結果
| 問題 |
No.1011 Infinite Stairs
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-03-20 21:35:22 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 222 ms / 2,000 ms |
| コード長 | 4,276 bytes |
| コンパイル時間 | 1,617 ms |
| コンパイル使用メモリ | 172,496 KB |
| 実行使用メモリ | 109,440 KB |
| 最終ジャッジ日時 | 2024-07-17 11:45:01 |
| 合計ジャッジ時間 | 3,311 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 24 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using VI = vector<int>;
using VL = vector<ll>;
using loop = int;
template<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;
#define FOR(i,a,n) for(loop (i)=(a);(i)<(n);++(i))
#define eFOR(i,a,n) for(loop (i)=(a);(i)<=(n);++(i))
#define rFOR(i,a,n) for(loop (i)=(n)-1;(i)>=(a);--(i))
#define erFOR(i,a,n) for(loop (i)=(n);(i)>=(a);--(i))
#define each(i, a) for(auto &i : a)
#define SORT(i) sort((i).begin(),(i).end())
#define rSORT(i,a) sort((i).begin(),(i).end(),(a))
#define all(i) (i).begin(),(i).end()
#define out(y,x) ((y) < 0 || h <= (y) || (x) < 0 || w <= (x))
#define line cout << "------------------------\n"
#define ENDL(i,n) ((i) == (n) - 1 ? "\n" : " ")
//#define stop system("pause") //comment out this on AOJ.
constexpr ll INF = 1000000000;
constexpr ll LLINF = 1LL << 60;
constexpr ll mod = 1000000007;
constexpr ll MOD = 998244353;
constexpr ld eps = 1e-10;
constexpr ld pi = 3.1415926535897932;
template<class T>inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; }return false; }
template<class T>inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; }return false; }
inline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }
template<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& elemnt : v)is >> elemnt; return is; }
template<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }
template<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }
template<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }
template<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }
template<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }
template<int modulo> struct ModInt {
int x;
ModInt() : x(0) {}
ModInt(long long y) : x(y >= 0 ? y % modulo : (modulo - (-y) % modulo) % modulo) {}
ModInt& operator+=(const ModInt& p) {
if ((x += p.x) >= modulo) x -= modulo;
return *this;
}
ModInt& operator-=(const ModInt& p) {
if ((x += modulo - p.x) >= modulo) x -= modulo;
return *this;
}
ModInt& operator*=(const ModInt& p) {
x = (int)(1LL * x * p.x % modulo);
return *this;
}
ModInt& operator/=(const ModInt& p) {
*this *= p.inverse();
return *this;
}
ModInt operator-() const { return ModInt(-x); }
ModInt operator+(const ModInt& p) const { return ModInt(*this) += p; }
ModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; }
ModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; }
ModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; }
bool operator==(const ModInt& p) const { return x == p.x; }
bool operator!=(const ModInt& p) const { return x != p.x; }
ModInt inverse() const {
int a = x, b = modulo, u = 1, v = 0, t;
while (b > 0) {
t = a / b;
a -= t * b;
swap(a, b);
u -= t * v;
swap(u, v);
}
return ModInt(u);
}
ModInt pow(int e) {
long long a = 1, p = x;
while (e > 0) {
if (e % 2 == 0) { p = (p * p) % modulo; e /= 2; }
else { a = (a * p) % modulo; e--; }
}
return ModInt(a);
}
friend ostream& operator<<(ostream& os, const ModInt<modulo>& p) {
return os << p.x;
}
friend istream& operator>>(istream& is, ModInt<modulo>& a) {
long long x;
is >> x;
a = ModInt<modulo>(x);
return (is);
}
};
using modint = ModInt<mod>;
int main() {
init();
ll n, d, k; cin >> n >> d >> k;
auto dp = vec<modint>(n + 1, k + 1);
dp[0][0] = 1;
FOR(i, 0, n) {
FOR(j, 0, k)dp[i][j + 1] += dp[i][j];
eFOR(j, 1, k) {
dp[i + 1][j] += dp[i][j - 1];
if (0 < j - d)dp[i + 1][j] -= dp[i][j - d - 1];
}
}
cout << dp[n][k] << "\n";
}