結果
問題 | No.1045 直方体大学 |
ユーザー |
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提出日時 | 2020-05-01 22:33:25 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 382 ms / 2,000 ms |
コード長 | 1,929 bytes |
コンパイル時間 | 3,028 ms |
コンパイル使用メモリ | 205,052 KB |
最終ジャッジ日時 | 2025-01-10 05:11:35 |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 17 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:33:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 33 | scanf("%d", &n); | ~~~~~^~~~~~~~~~ main.cpp:36:24: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 36 | rep(j, 3) scanf("%d", &a[i][j]); | ~~~~~^~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>#define For(i, a, b) for(int (i)=(int)(a); (i)<(int)(b); ++(i))#define rFor(i, a, b) for(int (i)=(int)(a)-1; (i)>=(int)(b); --(i))#define rep(i, n) For((i), 0, (n))#define rrep(i, n) rFor((i), (n), 0)#define fi first#define se secondusing namespace std;typedef long long lint;typedef unsigned long long ulint;typedef pair<int, int> pii;typedef pair<lint, lint> pll;template<class T> bool chmax(T &a, const T &b){if(a<b){a=b; return true;} return false;}template<class T> bool chmin(T &a, const T &b){if(a>b){a=b; return true;} return false;}template<class T> T div_floor(T a, T b){if(b < 0) a *= -1, b *= -1;return a>=0 ? a/b : (a+1)/b-1;}template<class T> T div_ceil(T a, T b){if(b < 0) a *= -1, b *= -1;return a>0 ? (a-1)/b+1 : a/b;}constexpr lint mod = 1e9+7;constexpr lint INF = mod * mod;constexpr int MAX = 200010;int dp[1<<16][100];vector<pii> z;int main(){int n;scanf("%d", &n);int a[n][3];rep(i, n){rep(j, 3) scanf("%d", &a[i][j]);int id[3] = {0, 1, 2};do{z.emplace_back(a[i][id[0]], a[i][id[1]]);}while(next_permutation(id, id+3));}z.emplace_back(mod, mod);sort(z.begin(), z.end());int m = z.size();z.erase(unique(z.begin(), z.end()), z.end());rep(S, 1<<n)rep(t, m) dp[S][t] = -1;dp[0][m-1] = 0;rep(S, 1<<n)rep(t, m)if(dp[S][t] >= 0){rep(i, n)if(!(S>>i & 1)){int id[3] = {0, 1, 2};do{int p = lower_bound(z.begin(), z.end(), make_pair(a[i][id[0]], a[i][id[1]])) - z.begin();if(z[t].fi >= a[i][id[0]] && z[t].se >= a[i][id[1]]){chmax(dp[S | (1<<i)][p], dp[S][t] + a[i][id[2]]);}}while(next_permutation(id, id+3));}}int ans = 0;rep(S, 1<<n)rep(t, m) chmax(ans, dp[S][t]);printf("%d\n", ans);}