結果

問題 No.213 素数サイコロと合成数サイコロ (3-Easy)
コンテスト
ユーザー rpy3cpp
提出日時 2015-08-24 19:04:27
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 171 ms / 3,000 ms
コード長 2,361 bytes
コンパイル時間 256 ms
コンパイル使用メモリ 82,164 KB
実行使用メモリ 76,472 KB
最終ジャッジ日時 2024-07-18 13:10:36
合計ジャッジ時間 997 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge2
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ファイルパターン 結果
other AC * 2
権限があれば一括ダウンロードができます

ソースコード

diff # 

def solve(N, P, C):
    mod = 10 ** 9 + 7
    ps = [2-2, 3-2, 5-2, 7-2, 11-2, 13-2]
    cs = [4-4, 6-4, 8-4, 9-4, 10-4, 12-4]
    distp = get_dist(ps, P)
    distc = get_dist(cs, C)
    dist = merge_dists(distp, distc)
    coefs = [0] * (2 * P + 4 * C - 1) + dist
    coefs.reverse()
    inits = set_inits(coefs, mod)
    inits_tricked = trick_inits(inits, coefs, mod)
    return LRS(inits_tricked, coefs, N - 1, mod)

def set_inits(coefs, mod):
    inits = [1]
    n = len(coefs)
    for i in range(1, n):
        v = sum(a * c for a, c, in zip(inits, coefs[-i:])) % mod
        inits.append(v)
    return inits

def trick_inits(bs, coefs, mod):
    k = len(coefs)
    inits = [0] * k
    for i in range(k):
        bbs = [0] * i + bs[:k - i]
        tmp = sum(coefs[:k - i])
        for j in range(k):
            inits[j] += bbs[j] * tmp
    return inits

def get_dist(qs, Q):
    len_dp = qs[-1] * Q + 1
    dp = [[0] * len_dp for n in range(Q + 1)]
    dp[0][0] = 1
    for q in qs:
        for n in range(1, Q + 1):
            current_dp = dp[n]
            prev_dp = dp[n - 1]
            for s in range(q, q * n + 1):
                current_dp[s] += prev_dp[s - q]
    return dp[Q]

def merge_dists(distp, distc):
    mod = 10 ** 9 + 7
    len_p = len(distp)
    len_c = len(distc)
    dist = [0] * (len_p + len_c - 1)
    for i, pi in enumerate(distp):
        for ij, cj in enumerate(distc, i):
            dist[ij] += pi * cj
            dist[ij] %= mod
    return dist

def poly_mult(poly1, poly2, f, mod):
    n = len(f)
    poly_long = [0] * (2 * n - 1)
    for i, p1 in enumerate(poly1):
        for j, p2 in enumerate(poly2):
            poly_long[i + j] += p1 * p2
    for i in range(2 * n - 2, n - 1, -1):
        p = poly_long[i] % mod
        for j, fk in enumerate(f, i - n):
            poly_long[j] += p * fk
    poly = [p % mod for p in poly_long[:n]]
    return poly

def poly_pow(f, p, mod):
    n = len(f)
    polyR = [0] * n
    polyR[0] = 1
    poly = [0] * n
    poly[1] = 1
    while p:
        if p & 1: polyR = poly_mult(poly, polyR, f, mod)
        poly = poly_mult(poly, poly, f, mod)
        p >>= 1
    return polyR

def LRS(As, Cs, n, mod):
    poly = poly_pow(Cs, n, mod)
    return sum(p * a for p, a in zip(poly, As)) % mod


if __name__ == '__main__':
    N, P, C = map(int, input().split())
    print(solve(N, P, C))
0