結果

問題 No.1044 正直者大学
ユーザー yukinon0808
提出日時 2020-05-01 23:14:56
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 29 ms / 2,000 ms
コード長 5,816 bytes
コンパイル時間 2,166 ms
コンパイル使用メモリ 172,592 KB
実行使用メモリ 5,632 KB
最終ジャッジ日時 2024-12-25 14:19:41
合計ジャッジ時間 3,470 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define SZ(x) (int)(x.size())
#define REP(i, n) for(int i=0;i<(n);++i)
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define RREP(i, n) for(int i=(int)(n)-1;i>=0;--i)
#define RFOR(i, a, b) for(int i=(int)(b)-1;i>=(a);--i)
#define ALL(a) a.begin(),a.end()
#define DUMP(x) cerr<<#x<<" = "<<(x)<<endl
#define DEBUG(x) cerr<<#x<<" = "<<(x)<<" (L"<<__LINE__<<")"<< endl;
using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using P = pair<int, int>;
const double EPS = 1e-8;
const ll MOD = 1000000007;
const int INF = INT_MAX / 2;
const ll LINF = LLONG_MAX / 2;
template <typename T1, typename T2>
bool chmax(T1 &a, const T2 &b) {
if (a < b) { a = b; return true; }
return false;
}
template <typename T1, typename T2>
bool chmin(T1 &a, const T2 &b) {
if (a > b) { a = b; return true; }
return false;
}
template<typename T1, typename T2>
ostream &operator<<(ostream &os, const map<T1, T2> &mp);
template<typename T>
ostream &operator<<(ostream &os, const vector<T> &v);
template<typename T1, typename T2>
ostream &operator<<(ostream &os, const pair<T1, T2> &p) {
os << "(" << p.first << ":" << p.second << ")";
return os;
}
template<typename T1, typename T2>
ostream &operator<<(ostream &os, const map<T1, T2> &mp) {
os << "{";
int a = 0;
for (auto &tp : mp) {
if (a) os << ", "; a = 1;
os << tp;
}
return os << "}";
}
template<typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
os << "[";
REP(i, SZ(v)) {
if (i) os << ", ";
os << v[i];
}
return os << "]";
}
template<int64_t mod>
struct modint {
using LL = int64_t;
LL val;
modint(LL val=0) : val(((val % mod) + mod) % mod) {}
const modint operator+() const { return *this; }
const modint operator-() const { return (-val + mod) % mod; }
const modint inv() const { return pow(mod-2); }
modint& operator+=(const modint& rhs) {
(val += rhs.val) %= mod;
return *this;
}
modint& operator-=(const modint& rhs) {
return *this += -rhs;
}
modint& operator*=(const modint& rhs) {
(val *= rhs.val) %= mod;
return *this;
}
modint& operator/=(const modint& rhs) {
return *this *= rhs.inv();
}
const modint operator+(const modint& rhs) const {
return modint(*this) += rhs;
}
const modint operator-(const modint& rhs) const {
return modint(*this) -= rhs;
}
const modint operator*(const modint& rhs) const {
return modint(*this) *= rhs;
}
const modint operator/(const modint& rhs) const {
return modint(*this) /= rhs;
}
const modint pow(LL n) const {
modint ret = 1, tmp = val;
while (n) {
if (n & 1) ret *= tmp;
tmp *= tmp; n >>= 1;
}
return ret;
}
bool operator==(const modint& rhs) const { return val == rhs.val; }
bool operator!=(const modint& rhs) const { return !(*this == rhs); }
friend const modint operator+(const LL& lhs, const modint& rhs) {
return modint(lhs) + rhs;
}
friend const modint operator-(const LL& lhs, const modint& rhs) {
return modint(lhs) - rhs;
}
friend const modint operator*(const LL& lhs, const modint& rhs) {
return modint(lhs) * rhs;
}
friend const modint operator/(const LL& lhs, const modint& rhs) {
return modint(lhs) / rhs;
}
friend bool operator==(const LL& lhs, const modint& rhs) {
return modint(lhs) == rhs;
}
friend bool operator!=(const LL& lhs, const modint& rhs) {
return modint(lhs) != rhs;
}
friend ostream& operator<<(ostream& os, const modint& a) {
return os << a.val;
}
friend istream& operator>>(istream& is, modint& a) {
LL tmp; is >> tmp;
a = tmp;
return is;
}
};
template<typename Field>
struct Combination {
vector<Field> _fact, _rfact, _inv;
Combination(int n) : _fact(n), _rfact(n), _inv(n) {
_fact[0] = _rfact[n-1] = 1;
for (int i = 1; i < n; ++i) _fact[i] = _fact[i-1] * i;
_rfact[n-1] /= _fact[n-1];
for (int i = n-1; i > 0; --i) _rfact[i-1] = _rfact[i] * i;
for (int i = 1; i < n; ++i) _inv[i] = _rfact[i] * _fact[i-1];
}
inline Field fact(int k) const { return _fact.at(k); }
inline Field rfact(int k) const { return _rfact.at(k); }
inline Field inv(int k) const { assert(k != 0); return _inv.at(k); }
Field P(int n, int r) const {
if (r < 0 or n < r) return 0;
return fact(n) * rfact(n-r);
}
Field C(int n, int r) const {
if (r < 0 or n < r) return 0;
return fact(n) * rfact(r) * rfact(n-r);
}
Field H (int n, int r) const {
return (n == 0 and r == 0) ? 1 : C(n+r-1, r);
}
};
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
cout << fixed << setprecision(10);
ll N, M, K; cin >> N >> M >> K;
using Int = modint<MOD>;
Combination<Int> comb(max(N, M)+1);
if (N == 1) {
if (K <= M-1) {
cout << comb.fact(M) << endl;
} else {
cout << 0 << endl;
}
return 0;
}
Int ans = 0;
for (int k = 1, updated = 1; updated; ++k) {
updated = 0;
if (K <= N + M - (2*k + 2)) {
updated = 1;
ans += comb.H(M-k, k) * comb.H(N-1-(k-1), (k-1));
}
if (K <= N + M - 2*k) {
updated = 1;
ans += comb.H(M-(k-1), (k-1)) * comb.H(N-1-k, k);
ans += 2 * comb.H(M-(k-1), (k-1)) * comb.H(N-1-(k-1), (k-1));
}
}
ans *= comb.fact(N-1) * comb.fact(M);
cout << ans << endl;
return 0;
}
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