結果
問題 | No.1036 Make One With GCD 2 |
ユーザー | kimiyuki |
提出日時 | 2020-04-24 22:14:34 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,003 ms / 2,000 ms |
コード長 | 3,279 bytes |
コンパイル時間 | 837 ms |
コンパイル使用メモリ | 63,920 KB |
最終ジャッジ日時 | 2025-01-09 23:57:42 |
ジャッジサーバーID (参考情報) |
judge3 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 41 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:25:17: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 25 | sparse_table() = default; | ~~~~~^~~~~~~~~~ main.cpp:28:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 28 | * @note $O(N \log N)$ time | ~~~~~^~~~~~~~~~~~~~~
ソースコード
#line 1 "main.cpp" #define PROBLEM "https://yukicoder.me/problems/no/1036" #include <cstdio> #include <vector> #line 2 "/home/user/GitHub/competitive-programming-library/utils/macros.hpp" #define REP(i, n) for (int i = 0; (i) < (int)(n); ++ (i)) #define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++ (i)) #define REP_R(i, n) for (int i = (int)(n) - 1; (i) >= 0; -- (i)) #define REP3R(i, m, n) for (int i = (int)(n) - 1; (i) >= (int)(m); -- (i)) #define ALL(x) std::begin(x), std::end(x) #line 2 "/home/user/GitHub/competitive-programming-library/data_structure/sparse_table.hpp" #include <cassert> #line 5 "/home/user/GitHub/competitive-programming-library/data_structure/sparse_table.hpp" /** * @brief Sparse Table (idempotent monoid) * @note the unit is required just for convenience * @note $O(N \log N)$ space */ template <class IdempotentMonoid> struct sparse_table { typedef typename IdempotentMonoid::value_type value_type; std::vector<std::vector<value_type> > table; IdempotentMonoid mon; sparse_table() = default; /** * @note $O(N \log N)$ time */ template <class InputIterator> sparse_table(InputIterator first, InputIterator last, const IdempotentMonoid & mon_ = IdempotentMonoid()) : mon(mon_) { table.emplace_back(first, last); int n = table[0].size(); int log_n = 32 - __builtin_clz(n); table.resize(log_n, std::vector<value_type>(n)); REP (k, log_n - 1) { REP (i, n) { table[k + 1][i] = i + (1ll << k) < n ? mon.mult(table[k][i], table[k][i + (1ll << k)]) : table[k][i]; } } } /** * @note $O(1)$ */ value_type range_get(int l, int r) const { if (l == r) return mon.unit(); // if there is no unit, remove this line assert (0 <= l and l < r and r <= (int)table[0].size()); int k = 31 - __builtin_clz(r - l); // log2 return mon.mult(table[k][l], table[k][r - (1ll << k)]); } }; #line 2 "/home/user/GitHub/competitive-programming-library/number/gcd.hpp" #include <algorithm> /** * @note if arguments are negative, the result may be negative */ template <typename T> T gcd(T a, T b) { while (a) { b %= a; std::swap(a, b); } return b; } template <typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; } #line 3 "/home/user/GitHub/competitive-programming-library/monoids/gcd.hpp" /** * @note a semilattice */ template <class Integer> struct gcd_monoid { typedef Integer value_type; Integer unit() const { return 0; } Integer mult(Integer a, Integer b) const { return gcd(a, b); } }; #line 7 "main.cpp" long long solve(int n, const std::vector<long long> & a) { sparse_table<gcd_monoid<long long> > table(ALL(a)); int r = 0; long long ans = 0; REP (l, n) { while (r < n and table.range_get(l, r) != 1) { ++ r; } if (r == n and table.range_get(l, r) != 1) { break; } ans += n - r + 1; } return ans; } int main() { int n; scanf("%d", &n); std::vector<long long> a(n); REP (i, n) { scanf("%lld", &a[i]); } printf("%lld\n", solve(n, a)); return 0; }