結果

問題 No.1036 Make One With GCD 2
ユーザー opt
提出日時 2020-04-25 00:28:26
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 620 ms / 2,000 ms
コード長 3,121 bytes
コンパイル時間 2,874 ms
コンパイル使用メモリ 204,300 KB
最終ジャッジ日時 2025-01-10 00:45:56
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 41
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define rep2(i, m, n) for(int i=int(m); i<int(n); ++i)
#define drep2(i, m, n) for(int i=int(m-1); i>=int(n); --i)
#define rep(i, n) rep2(i, 0, n)
#define drep(i, n) drep2(i, n, 0)
#define all(a) a.begin(), a.end()
using ll = long long;
using ld = long double;
using V = vector<int>;
using Vll = vector<ll>;
using Vld = vector<ld>;
using Vbo = vector<bool>;
using VV = vector<V>;
using VVll = vector<Vll>;
using VVld = vector<Vld>;
using VVbo = vector<Vbo>;
using P = pair<int, int>;
using Pll = pair<ll, ll>;
using Pld = pair<ld, ld>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
template<typename T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; }
template<typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; }
template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << "(" << p.first << ", " << p.second << ")"; return 
    os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v) { for (auto &e : v) is >> e; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v) { for (auto &e : v) os << e << " "; return os; }
template<typename T> inline int count_between(vector<T> &a, T l, T r) { return lower_bound(all(a), r) - lower_bound(all(a), l); } // [l, r)
inline int Log2(ll x) { int k; for (k = 0; x > 0; ++k) x >>= 1; return k; } // number of binary digits
const int INF  = 1<<30;
const ll INFll = 1ll<<62;
const ld EPS   = 1e-10;
const int MOD  = int(1e9)+7;
template<typename T>
struct SegmentTree {
  int m, n; // m: size of original vector, n: size of segment tree
  vector<T> d;
  T idt = 0;
  T op(T &a, T &b) {
    // return a + b;
    return gcd(a, b);
  }
  SegmentTree(vector<T> v) : m(v.size()) {
    n = 1; while(n < m) n <<= 1;
    d.assign(2*n-1, 0);
    rep(i, m) d[i+n-1] = v[i];
    drep(i, n-1) d[i] = op(d[i*2+1], d[i*2+2]);
  }
 
  void add(int k, T val) {
    k += n-1, d[k] += val;
    while (k) k = (k-1)/2, d[k] = op(d[2*k+1], d[2*k+2]);
  } 
  void set(int k, T val) {
    k += n-1, d[k] = val;
    while (k) k = (k-1)/2, d[k] = op(d[2*k+1], d[2*k+2]);
  }
 
  T op_range(int a, int b, int k=0, int l=0, int r=-1) {
    if (r < 0) r = n;
    if (b <= l || r <= a) return idt;
    if (a <= l && r <= b) return d[k];
    T vl = op_range(a, b, 2*k+1, l, (l+r)/2);
    T vr = op_range(a, b, 2*k+2, (l+r)/2, r);
    return op(vl, vr);
  }
 
  T get(int a) { return d[n-1+a]; }
 
  vector<T> get_all() {
    vector<T> res(m);
    copy(d.begin()+n-1, d.begin()+n+m-1, res.begin());
    return res;
  }
};
int main() {
  ll n; cin >> n;
  Vll a(n); cin >> a;
  ll ans = 0;
  SegmentTree<ll> st(a);
  int j = 0;
  rep(i, n) {
    ll y = st.op_range(i, j+1);
    while (j < n && st.op_range(i, j+1) > 1) ++j;
    ans += n-j;
    if (i == j) ++j;
  }
  cout << ans << endl;
  return 0;
}
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