結果
| 問題 |
No.405 ローマ数字の腕時計
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-04-25 22:16:28 |
| 言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
| 結果 |
AC
|
| 実行時間 | 31 ms / 2,000 ms |
| コード長 | 262 bytes |
| コンパイル時間 | 76 ms |
| コンパイル使用メモリ | 12,672 KB |
| 実行使用メモリ | 10,880 KB |
| 最終ジャッジ日時 | 2024-07-06 19:28:03 |
| 合計ジャッジ時間 | 1,622 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 27 |
ソースコード
l = ["I","II","III","IIII","V","VI","VII","VIII","IX","X","XI","XII","I","II","III","IIII","V","VI","VII","VIII","IX","X","XI","XII","I","II","III","IIII","V","VI","VII","VIII","IX","X","XI","XII"] a,b = input().split() b = int(b) print(l[(l.index(a) + b) % 12])