結果

問題 No.889 素数!
ユーザー tonnnura172tonnnura172
提出日時 2020-03-29 06:25:13
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 1,922 bytes
コンパイル時間 404 ms
コンパイル使用メモリ 12,416 KB
実行使用メモリ 12,544 KB
最終ジャッジ日時 2025-01-02 13:05:40
合計ジャッジ時間 5,117 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample RE * 3
other RE * 61
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians
from itertools import accumulate, permutations, combinations, product
from operator import itemgetter, mul, add
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left
from fractions import gcd
from heapq import heappush, heappop
from functools import reduce
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def ZIP(n): return zip(*(MAP() for _ in range(n)))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7
N = INT()
def is_prime(num):
""" """
from math import sqrt
if num < 2:
return False
if num in [2, 3, 5]:
return True
if num % 2 == 0 or num % 3 == 0 or num % 5 == 0:
return False
# (23)
prime = 7
step = 4
num_sqrt = sqrt(num)
while prime <= num_sqrt:
if num % prime == 0:
return False
prime += step
step = 6 - step
return True
def is_heihou(num):
if num >= 2 and (num**(1/2)).is_integer():
return True
else:
False
def is_rippou(num):
if num >= 2 and (num**(1/3)).is_integer():
return True
else:
False
def is_kanzen(num):
divisors = []
for i in range(1, int(num**0.5)+1):
if num % i == 0:
divisors.append(i)
if i != num // i:
divisors.append(num//i)
if num >= 1 and sum(divisors) - num == num:
return True
else:
False
if is_prime(N):
print("Sosu!")
elif is_heihou(N):
print("Heihosu!")
elif is_rippou(N):
print("Ripposu!")
elif is_kanzen(N):
print("Kanzensu!")
else:
print(N)
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