結果

問題 No.344 ある無理数の累乗
ユーザー firiexp
提出日時 2020-03-30 01:47:48
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
CE  
(最新)
AC  
(最初)
実行時間 -
コード長 4,585 bytes
コンパイル時間 749 ms
コンパイル使用メモリ 85,816 KB
最終ジャッジ日時 2024-11-14 22:14:29
合計ジャッジ時間 1,333 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
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コンパイルエラー時のメッセージ・ソースコードは、提出者また管理者しか表示できないようにしております。(リジャッジ後のコンパイルエラーは公開されます)
ただし、clay言語の場合は開発者のデバッグのため、公開されます。

コンパイルメッセージ
main.cpp:18:39: error: '::numeric_limits' has not been declared
   18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
      |                                       ^~~~~~~~~~~~~~
main.cpp:18:55: error: expected primary-expression before '>' token
   18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
      |                                                       ^
main.cpp:18:61: error: no matching function for call to 'max()'
   18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
      |                                                        ~~~~~^~
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/string:50,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/locale_classes.h:40,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/ios_base.h:41,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ios:42,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:38,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/iostream:39,
                 from main.cpp:1:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note: candidate: 'template<class _Tp> constexpr const _Tp& std::max(const _Tp&, const _Tp&)'
  254 |     max(const _Tp& __a, const _Tp& __b)
      |     ^~~
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note:   template argument deduction/substitution failed:
main.cpp:18:61: note:   candidate expects 2 arguments, 0 provided
   18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
      |                                                        ~~~~~^~
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:300:5: note: candidate: 'templat

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <iomanip>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <numeric>
#include <bitset>
#include <cmath>
static const int MOD = 1000;
using ll = long long;
using u32 = unsigned;
using u64 = unsigned long long;
using namespace std;
template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
template<u32 M = 1000000007>
struct modint{
u32 val;
modint(): val(0){}
template<typename T>
modint(T t){t %= (T)M; if(t < 0) t += (T)M; val = t;}
modint pow(ll k) const {
modint res(1), x(val);
while(k){
if(k&1) res *= x;
x *= x;
k >>= 1;
}
return res;
}
template<typename T>
modint& operator=(T t){t %= (T)M; if(t < 0) t += (T)M; val = t; return *this;}
modint inv() const {return pow(M-2);}
modint& operator+=(modint a){val += a.val; if(val >= M) val -= M; return *this;}
modint& operator-=(modint a){if(val < a.val) val += M-a.val; else val -= a.val; return *this;}
modint& operator*=(modint a){val = (u64)val*a.val%M; return *this;}
modint& operator/=(modint a){return (*this) *= a.inv();}
modint operator+(modint a) const {return modint(val) +=a;}
modint operator-(modint a) const {return modint(val) -=a;}
modint operator*(modint a) const {return modint(val) *=a;}
modint operator/(modint a) const {return modint(val) /=a;}
modint operator-(){return modint(M-val);}
bool operator==(const modint a) const {return val == a.val;}
bool operator!=(const modint a) const {return val != a.val;}
bool operator<(const modint a) const {return val < a.val;}
};
using mint = modint<MOD>;
template<class H, size_t SIZE>
struct SquareMatrix {
using T = typename H::T;
using ar = array<T, SIZE>;
using mat = array<ar, SIZE>;
mat A;
SquareMatrix() = default;
static SquareMatrix I(){
SquareMatrix X{};
for (int i = 0; i < SIZE; ++i) {
for (int j = 0; j < SIZE; ++j) {
if(i == j) X[i][j] = H::one();
else X[i][j] = H::zero();
}
}
return X;
}
friend ar operator*=(ar &x, const SquareMatrix &Y) {
ar ans{};
for (int i = 0; i < SIZE; ++i) {
for (int j = 0; j < SIZE; ++j) {
H::add(ans[j], H::mul(x[i], Y[i][j]));
}
}
x.swap(ans);
return x;
}
friend ar operator*(ar x, const SquareMatrix &Y) { return x *= Y; }
inline const ar &operator[](int k) const{ return (A.at(k)); }
inline ar &operator[](int k) { return (A.at(k)); }
SquareMatrix &operator+= (const SquareMatrix &B){
for (int i = 0; i < SIZE; ++i) {
for (int j = 0; j < SIZE; ++j) {
H::add((*this)[i][j], B[i][j]);
}
}
return (*this);
}
SquareMatrix &operator-= (const SquareMatrix &B){
for (int i = 0; i < SIZE; ++i) {
for (int j = 0; j < SIZE; ++j) {
H::add((*this)[i][j], -B[i][j]);
}
}
return (*this);
}
SquareMatrix &operator*=(const SquareMatrix &B) {
SquareMatrix C{};
for (int i = 0; i < SIZE; ++i) {
for (int k = 0; k < SIZE; ++k) {
for (int j = 0; j < SIZE; ++j) {
H::add(C[i][j], H::mul((*this)[i][k], B[k][j]));
}
}
}
A.swap(C.A);
return (*this);
}
SquareMatrix pow(ll n) const {
SquareMatrix a = (*this), res = I();
while(n > 0){
if(n & 1) res *= a;
a *= a;
n >>= 1;
}
return res;
}
SquareMatrix operator+(const SquareMatrix &B) const {return SquareMatrix(*this) += B;}
SquareMatrix operator-(const SquareMatrix &B) const {return SquareMatrix(*this) -= B;}
SquareMatrix operator*(const SquareMatrix &B) const {return SquareMatrix(*this) *= B;}
};
struct SemiRing {
using T = mint;
static inline T mul(T x, T y){ return x * y; }
static inline void add(T &x, T y){ x += y; }
static inline T one(){ return {1}; }
static inline T zero(){ return {0}; }
};
using ar = array<SemiRing::T, 2>;
using mat = SquareMatrix<SemiRing, 2>;
int main() {
int n;
cin >> n;
if(!n){
puts("1");
return 0;
}
ar x{1, 0};
mat A;
A[0][0] = 1; A[0][1] = 1;
A[1][0] = 3; A[1][1] = 1;
x *= A.pow(n);
printf("%d\n", (x[0]+x[0] - mint(1-(n&1))).val);
return 0;
}
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