結果

問題 No.25 有限小数
コンテスト
ユーザー fumiphys
提出日時 2020-04-07 01:00:36
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 5,000 ms
コード長 4,420 bytes
コンパイル時間 1,507 ms
コンパイル使用メモリ 171,724 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-07-07 10:36:48
合計ジャッジ時間 2,655 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge2
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ファイルパターン 結果
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff # 

// includes
#include <bits/stdc++.h>
using namespace std;

// macros
#define pb emplace_back
#define mk make_pair
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define whole(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define bit(n) (1LL<<(n))
// functions
template <typename T> void unique(T& c){c.erase(std::unique(c.begin(), c.end()), c.end());}
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << "(" << p.first << ", " << p.second << ")"; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << "(" << itr->first << ", " << itr->second << ")"; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << "(" << itr->first << ", " << itr->second << ")"; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
//  types
using ll = long long int;
using P = pair<int, int>;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1000000007;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// io
struct fast_io{
  fast_io(){ios_base::sync_with_stdio(false); cin.tie(nullptr); cout << fixed << setprecision(20);}
} fast_io_;

template<typename T>
T gcd(T a, T b) {
  if(a > b)return gcd(b, a);
  if(a == 0)return b;
  return gcd(b % a, a);
}

ostream& operator<<(ostream& dest, __int128_t value) {
  ostream::sentry s(dest);
  if(s){
    __uint128_t tmp = value < 0 ? - value: value;
    char buf[128];
    char *d = end(buf);
    do{
      --d;
      *d = "0123456789"[tmp % 10];
      tmp /= 10;
    }while(tmp != 0);
    if(value < 0)--d, *d='-';
    int len = end(buf) - d;
    if(dest.rdbuf()->sputn(d, len) != len){
      dest.setstate(ios_base::badbit);
    }
  }
  return dest;
}

__int128_t to_int128(string s){
  __int128_t res = 0;
  for(size_t i = 0; i < s.size(); i++){
    res = res * 10 + (s[i] - '0');
  }
  return res;
}


using Int = __int128_t;

int main(int argc, char const* argv[])
{
  ll nl, ml; cin >> nl >> ml;
  Int n = nl, m = ml;
  ll g = gcd(n, m);
  n /= g, m /= g;
  // check finite
  ll tmp = m;
  while(tmp % 2 == 0)tmp /= 2;
  while(tmp % 5 == 0)tmp /= 5;
  if(tmp != 1){
    cout << -1 << endl;
    return 0;
  }
  // check finite
  // calc decimal
  vector<int> v;
  while(10 * m <= n)m *= 10;
  while(n){
    if(n % m == 0){
      ll t = n / m;
      while(t){
        v.pb(t % 10);
        t /= 10;
      }
      break;
    }
    while(n < m){
      n *= 10;
    }
    v.pb((n / m) % 10);
    n = n - ((n / m) % 10) * m;
  }
  //cerr << v << endl;
  while(sz(v) && v.back() == 0)v.pop_back();
  cout << v.back() << endl;
  // calc decimal
  return 0;
}
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