結果
問題 | No.31 悪のミックスジュース |
ユーザー |
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提出日時 | 2014-09-29 00:22:09 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 18 ms / 5,000 ms |
コード長 | 2,526 bytes |
コンパイル時間 | 712 ms |
コンパイル使用メモリ | 83,324 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-14 15:49:17 |
合計ジャッジ時間 | 1,540 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 17 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:42:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 42 | scanf("%d%d", &N, &V); | ~~~~~^~~~~~~~~~~~~~~~ main.cpp:44:24: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 44 | rep(i, N) scanf("%d", &C[i]); | ~~~~~^~~~~~~~~~~~~
ソースコード
#define _CRT_SECURE_NO_WARNINGS#include <string>#include <vector>#include <algorithm>#include <numeric>#include <set>#include <map>#include <queue>#include <iostream>#include <sstream>#include <cstdio>#include <cmath>#include <ctime>#include <cstring>#include <cctype>#include <cassert>#include <limits>#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))#if defined(_MSC_VER) || __cplusplus > 199711L#define aut(r,v) auto r = (v)#else#define aut(r,v) typeof(v) r = (v)#endif#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)#define all(o) (o).begin(), (o).end()#define pb(x) push_back(x)#define mp(x,y) make_pair((x),(y))#define mset(m,v) memset(m,v,sizeof(m))#define INF 0x3f3f3f3f#define INFL 0x3f3f3f3f3f3f3f3fLLusing namespace std;typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii;typedef long long ll; typedef vector<long long> vl; typedef pair<long long,long long> pll; typedef vector<pair<long long,long long> > vpll;typedef vector<string> vs; typedef long double ld;template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }int main() {int N, V;scanf("%d%d", &N, &V);vector<int> C(N);rep(i, N) scanf("%d", &C[i]);reverse(all(C));vector<long long> sum(N+1);rep(i, N) sum[i+1] = sum[i] + C[i];long long base = sum[N];int V2 = max(0, V - N);int Mi = -1; long long Mcost = INFL;rep(i, N) {// cerr << i << ": " << (sum[N] - sum[i]) * 1. / (N - i) << endl;if(Mi == -1 || (sum[N] - sum[Mi]) * (N - i) > (sum[N] - sum[i]) * (N - Mi)) {Mcost = (sum[N] - sum[i]);Mi = i;}}// cerr << (sum[N] - sum[Mi]) * 1. / (N - Mi) << endl;const int XXX = 1111, YYY = 1111;int t = max(0, V2 / (N - Mi) - XXX);V2 -= (N - Mi) * t;// cerr << Mi << ", " << Mcost << ", " << t << ", " << Mcost * t << ", " << t << ", " << V2 << endl;base += Mcost * t;vector<long long> dp(V2 + YYY + 1, INFL);dp[0] = 0;rep(i, N) {int x = N - i; long long y = sum[N] - sum[i];rer(j, 0, V2 + YYY - x)amin(dp[j + x], dp[j] + y);}// rer(v, 0, V2 + YYY) cerr << v << ": " << dp[v] << endl;long long ans = INFL;rer(v, V2, V2 + YYY)amin(ans, dp[v]);ans += base;printf("%lld\n", ans);return 0;}