結果

問題 No.1024 Children in a Row
ユーザー 👑 emthrmemthrm
提出日時 2020-04-14 23:46:42
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,711 bytes
コンパイル時間 3,982 ms
コンパイル使用メモリ 213,444 KB
最終ジャッジ日時 2025-01-09 19:12:28
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2 WA * 1
other AC * 2 WA * 25
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
using namespace std;
#define FOR(i,m,n) for(int i=(m);i<(n);++i)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(),(v).end()
using ll = long long;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3f3fLL;
const double EPS = 1e-8;
const int MOD = 1000000007;
// const int MOD = 998244353;
const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};
const int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};
template <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }
template <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }
struct IOSetup {
IOSetup() {
cin.tie(nullptr);
ios_base::sync_with_stdio(false);
cout << fixed << setprecision(20);
}
} iosetup;
int main() {
int n, m; cin >> n >> m;
vector<int> a(m), b(m), k(m); REP(i, m) cin >> a[i] >> b[i] >> k[i], --a[i], --b[i];
vector<vector<vector<pair<int, int>>>> graph(n, vector<vector<pair<int, int>>>(1));
vector<int> dst(m);
REP(i, m) {
dst[i] = graph[a[i]].size();
graph[a[i]].emplace_back();
graph[b[i]].back().emplace_back(a[i], dst[i]);
}
// REP(i, m) cout << dst[i] << " \n"[i + 1 == m];
vector<vector<int>> l(n), r(n);
REP(i, n) {
l[i].resize(graph[i].size());
r[i].resize(graph[i].size());
}
vector<int> children;
function<void(int, int)> dfs = [&](int src1, int src2) {
l[src1][src2] = children.size();
children.emplace_back(src1);
reverse(ALL(graph[src1][src2]));
for (auto [dst1, dst2] : graph[src1][src2]) dfs(dst1, dst2);
r[src1][src2] = children.size();
};
REP(i, n) dfs(i, 0);
// REP(i, n + m) cout << children[i] << " \n"[i + 1 == n + m];
// REP(i, n) REP(j, graph[i].size()) cout << i << ' ' << j << " : " << l[i][j] << ' ' << r[i][j] << '\n';
vector<int> latest(n);
REP(i, n) latest[i] = l[i][graph[i].size() - 1];
sort(ALL(latest));
// REP(i, n) cout << latest[i] << " \n"[i + 1 == n];
function<bool(int, int, int&)> solve = [&](int left, int right, int &k) {
// cout << left << ' ' << right << '\n';
int cnt = upper_bound(ALL(latest), right) - lower_bound(ALL(latest), left);
if (cnt < k) {
k -= cnt;
return false;
}
int idx = lower_bound(ALL(latest), left) - latest.begin();
cout << children[latest[idx + k - 1]] + 1 << '\n';
return true;
};
REP(i, m) {
int prev = l[a[i]][dst[i] - 1];
assert(solve(0, prev, k[i])
|| solve(l[a[i]][dst[i]], r[a[i]][dst[i]] - 1, k[i])
|| solve(prev + 1, l[a[i]][dst[i]] - 1, k[i])
|| solve(r[a[i]][dst[i]], n + m - 1, k[i]));
}
return 0;
}
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