結果

問題 No.1036 Make One With GCD 2
ユーザー ningenMe
提出日時 2020-03-12 03:12:00
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 4,148 bytes
コンパイル時間 2,119 ms
コンパイル使用メモリ 179,008 KB
実行使用メモリ 98,432 KB
最終ジャッジ日時 2024-11-07 01:53:16
合計ジャッジ時間 26,684 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 34 TLE * 2 -- * 5
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
 
#define ALL(obj) (obj).begin(),(obj).end()
#define SPEED cin.tie(0);ios::sync_with_stdio(false);
 
template<class T> using PQ = priority_queue<T>;
template<class T> using PQR = priority_queue<T,vector<T>,greater<T>>;
 
constexpr long long MOD = (long long)1e9 + 7;
constexpr long long MOD2 = 998244353;
constexpr long long HIGHINF = (long long)1e18;
constexpr long long LOWINF = (long long)1e15;
constexpr long double PI = 3.1415926535897932384626433;
 
template <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}
template <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}
template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}
template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}
template <class T> void chmax(T& a, const T b){a=max(a,b);}
template <class T> void chmin(T& a, const T b){a=min(a,b);}
void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;}
void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;}
void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;}


template<class Operator> class DisjointSparseTable{
public:
	Operator Op;                           
	using typeNode = decltype(Op.unitNode);
	size_t depth;
	size_t length;
	vector<vector<typeNode>> node;
	vector<size_t> msb;

	DisjointSparseTable(const vector<typeNode>& vec) {
		for(depth = 0;(1<<depth)<=vec.size();++depth);
		length = (1<<depth);
		
		//msb
		msb.resize(length,0);
		for(int i = 0; i < length; ++i) for(int j = 0; j < depth; ++j) if(i>>j) msb[i] = j;

		//init value
		node.resize(depth,vector<typeNode>(length,Op.unitNode));
		for(int i = 0; i < vec.size(); ++i) node[0][i] = vec[i];

		for(int i = 1; i < depth; ++i) {
			for(int r = (1<<i),l = r-1; r < length; r += (2<<i),l = r-1){
				//init accumulate
				node[i][l] = node[0][l];
				node[i][r] = node[0][r];
				//accumulate
				for(int k = 1; k < (1<<i); ++k) {
					node[i][l-k] = Op.funcNode(node[i][l-k+1],node[0][l-k]);
					node[i][r+k] = Op.funcNode(node[i][r+k-1],node[0][r+k]);
				}
			}
		}
	}

	//[l,r)
	typeNode get(int l,int r) {
		r--;
		return (l>r||l<0||length<=r) ? Op.unitNode: (l==r ? node[0][l] : Op.funcNode(node[msb[l^r]][l],node[msb[l^r]][r]));
	}
};

//一点更新 区間最小
template<class typeNode> struct nodeGCD {
	typeNode unitNode = 0;
	typeNode funcNode(typeNode l,typeNode r){return ((r == 0) ? l : funcNode(r, l % r));}
};

int main() {
	SPEED
	int N; cin >> N;
	vector<ll> A(N+1,1);
	for(int i = 0; i < N; ++i) cin >> A[i];
	DisjointSparseTable<nodeGCD<ll>> dst(A);
    ll ans = 0;
    for(int i = 0; i < N; ++i) {
        if(A[i] == 1){
            ans += (N-i);
        }
        else{
            int ok = N,ng = i,md;
            while(ok-ng>1){
                md = (ok+ng)/2;
                (dst.get(i,md+1)==1?ok:ng)=md;
            }
            ans += (N-ok);
        }
    }
    cout << ans << endl;
	return 0;
}
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