB
実行使用メモリ 9,340 KB
最終ジャッジ日時 2024-10-06 13:30:28
合計ジャッジ時間 9,282 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 4 ms
7,308 KB
testcase_01 AC 4 ms
7,340 KB
testcase_02 AC 4 ms
7,148 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
testcase_24 WA -
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
testcase_28 WA -
testcase_29 WA -
testcase_30 WA -
testcase_31 WA -
testcase_32 WA -
testcase_33 WA -
testcase_34 WA -
testcase_35 WA -
testcase_36 WA -
testcase_37 WA -
testcase_38 WA -
testcase_39 WA -
testcase_40 WA -
testcase_41 WA -
testcase_42 WA -
testcase_43 WA -
testcase_44 WA -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#define all(x) (x).begin(),(x).end()
//#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60;
template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
//---------------------------------------------------------------------------------------------------
template<int MOD> struct ModInt {
    static const int Mod = MOD; unsigned x; ModInt() : x(0) { }
    ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
    ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
    int get() const { return (int)x; }
    ModInt& operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
    ModInt& operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
    ModInt& operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
    ModInt& operator/=(ModInt that) { return *this *= that.inverse(); }
    ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
    ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
    ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
    ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }
    ModInt inverse() const {
        long long a = x, b = MOD, u = 1, v = 0;
        while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }
        return ModInt(u);
    }
    bool operator==(ModInt that) const { return x == that.x; }
    bool operator!=(ModInt that) const { return x != that.x; }
    ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
    ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r;
}
typedef ModInt<1000000007> mint;
vector<int> compress1(int* v, int n) {
    vector<int> dic;
    rep(i, 0, n) dic.push_back(v[i]);
    sort(all(dic));
    dic.erase(unique(all(dic)), dic.end());
    rep(i, 0, n) v[i] = lower_bound(all(dic), v[i]) - dic.begin();
    return dic;
}
#define def make_pair(0,mint(1))
using V = pair<int, mint>;
template<int NV> struct SegTree { //[l,r)
    V comp(V& l, V& r) { 
        if (l.first < r.first) return r;
        else if (l.first > r.first) return l;
        return make_pair(l.first, l.second + r.second);
    };

    vector<V> val; SegTree() { val = vector<V>(NV * 2, def); }
    V get(int x, int y, int l = 0, int r = NV, int k = 1) {
        if (r <= x || y <= l)return def; if (x <= l && r <= y)return val[k];
        auto a = get(x, y, l, (l + r) / 2, k * 2);
        auto b = get(x, y, (l + r) / 2, r, k * 2 + 1);
        return comp(a, b);
    }
    void update(int i, V v) {
        i += NV; val[i] = v;
        while (i > 1) i >>= 1, val[i] = comp(val[i * 2], val[i * 2 + 1]);
    }
    V operator[](int x) { return get(x, x + 1); }
};
/*---------------------------------------------------------------------------------------------------
            ∧_∧
      ∧_∧  (´<_` )  Welcome to My Coding Space!
     ( ´_ゝ`) /  ⌒i     @hamayanhamayan0
    /   \     | |
    /   / ̄ ̄ ̄ ̄/  |
  __(__ニつ/     _/ .| .|____
     \/____/ (u ⊃
---------------------------------------------------------------------------------------------------*/














int N, A[201010];
SegTree<1 << 18> st;
//---------------------------------------------------------------------------------------------------
void _main() {
    cin >> N;
    rep(i, 0, N) cin >> A[i];
    compress1(A, N);

    rep(i, 0, N) {
        auto p = st.get(0, A[i]);
        p.first++;

        auto cu = st[A[i]];
        st.update(A[i], st.comp(cu, p));
    }
    cout << st.get(0, N).second << endl;

}





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