結果

問題 No.898 tri-βutree
ユーザー 👑 obakyanobakyan
提出日時 2020-04-18 23:53:35
言語 Lua
(LuaJit 2.1.1696795921)
結果
AC  
実行時間 1,098 ms / 4,000 ms
コード長 3,380 bytes
コンパイル時間 262 ms
コンパイル使用メモリ 7,196 KB
実行使用メモリ 35,712 KB
最終ジャッジ日時 2024-04-26 09:22:41
合計ジャッジ時間 16,882 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 411 ms
35,328 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 4 ms
5,376 KB
testcase_03 AC 4 ms
5,376 KB
testcase_04 AC 3 ms
5,376 KB
testcase_05 AC 4 ms
5,376 KB
testcase_06 AC 3 ms
5,376 KB
testcase_07 AC 827 ms
35,584 KB
testcase_08 AC 869 ms
35,712 KB
testcase_09 AC 854 ms
35,584 KB
testcase_10 AC 836 ms
35,584 KB
testcase_11 AC 868 ms
35,712 KB
testcase_12 AC 865 ms
35,584 KB
testcase_13 AC 854 ms
35,712 KB
testcase_14 AC 863 ms
35,584 KB
testcase_15 AC 897 ms
35,712 KB
testcase_16 AC 843 ms
35,712 KB
testcase_17 AC 1,098 ms
35,712 KB
testcase_18 AC 1,093 ms
35,584 KB
testcase_19 AC 846 ms
35,584 KB
testcase_20 AC 878 ms
35,584 KB
testcase_21 AC 870 ms
35,584 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

local mfl, mce = math.floor, math.ceil
local mmi, mma = math.min, math.max
local bls, brs = bit.lshift, bit.rshift
local SegTree = {}
SegTree.updateAll = function(self)
  for i = self.stagenum - 1, 1, -1 do
    local cnt = bls(1, i - 1)
    for j = 1, cnt do
      self.stage[i][j] = self.func(self.stage[i + 1][j * 2 - 1], self.stage[i + 1][j * 2])
    end
  end
end
SegTree.create = function(self, n, func, emptyvalue)
  self.func, self.emptyvalue = func, emptyvalue
  local stagenum, mul = 1, 1
  self.stage = {{}}
  while mul < n do
    mul, stagenum = mul * 2, stagenum + 1
    self.stage[stagenum] = {}
  end
  self.stagenum = stagenum
  for i = 1, mul do self.stage[stagenum][i] = emptyvalue end
  self:updateAll()
end
SegTree.getRange = function(self, left, right)
  if left == right then return self.stage[self.stagenum][left] end
  local stagenum = self.stagenum
  local ret = self.emptyvalue
  while left <= right do
    local stage, sz = 1, bls(1, stagenum - 1)
    local len = right - left + 1
    while (left - 1) % sz ~= 0 or len < sz do
      stage, sz = stage + 1, brs(sz, 1)
    end
    ret = self.func(ret, self.stage[stage][1 + brs(left - 1, stagenum - stage)])
    left = left + sz
  end
  return ret
end
SegTree.setValue = function(self, idx, value, silent)
  self.stage[self.stagenum][idx] = value
  if not silent then
    for i = self.stagenum - 1, 1, -1 do
      local dst = brs(idx + 1, 1)
      local rem = dst * 4 - 1 - idx
      self.stage[i][dst] = self.func(self.stage[i + 1][idx], self.stage[i + 1][rem])
      idx = dst
    end
  end
end
SegTree.new = function(n, func, emptyvalue)
  local obj = {}
  setmetatable(obj, {__index = SegTree})
  obj:create(n, func, emptyvalue)
  return obj
end

local n = io.read("*n")
local edge = {}
local edgecost = {}
local asked = {}
local cpos = {}
local len = {}
local cost = {}
local stpos = {}
for i = 1, n do
  edge[i] = {}
  edgecost[i] = {}
  asked[i] = false
  cpos[i] = 0
  len[i] = 0
  cost[i] = 0
  stpos[i] = 0
end
len[n + 1] = 1000000007
for i = 1, n - 1 do
  local x, y, c = io.read("*n", "*n", "*n")
  x, y = x + 1, y + 1
  table.insert(edge[x], y)
  table.insert(edge[y], x)
  table.insert(edgecost[x], c)
  table.insert(edgecost[y], c)
end
local st = SegTree.new(2 * n - 1, function(a, b) return len[a] < len[b] and a or b end, n + 1)

local tasks = {1}
local sti = 1
while 0 < #tasks do
  local src = tasks[#tasks]
  table.remove(tasks)
  asked[src] = true
  stpos[src] = sti
  st:setValue(sti, src, true)
  sti = sti + 1
  while cpos[src] < #edge[src] do
    cpos[src] = cpos[src] + 1
    local dst = edge[src][cpos[src]]
    if not asked[dst] then
      len[dst] = len[src] + 1
      cost[dst] = cost[src] + edgecost[src][cpos[src]]
      table.insert(tasks, src)
      table.insert(tasks, dst)
      break
    end
  end
end
st:updateAll()

local function solve(x, y, z)
  local xp, yp, zp = stpos[x], stpos[y], stpos[z]
  local xyroot = xp < yp and st:getRange(xp, yp) or st:getRange(yp, xp)
  local xzroot = xp < zp and st:getRange(xp, zp) or st:getRange(zp, xp)
  local yzroot = yp < zp and st:getRange(yp, zp) or st:getRange(zp, yp)
  local ret = cost[x] + cost[y] + cost[z]
  ret = ret - cost[xyroot] - cost[yzroot] - cost[xzroot]
  print(ret)
end

local q = io.read("*n")
for iq = 1, q do
  local x, y, z = io.read("*n", "*n", "*n")
  x, y, z = x + 1, y + 1, z + 1
  solve(x, y, z)
end
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