結果

問題 No.1018 suffixsuffixsuffix
ユーザー n_vip
提出日時 2020-04-03 23:04:38
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 307 ms / 2,000 ms
コード長 5,372 bytes
コンパイル時間 2,611 ms
コンパイル使用メモリ 151,204 KB
最終ジャッジ日時 2025-01-09 13:37:15
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 34
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <string>
#include <vector>
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<stack>
#include<queue>
#include<cmath>
#include<algorithm>
#include<functional>
#include<list>
#include<deque>
#include<bitset>
#include<set>
#include<map>
#include<unordered_map>
#include<unordered_set>
#include<cstring>
#include<sstream>
#include<complex>
#include<iomanip>
#include<numeric>
#include<cassert>
#include<random>
#define X first
#define Y second
#define pb push_back
#define rep(X,Y) for (int (X) = 0;(X) < (Y);++(X))
#define reps(X,S,Y) for (int (X) = S;(X) < (Y);++(X))
#define rrep(X,Y) for (int (X) = (Y)-1;(X) >=0;--(X))
#define rreps(X,S,Y) for (int (X) = (Y)-1;(X) >= (S);--(X))
#define repe(X,Y) for ((X) = 0;(X) < (Y);++(X))
#define peat(X,Y) for (;(X) < (Y);++(X))
#define all(X) (X).begin(),(X).end()
#define rall(X) (X).rbegin(),(X).rend()
#define eb emplace_back
#define UNIQUE(X) (X).erase(unique(all(X)),(X).end())
#define Endl endl
#define NL <<"\n"
using namespace std;
using ll=long long;
using pii=pair<int,int>;
using pll=pair<ll,ll>;
template<class T> using vv=vector<vector<T>>;
template<class T> inline bool MX(T &l,const T &r){return l<r?l=r,1:0;}
template<class T> inline bool MN(T &l,const T &r){return l>r?l=r,1:0;}
//#undef NUIP
#ifdef NUIP
#include "benri.h"
#else
#define out(args...)
#endif
#ifdef __cpp_init_captures
template<typename T>vector<T> table(int n, T v){ return vector<T>(n, v);}
template <class... Args> auto table(int n, Args... args){auto val = table(args...); return vector<decltype(val)>(n, move(val));}
#endif
const ll MOD=1e9+7; //998244353
struct RMQ{
const int INF=MOD;
vv<int> mn;
int D;
void upd(const vector<int> &v){
mn.clear();
D=0;
for(int i=v.size();i;i/=2) ++D;
mn.resize(D+1,vector<int>(1<<D+1,INF));
rep(i,v.size()) mn[D][i]=v[i];
rrep(i,D)rep(j,1<<D){
int b=(j>>(D-i)|1)<<(D-i);
//assert(b!=(1<<D) || !(j>>(D-i)&1));
mn[i][j]=j>>(D-i)&1?get(b,j+1):get(j,b);
}
}
RMQ(){}
RMQ(const vector<int> &v){upd(v);}
int get(int l,int r){ //[l,r)
--r;
if(l==r)return mn[D][l];
if(l>r) return INF;
int d=__builtin_clz(l^r)+D-31;
return min(mn[d][l],mn[d][r]);
}
};
// Larsson-Sadakane's Suffix array Construction: O(n (log n)^2)
struct SA:public vector<int>{
struct SAComp {
const int h;
const vector<int> &g;
SAComp(int h, const vector<int> &g) : h(h), g(g) {}
bool operator() (int a, int b) {
return a == b ? false : g[a] != g[b] ? g[a] < g[b] : g[a+h] < g[b+h];
}
};
vector<int> inv,lcp;
string str;
RMQ rmq;
SA(){}
SA(const string &str):str(str){build(str);}
void build(const string &s){
str=s;
buildSA();
buildLCP();
rmq.upd(lcp);
inv.resize(size());
rep(i,size()) inv[at(i)]=i;
}
void buildSA(){
int n=str.size();
vector<int> g(n+1),b(n+1);
resize(n+1);
rep(i,n+1) at(i)=i, g[i]=str[i];
sort(all(*this), SAComp(0,g));
for(int h=1; b[n]!=n; h*=2) {
SAComp comp(h,g);
sort(all(*this),comp);
rep(i,n) b[i+1]=b[i]+comp(at(i),at(i+1));
rep(i,n+1) g[at(i)]=b[i];
}
}
void buildLCP(){
int n=str.size();
int h=0;
vector<int> b(n+1);
lcp.resize(n+1);
rep(i,n+1) b[at(i)]=i;
rep(i,n+1) {
if(b[i]){
for (int j=at(b[i]-1); j+h<n && i+h<n && str[j+h]==str[i+h]; ++h);
lcp[b[i]]=h;
} else lcp[b[i]]=-1;
if (h>0) --h;
}
}
int getMn(int l,int r){return rmq.get(l+1,r+1);}
};
ostream& operator<<(ostream &os,const SA &sa){
rep(i,sa.size()) os<<sa.lcp[i]<<"\t"<<sa.str.substr(sa[i])<<endl;
return os;
}
void kmp(const string &str,vector<int> &re){
re.resize(str.size()+1); re[0]=-1;
int j=-1;
rep(i,str.size()){
while(j>=0 && str[i]!=str[j]) j=re[j];
re[i+1]=++j;
}
}
vector<ll> solve(string s,ll m,vector<ll> inds){
const int q=inds.size();
const int n=s.size();
if(m==1){
SA sa(s);
vector<ll> re(q);
rep(i,q) re[i]=sa[inds[i]+1];
return re;
}
SA sa(s+s);
out(sa,1);
vector<pll> ps;
ll cur=0;
for(auto x:sa){
if(x==2*n) continue;
ps.eb(cur,x);
if(x<n) cur+=m-1;
else ++cur;
}
ps.eb(cur,-1);
assert(cur==n*m);
out(ps,1);
vector<ll> re(q);
ll ad=(m-2ll)*n;
rep(i,q){
auto ind=inds[i];
auto p=*(upper_bound(all(ps),pll(ind,MOD))-1);
out(p,1);
auto dif=ind-p.X;
re[i]=p.Y+ad-n*dif;
}
return re;
}
vector<ll> naive(string s,ll m,vector<ll> inds){
string ss;
rep(_,m) ss+=s;
return solve(ss,1,inds);
}
vector<ll> solve2(string s,ll m,vector<ll> inds){
const int n=s.size();
vector<int> kmp;
::kmp(s,kmp);
out(kmp,1);
int t=n-kmp.back();
if(kmp.back() && n%t==0){
s=s.substr(0,t);
m*=n/t;
}
out(s,m,1);
return solve(s,m,inds);
}
int main(){
ios_base::sync_with_stdio(false); cin.tie(0);
cout<<fixed<<setprecision(0);
if(0){
rep(_,10000){
const int n=rand()%10+1;
string s(n,'.');
for(char &c:s) c=rand()%1+'a';
// s+=s; s+=s;
// s.resize(rand()%s.size()+1);
int m=10;
vector<ll> inds(s.size()*m); iota(all(inds),0);
auto exp=naive(s,m,inds);
auto act=solve2(s,m,inds);
if(exp!=act){
out(s,m,inds,exp,act,1);
return 0;
}
}
return 0;
}
ll n,m,q;
cin>>n>>m>>q;
string s;
cin>>s;
vector<ll> inds(q);
for(auto &x:inds) cin>>x, --x;
auto re=solve2(s,m,inds);
rep(i,q) cout<<re[i]+1<<" \n"[i+1==q];
return 0;
}
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