結果

問題 No.507 ゲーム大会(チーム決め)
ユーザー 👑 obakyanobakyan
提出日時 2020-04-19 19:12:44
言語 Lua
(LuaJit 2.1.1696795921)
結果
AC  
実行時間 2,282 ms / 3,000 ms
コード長 3,447 bytes
コンパイル時間 115 ms
コンパイル使用メモリ 6,820 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-10-06 02:22:47
合計ジャッジ時間 12,895 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
6,820 KB
testcase_01 AC 2 ms
6,820 KB
testcase_02 AC 2 ms
6,820 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 2 ms
6,820 KB
testcase_06 AC 2 ms
6,820 KB
testcase_07 AC 71 ms
6,820 KB
testcase_08 AC 248 ms
6,816 KB
testcase_09 AC 64 ms
6,820 KB
testcase_10 AC 889 ms
6,820 KB
testcase_11 AC 1,549 ms
6,820 KB
testcase_12 AC 92 ms
6,816 KB
testcase_13 AC 2,277 ms
6,816 KB
testcase_14 AC 2,282 ms
6,820 KB
testcase_15 AC 2,143 ms
6,820 KB
testcase_16 AC 2,034 ms
6,816 KB
testcase_17 AC 2 ms
6,816 KB
testcase_18 AC 2 ms
6,816 KB
testcase_19 AC 2 ms
6,820 KB
testcase_20 AC 2 ms
6,820 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

local mfl, mce = math.floor, math.ceil
local mmi, mma = math.min, math.max
local bls, brs = bit.lshift, bit.rshift
local function comp(a, b)
  return a < b
end

local function lower_bound(ary, x)
  local num = #ary
  if num == 0 then return 1 end
  if not comp(ary[1], x) then return 1 end
  if comp(ary[num], x) then return num + 1 end
  local min, max = 1, num
  while 1 < max - min do
    local mid = mfl((min + max) / 2)
    if comp(ary[mid], x) then
      min = mid
    else
      max = mid
    end
  end
  return max
end

local SegTree = {}
SegTree.clearAll = function(self)
  for i = self.stagenum, 1, -1 do
    local cnt = bls(1, i - 1)
    for j = 1, cnt do
      self.stage[i][j] = true
    end
  end
end
SegTree.create = function(self, n)
  local stagenum, mul = 1, 1
  self.stage = {{}}
  while mul < n do
    mul, stagenum = mul * 2, stagenum + 1
    self.stage[stagenum] = {}
  end
  self.stagenum = stagenum
  self:clearAll()
end
SegTree.setValue = function(self, idx)
  self.stage[self.stagenum][idx] = false
  for i = self.stagenum - 1, 1, -1 do
    local dst = brs(idx + 1, 1)
    local rem = dst * 4 - 1 - idx
    self.stage[i][dst] = self.stage[i + 1][idx] or self.stage[i + 1][rem]
    idx = dst
  end
end

SegTree.right_bound = function(self, left, right)
  local retpos = left - 1
  local stage, l, r = 1, left, right
  local stagenum = self.stagenum
  while true do
    local sz = bls(1, stagenum - stage)
    while (l - 1) % sz ~= 0 or r + 1 - l < sz do
      stage = stage + 1
      sz = bls(1, stagenum - stage)
    end
    if not self.stage[stage][mce(l / sz)] then
      retpos = l + sz - 1
      if retpos == right then break end
      if l + sz <= r then stage, l, r = 1, l + sz, r
      else break end
    else
      if sz ~= 1 then stage, l, r = stage + 1, l, l + sz - 2
      else break end
    end
  end
  return retpos + 1
end

SegTree.left_bound = function(self, left, right)
  local retpos = right + 1
  local stage, l, r = 1, left, right
  local stagenum = self.stagenum
  while true do
    local sz = bls(1, stagenum - stage)
    while r % sz ~= 0 or r + 1 - l < sz do
      stage = stage + 1
      sz = bls(1, stagenum - stage)
    end
    if not self.stage[stage][mfl(r / sz)] then
      retpos = r - sz + 1
      if l + sz <= r then stage, l, r = 1, l, r - sz
      else break end
    else
      if sz ~= 1 then stage, l, r = stage + 1, r - sz + 2, r
      else break end
    end
  end
  return retpos - 1
end
SegTree.new = function(n)
  local obj = {}
  setmetatable(obj, {__index = SegTree})
  obj:create(n)
  return obj
end

local n, m = io.read("*n", "*n")
local a = io.read("*n")
local t = {}
n = n - 1
for i = 1, n do
  t[i] = io.read("*n")
end
table.sort(t)
local st = SegTree
st:create(n)

local function judge(x)
  local tgt = a + t[x] + 1
  st:clearAll()
  st:setValue(x)
  local cnt = 0
  for i = 1, m do
    local rightpos = st:left_bound(1, n)
    if rightpos <= 1 then return true end
    st:setValue(rightpos)
    local lbpos = lower_bound(t, tgt - t[rightpos])
    if n < lbpos then return true end
    local leftpos = st:right_bound(lbpos, n)
    if n < leftpos then return true end
    st:setValue(leftpos)
  end
  return false
end
if not judge(n) then
  print(-1)
elseif judge(1) then
  print(t[1])
else
  local min, max = 1, n
  while 1 < max - min do
    local mid = brs(min + max, 1)
    if judge(mid) then
      max = mid
    else
      min = mid
    end
  end
  print(t[max])
end
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