結果

問題 No.1029 JJOOII 3
ユーザー ThistleThistle
提出日時 2020-04-16 15:30:44
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 94 ms / 2,000 ms
コード長 4,713 bytes
コンパイル時間 1,827 ms
コンパイル使用メモリ 135,268 KB
実行使用メモリ 8,348 KB
最終ジャッジ日時 2024-04-27 03:08:27
合計ジャッジ時間 4,075 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
6,816 KB
testcase_01 AC 2 ms
6,944 KB
testcase_02 AC 3 ms
6,944 KB
testcase_03 AC 6 ms
6,944 KB
testcase_04 AC 8 ms
6,940 KB
testcase_05 AC 41 ms
6,944 KB
testcase_06 AC 36 ms
6,944 KB
testcase_07 AC 36 ms
6,944 KB
testcase_08 AC 42 ms
8,296 KB
testcase_09 AC 35 ms
6,984 KB
testcase_10 AC 38 ms
7,020 KB
testcase_11 AC 44 ms
6,944 KB
testcase_12 AC 31 ms
6,944 KB
testcase_13 AC 41 ms
6,944 KB
testcase_14 AC 43 ms
6,944 KB
testcase_15 AC 17 ms
6,944 KB
testcase_16 AC 20 ms
7,020 KB
testcase_17 AC 22 ms
8,348 KB
testcase_18 AC 37 ms
6,940 KB
testcase_19 AC 2 ms
6,940 KB
testcase_20 AC 15 ms
6,944 KB
testcase_21 AC 14 ms
6,944 KB
testcase_22 AC 16 ms
6,940 KB
testcase_23 AC 13 ms
6,948 KB
testcase_24 AC 15 ms
6,944 KB
testcase_25 AC 16 ms
7,760 KB
testcase_26 AC 23 ms
7,828 KB
testcase_27 AC 28 ms
6,940 KB
testcase_28 AC 24 ms
7,712 KB
testcase_29 AC 21 ms
6,940 KB
testcase_30 AC 27 ms
6,940 KB
testcase_31 AC 23 ms
6,944 KB
testcase_32 AC 94 ms
6,952 KB
testcase_33 AC 93 ms
6,944 KB
testcase_34 AC 92 ms
6,988 KB
testcase_35 AC 94 ms
8,008 KB
testcase_36 AC 93 ms
6,940 KB
testcase_37 AC 3 ms
6,940 KB
testcase_38 AC 2 ms
7,636 KB
testcase_39 AC 2 ms
6,940 KB
testcase_40 AC 2 ms
6,940 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#pragma GCC target ("avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define _USE_MATH_DEFINES
#include<iostream>
#include<string>
#include<queue>
#include<cmath>
#include<map>
#include<set>
#include<list>
#include<iomanip>
#include<vector>
#include<random>
#include<functional>
#include<algorithm>
#include<stack>
#include<cstdio>
#include<cstring>
#include<bitset>
#include<unordered_map>
#include<climits>
#include<fstream>
#include<complex>
#include<time.h>
#include<cassert>
#include<functional>
#include<numeric>
#include<tuple>
using namespace std;
using ll = long long;
using ld = long double;
#define int long long
#define all(a) (a).begin(),(a).end()
#define fs first
#define sc second
#define xx first
#define yy second.first
#define zz second.second
#define H pair<int, int>
#define P pair<int, pair<int, int>>
#define Q(i,j,k) mkp(i,mkp(j,k))
#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)
#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)
#define mkp make_pair
#define vec vector
#define pb emplace_back
#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())
#define getidx(b,i) lower_bound(all(b),(i))-b.begin()
#define ssp(i,n) (i==(int)(n)-1?"\n":" ")
#define ctoi(c) (int)(c-'0')
#define itoc(c) (char)(c+'0')
#define pp(x,y) pb(H{x,y})
#define ppp(x,y,z) pb(Q(x,y,z))
#define cyes printf("Yes\n")
#define cno printf("No\n")
#define cdf(n) for(int qq123_=(n);qq123_;qq123_--)
//#define endl "\n"
constexpr int mod = 1e9 + 7;
constexpr int Mod = 998244353;
constexpr int MXN = 500000 + 100;
constexpr ld EPS = 1e-10;
constexpr ll inf = 3 * 1e18;
constexpr int Inf = 15 * 1e8;
const vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };
template<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
ll read() { ll u, k = scanf("%lld", &u); return u; }
string reads() { string s; cin >> s; return s; }
H readh(bool g = 0) { H u; int k = scanf("%lld %lld", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }
void printh(H t) { printf("%lld %lld\n", t.fs, t.sc); }
bool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }
ll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }
ll lcm(ll i, ll j) { return i / gcd(i, j) * j; }
ll mod_pow(ll x, ll n, ll p = mod) {
    ll res = 1; x %= p;
    while (n > 0) {
        if (n & 1) res = res * x % p;
        x = x * x % p;
        n >>= 1;
    }
    return res;
}//x^n%p
ll bitcount(ll x) {
    int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;
    return sum;
}
/*constexpr int fn_ = 1000005;
ll fact_[fn_], comp_[fn_];
ll comb(ll x, ll y, ll Mod = mod) {
    if (!fact_[0]) {
        fact_[0] = 1; comp_[0] = 1;
        for (int i = 1; i < fn_; i++)
            fact_[i] = fact_[i - 1] * i % Mod;
        comp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);
        for (int i = fn_ - 2; i > 0; i--)
            comp_[i] = comp_[i + 1] * (i + 1) % Mod;
    }
    if (x < y) return 0;
    return fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;
}*/
//--------------------------------------------------------------
int n, k;
string s[100];
int cnt[100][100][3];
int c[100];
int dp[3][200000];
signed main() {
    cin >> n >> k;
    string joi = "JOI";
    rep(i, n) {
        cin >> s[i] >> c[i];
        rep(j, s[i].size()) rep(z, 3) cnt[i][j][z] = (j > 0 ? cnt[i][j - 1][z] : 0) + (s[i][j] == joi[z]);
    }
    rep(i, 3) {
        rng(j, 1, k + 1) dp[i][j] = inf;
        rep(j, n)rng(z, 1, k + 1) {
            chmin(dp[i][z], dp[i][max(0ll, z - cnt[j][s[j].size() - 1][i])] + c[j]);
        }
    }
    rep(i, 3)if (dp[i][k] == inf) {
        cout << -1 << endl;
        return 0;
    }
    int ans = inf;
    rep(i, n) rep(j, n) {
        rep(t, s[i].size() + 1) rep(r, s[j].size() + 1) {
            int sum = dp[0][max(0ll, k - (t > 0 ? cnt[i][t - 1][0] : 0))] +
                dp[1][max(0ll, k - (cnt[i][s[i].size() - 1][1] - (t > 0 ? cnt[i][t - 1][1] : 0)) - (r > 0 ? cnt[j][r - 1][1] : 0))] +
                dp[2][max(0ll, k - (cnt[j][s[j].size() - 1][2] - (r > 0 ? cnt[j][r - 1][2] : 0)))];
            sum += c[i] + c[j];
            chmin(ans, sum);
        }
    }
    rep(i, n) {
        rep(j, s[i].size())rng(z, j, s[i].size()) {
            //[j,z]をOに割り当てる
            if (cnt[i][z][1] - (j > 0 ? cnt[i][j - 1][1] : 0) >= k) {
                chmin(ans, c[i] + dp[0][max(0ll, k - (j > 0 ? cnt[i][j - 1][0] : 0))] + dp[2][k - (cnt[i][s[i].size() - 1][2] - cnt[i][z][2])]);
            }
        }
    }
    cout << ans << endl;
}
0