結果

問題 No.1025 Modular Equation
ユーザー beet
提出日時 2020-04-10 23:16:36
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 7,474 bytes
コンパイル時間 2,603 ms
コンパイル使用メモリ 215,596 KB
最終ジャッジ日時 2025-01-09 16:51:16
ジャッジサーバーID
(参考情報)
judge2 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2 WA * 1
other AC * 4 WA * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
template<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}
template<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}
using Int = long long;
const char newl = '\n';
template<typename T,T MOD = 1000000007>
struct Mint{
static constexpr T mod = MOD;
T v;
Mint():v(0){}
Mint(signed v):v(v){}
Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}
Mint pow(long long k){
Mint res(1),tmp(v);
while(k){
if(k&1) res*=tmp;
tmp*=tmp;
k>>=1;
}
return res;
}
static Mint add_identity(){return Mint(0);}
static Mint mul_identity(){return Mint(1);}
Mint inv(){return pow(MOD-2);}
Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}
Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}
Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}
Mint& operator/=(Mint a){return (*this)*=a.inv();}
Mint operator+(Mint a) const{return Mint(v)+=a;}
Mint operator-(Mint a) const{return Mint(v)-=a;}
Mint operator*(Mint a) const{return Mint(v)*=a;}
Mint operator/(Mint a) const{return Mint(v)/=a;}
Mint operator-() const{return v?Mint(MOD-v):Mint(v);}
bool operator==(const Mint a)const{return v==a.v;}
bool operator!=(const Mint a)const{return v!=a.v;}
bool operator <(const Mint a)const{return v <a.v;}
static Mint comb(long long n,int k){
Mint num(1),dom(1);
for(int i=0;i<k;i++){
num*=Mint(n-i);
dom*=Mint(i+1);
}
return num/dom;
}
};
template<typename T,T MOD> constexpr T Mint<T, MOD>::mod;
template<typename T,T MOD>
ostream& operator<<(ostream &os,Mint<T, MOD> m){os<<m.v;return os;}
namespace FFT{
using dbl = double;
struct num{
dbl x,y;
num(){x=y=0;}
num(dbl x,dbl y):x(x),y(y){}
};
inline num operator+(num a,num b){
return num(a.x+b.x,a.y+b.y);
}
inline num operator-(num a,num b){
return num(a.x-b.x,a.y-b.y);
}
inline num operator*(num a,num b){
return num(a.x*b.x-a.y*b.y,a.x*b.y+a.y*b.x);
}
inline num conj(num a){
return num(a.x,-a.y);
}
int base=1;
vector<num> rts={{0,0},{1,0}};
vector<int> rev={0,1};
const dbl PI=asinl(1)*2;
void ensure_base(int nbase){
if(nbase<=base) return;
rev.resize(1<<nbase);
for(int i=0;i<(1<<nbase);i++)
rev[i]=(rev[i>>1]>>1)+((i&1)<<(nbase-1));
rts.resize(1<<nbase);
while(base<nbase){
dbl angle=2*PI/(1<<(base+1));
for(int i=1<<(base-1);i<(1<<base);i++){
rts[i<<1]=rts[i];
dbl angle_i=angle*(2*i+1-(1<<base));
rts[(i<<1)+1]=num(cos(angle_i),sin(angle_i));
}
base++;
}
}
void fft(vector<num> &as){
int n=as.size();
assert((n&(n-1))==0);
int zeros=__builtin_ctz(n);
ensure_base(zeros);
int shift=base-zeros;
for(int i=0;i<n;i++)
if(i<(rev[i]>>shift))
swap(as[i],as[rev[i]>>shift]);
for(int k=1;k<n;k<<=1){
for(int i=0;i<n;i+=2*k){
for(int j=0;j<k;j++){
num z=as[i+j+k]*rts[j+k];
as[i+j+k]=as[i+j]-z;
as[i+j]=as[i+j]+z;
}
}
}
}
template<typename T>
vector<long long> multiply(vector<T> &as,vector<T> &bs){
int need=as.size()+bs.size()-1;
int nbase=0;
while((1<<nbase)<need) nbase++;
ensure_base(nbase);
int sz=1<<nbase;
vector<num> fa(sz);
for(int i=0;i<sz;i++){
T x=(i<(int)as.size()?as[i]:0);
T y=(i<(int)bs.size()?bs[i]:0);
fa[i]=num(x,y);
}
fft(fa);
num r(0,-0.25/sz);
for(int i=0;i<=(sz>>1);i++){
int j=(sz-i)&(sz-1);
num z=(fa[j]*fa[j]-conj(fa[i]*fa[i]))*r;
if(i!=j)
fa[j]=(fa[i]*fa[i]-conj(fa[j]*fa[j]))*r;
fa[i]=z;
}
fft(fa);
vector<long long> res(need);
for(int i=0;i<need;i++)
res[i]=round(fa[i].x);
return res;
}
};
template<typename T>
struct ArbitraryMod{
using dbl=FFT::dbl;
using num=FFT::num;
vector<T> multiply(vector<T> as,vector<T> bs){
int need=as.size()+bs.size()-1;
int sz=1;
while(sz<need) sz<<=1;
vector<num> fa(sz),fb(sz);
for(int i=0;i<(int)as.size();i++)
fa[i]=num(as[i].v&((1<<15)-1),as[i].v>>15);
for(int i=0;i<(int)bs.size();i++)
fb[i]=num(bs[i].v&((1<<15)-1),bs[i].v>>15);
fft(fa);fft(fb);
dbl ratio=0.25/sz;
num r2(0,-1),r3(ratio,0),r4(0,-ratio),r5(0,1);
for(int i=0;i<=(sz>>1);i++){
int j=(sz-i)&(sz-1);
num a1=(fa[i]+conj(fa[j]));
num a2=(fa[i]-conj(fa[j]))*r2;
num b1=(fb[i]+conj(fb[j]))*r3;
num b2=(fb[i]-conj(fb[j]))*r4;
if(i!=j){
num c1=(fa[j]+conj(fa[i]));
num c2=(fa[j]-conj(fa[i]))*r2;
num d1=(fb[j]+conj(fb[i]))*r3;
num d2=(fb[j]-conj(fb[i]))*r4;
fa[i]=c1*d1+c2*d2*r5;
fb[i]=c1*d2+c2*d1;
}
fa[j]=a1*b1+a2*b2*r5;
fb[j]=a1*b2+a2*b1;
}
fft(fa);fft(fb);
vector<T> cs(need);
using ll = long long;
for(int i=0;i<need;i++){
ll aa=T(llround(fa[i].x)).v;
ll bb=T(llround(fb[i].x)).v;
ll cc=T(llround(fa[i].y)).v;
cs[i]=T(aa+(bb<<15)+(cc<<30));
}
return cs;
}
};
template<typename T>
struct Rint{
static T mod;
static void set_mod(T nmod){mod=nmod;}
T v;
Rint():v(0){}
Rint(signed v):v(v){}
Rint(long long t){v=t%mod;if(v<0) v+=mod;}
Rint pow(long long k){
Rint res(1),tmp(v);
while(k){
if(k&1) res*=tmp;
tmp*=tmp;
k>>=1;
}
return res;
}
static Rint add_identity(){return Rint(0);}
static Rint mul_identity(){return Rint(1);}
Rint inv(){return pow(mod-2);}
Rint& operator+=(Rint a){v+=a.v;if(v>=mod)v-=mod;return *this;}
Rint& operator-=(Rint a){v+=mod-a.v;if(v>=mod)v-=mod;return *this;}
Rint& operator*=(Rint a){v=1LL*v*a.v%mod;return *this;}
Rint& operator/=(Rint a){return (*this)*=a.inv();}
Rint operator+(Rint a) const{return Rint(v)+=a;}
Rint operator-(Rint a) const{return Rint(v)-=a;}
Rint operator*(Rint a) const{return Rint(v)*=a;}
Rint operator/(Rint a) const{return Rint(v)/=a;}
Rint operator-() const{return v?Rint(mod-v):Rint(v);}
bool operator==(const Rint a)const{return v==a.v;}
bool operator!=(const Rint a)const{return v!=a.v;}
bool operator <(const Rint a)const{return v <a.v;}
};
template<typename T> T Rint<T>::mod;
template<typename T>
ostream& operator<<(ostream &os,Rint<T> m){os<<m.v;return os;}
//INSERT ABOVE HERE
signed main(){
cin.tie(0);
ios::sync_with_stdio(0);
int p,n,k,b;
cin>>p>>n>>k>>b;
vector<int> as(n);
for(int i=0;i<n;i++) cin>>as[i];
using R = Rint<int>;
R::set_mod(p);
vector<R> ps(p);
for(int i=0;i<p;i++)
ps[i]=R(i).pow(k);
using M = Mint<int>;
ArbitraryMod<M> arb;
using Poly = vector<M>;
M po{1};
map<int, int> cnt,rpr;
for(int i=0;i<n;i++){
if(as[i]==0) po*=M(p);
int o=p;
for(int j=0;j<p;j++)
chmin(o,(R(as[i])*ps[j]).v);
cnt[o]++;
rpr[o]=i;
}
auto mul=[&](Poly &as,Poly &bs){
assert((int)as.size()==p);
assert((int)bs.size()==p);
auto cs=arb.multiply(as,bs);
for(int j=p;j<(int)cs.size();j++) cs[j-p]+=cs[j];
cs.resize(p);
return cs;
};
Poly dp(p,0);
dp[0]=1;
for(auto tmp:cnt){
int i=rpr[tmp.first];
Poly ad(p,0);
for(int j=0;j<p;j++)
ad[(R(as[i])*ps[j]).v]+=M(1);
int x=tmp.second;
while(x){
if(x&1) dp=mul(dp,ad);
x>>=1;
if(x) ad=mul(ad,ad);
}
}
cout<<dp[b]*po<<newl;
return 0;
}
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