結果
| 問題 |
No.1028 闇討ち
|
| コンテスト | |
| ユーザー |
Jumbo_kpr
|
| 提出日時 | 2020-04-17 21:58:23 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 155 ms / 2,000 ms |
| コード長 | 4,153 bytes |
| コンパイル時間 | 1,327 ms |
| コンパイル使用メモリ | 119,472 KB |
| 実行使用メモリ | 20,736 KB |
| 最終ジャッジ日時 | 2024-10-03 12:51:44 |
| 合計ジャッジ時間 | 3,503 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 20 |
ソースコード
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("unroll-loops")
//#pragma warning(disable : 4996)
#include<iostream>
#include<string>
#include<algorithm>
#include<vector>
#include<queue>
#include<map>
#include<math.h>
#include<iomanip>
#include<set>
#include<numeric>
#include<cstring>
#include<cstdio>
#include<functional>
#include<bitset>
#include<limits.h>
#include<cassert>
#include<iterator>
#include<complex>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<time.h>
#include<random>
#include<array>
using namespace std;
#define REP(i, n) for(int i = 0;i < n;++i)
#define REPR(i, n) for(int i = n-1;i >= 0;--i)
#define FOR(i, m, n) for(int i = m;i < n;++i)
#define FORR(i, m, n) for(int i = m-1;i >= n;--i)
#define SORT(v, n) sort(v, v+n);
#define VSORT(v) sort(v.begin(), v.end());
#define REVERSE(v,n) reverse(v,v+n);
#define VREVERSE(v) reverse(v.begin(), v.end())
#define ll long long
#define print(x) cout<<(x)<<'\n'
#define pe(x) cout<<(x)<<" "
#define DEBUG(x) cout<<#x<<": "<<x<<endl
#define lb(v,n) lower_bound(v.begin(), v.end(), (n))
#define ub(v,n) upper_bound(v.begin(), v.end(), (n))
#define int long long
//#define double long double
#define all(x) (x).begin(), (x).end()
#define print_space(v) REP(i,v.size())cout << v[i] << ((i == v.size() - 1) ? "\n" : " ")
template<typename T1, typename T2> inline void chmin(T1 & a, T2 b) { if (a > b) a = b; }
template<typename T1, typename T2> inline void chmax(T1& a, T2 b) { if (a < b) a = b; }
typedef pair<int, int>pii;
typedef array<int, 3> arr3;
std::random_device rd;
std::mt19937 mt(rd());
constexpr ll MOD = 1e9 + 7; constexpr int MAX = 2000020;
const double pi = acos(-1); constexpr double EPS = 1e-8;
constexpr ll INF = 1e18;
void yes(bool c) { if (c)print("Yes"); else print("No"); };
//const int mod = 1000000007;
const int mod = 998244353;
struct mint {
ll x; // typedef long long ll;
mint(ll x = 0) :x((x%mod + mod) % mod) {}
mint operator-() const { return mint(-x); }
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod - a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; }
mint operator+(const mint a) const { return mint(*this) += a; }
mint operator-(const mint a) const { return mint(*this) -= a; }
mint operator*(const mint a) const { return mint(*this) *= a; }
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t >> 1);
a *= a;
if (t & 1) a *= *this;
return a;
}
// for prime mod
mint inv() const { return pow(mod - 2); }
mint& operator/=(const mint a) { return *this *= a.inv(); }
mint operator/(const mint a) const { return mint(*this) /= a; }
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }
int A[1010][1010];
void solve() {
int N; cin >> N;
//vector<int>ans(N);
vector<vector<int>>X(N),Y(N);
REP(i, N) {
REP(j, N) {
int a; cin >> a;
a--;
X[a].push_back(i);
Y[a].push_back(j);
}
}
ll ans = 0;
REP(i, N) {
int l = 0, r = N;
int ret = 1e9;
while (r - l > 10) {
int m1 = (l * 2 + r) / 3, m2 = (l + r * 2)/3;
int res1 = 0, res2 = 0;
REP(j, N) {
res1 += Y[i][j];
int x1 = m1 + Y[i][j],x2= m1 - Y[i][j];
if (X[i][j] > x1)res1 += X[i][j] - x1;
else if (X[i][j] < x2)res1 += x2 - X[i][j];
}
REP(j, N) {
res2 += Y[i][j];
int x1 = m2 + Y[i][j], x2 = m2 - Y[i][j];
if (X[i][j] > x1)res2+= X[i][j] - x1;
else if (X[i][j] < x2)res2 += x2 - X[i][j];
}
if (res1 < res2)r = m2;
else l = m1;
ret = min({ ret,res1,res2 });
}
FOR(m, l, r + 1) {
int res1 = 0;
REP(j, N) {
res1 += Y[i][j];
int x1 = m + Y[i][j], x2 = m - Y[i][j];
if (X[i][j] > x1)res1 += X[i][j] - x1;
else if (X[i][j] < x2)res1 += x2 - X[i][j];
}
ret = min(ret, res1);
}
ans += ret;
}
print(ans);
}
signed main() {
cin.tie(0);
ios::sync_with_stdio(false);
//int q; cin >> q;
//while (q--)
solve();
}
Jumbo_kpr