結果
問題 | No.1029 JJOOII 3 |
ユーザー |
![]() |
提出日時 | 2020-04-17 22:05:52 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
TLE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,032 bytes |
コンパイル時間 | 12,766 ms |
コンパイル使用メモリ | 289,452 KB |
最終ジャッジ日時 | 2025-01-09 20:05:53 |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 33 TLE * 5 |
コンパイルメッセージ
main.cpp: In function 'int main()': main.cpp:63:16: warning: 'status' may be used uninitialized [-Wmaybe-uninitialized] 63 | status = status + 1; | ~~~~~~~^~~~~~~~~~~~ main.cpp:50:9: note: 'status' was declared here 50 | int status, cnt = i % k; | ^~~~~~
ソースコード
#pragma GCC optimize("Ofast", "unroll-loops", "omit-frame-pointer", "inline")#pragma GCC option("arch=native", "tune=native", "no-zero-upper")#pragma GCC target("avx2")#define _USE_MATH_DEFINES#include <bits/stdc++.h>using namespace std;#define FOR(i,m,n) for(int i=(m);i<(n);++i)#define REP(i,n) FOR(i,0,n)#define ALL(v) (v).begin(),(v).end()using ll = long long;const int INF = 0x3f3f3f3f;const ll LINF = 0x3f3f3f3f3f3f3f3fLL;const double EPS = 1e-8;const int MOD = 1000000007;// const int MOD = 998244353;const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};const int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};template <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }template <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }struct IOSetup {IOSetup() {cin.tie(nullptr);ios_base::sync_with_stdio(false);cout << fixed << setprecision(20);}} iosetup;int main() {int n, k; cin >> n >> k;vector<string> s(n);vector<int> c(n);REP(i, n) cin >> s[i] >> c[i];{bool j = false, o = false, I = false;REP(i, n) for (char c : s[i]) {j |= c == 'J';o |= c == 'O';I |= c == 'I';}// cout << j << ' ' << o << ' ' << i << '\n';if (!j || !o || !I) {cout << "-1\n";return 0;}}vector<ll> dp(k * 3 + 1, LINF);dp[0] = 0;REP(i, k * 3) REP(j, n) {int status, cnt = i % k;if (i < k) status = 0;if (k <= i && i < k * 2) status = 1;if (k * 2 <= i) status = 2;for (char c : s[j]) {if (status == 0) {if (c == 'J') ++cnt;} else if (status == 1) {if (c == 'O') ++cnt;} else if (status == 2) {if (c == 'I') ++cnt;}if (cnt == k && status < 2) {status = status + 1;cnt = 0;}}chmin(cnt, k);chmin(dp[status * k + cnt], dp[i] + c[j]);}cout << dp[k * 3] << '\n';return 0;}