結果
| 問題 |
No.217 魔方陣を作ろう
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2020-05-04 15:40:18 |
| 言語 | Lua (LuaJit 2.1.1734355927) |
| 結果 |
AC
|
| 実行時間 | 3 ms / 5,000 ms |
| コード長 | 3,090 bytes |
| コンパイル時間 | 65 ms |
| コンパイル使用メモリ | 6,944 KB |
| 実行使用メモリ | 6,944 KB |
| 最終ジャッジ日時 | 2024-06-24 10:21:06 |
| 合計ジャッジ時間 | 1,113 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 18 |
ソースコード
local n = io.read("*n")
local t = {}
for i = 1, n * n do t[i] = 0 end
if n % 2 == 1 then
local hn = math.floor(n / 2) + 1
local curh = 1
local curw = hn
for i = 1, n * n do
t[(curh - 1) * n + curw] = i
curh = curh - 1
if curh == 0 then curh = n end
curw = curw + 1
if curw == n + 1 then curw = 1 end
if 0 < t[(curh - 1) * n + curw] then
curh = curh + 2
if n < curh then curh = curh - n end
curw = curw - 1
if curw == 0 then curw = n end
end
end
elseif n % 4 == 0 then
local k1 = {0, 1, 0, 1, 2, 3, 2, 3}
local k2 = {0, 0, 1, 1, 2, 2, 3, 3}
for i = 1, n do
for j = 1, n do
local idx = (i - 1) * n + j
local ip4, jp4 = i % 4, j % 4
local f = false
for k = 1, 8 do
if ip4 == k1[k] and jp4 == k2[k] then
f = true break
end
end
if f then
t[idx] = idx
else
t[idx] = n * n + 1 - idx
end
end
end
else
local b = {}
local tn = math.floor(n / 2)
for i = 1, tn * tn do b[i] = 0 end
local hn = math.floor(tn / 2) + 1
local curh = 1
local curw = hn
for i = 1, tn * tn do
b[(curh - 1) * tn + curw] = i
curh = curh - 1
if curh == 0 then curh = tn end
curw = curw + 1
if curw == tn + 1 then curw = 1 end
if 0 < b[(curh - 1) * tn + curw] then
curh = curh + 2
if tn < curh then curh = curh - tn end
curw = curw - 1
if curw == 0 then curw = tn end
end
end
for i = 1, tn * tn do
b[i] = (b[i] - 1) * 4
end
for i = 1, tn do
for j = 1, tn do
if i < hn or (i == hn and j ~= hn) or (i == hn + 1 and j == hn) then
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 2
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 3
elseif i <= hn + 1 then
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 2
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 3
else
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 3
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 2
end
end
end
end
for i = 1, n do
for j = 1, n do
io.write(t[(i - 1) * n + j])
io.write(j == n and "\n" or " ")
end
end
local ast = math.floor(n * (n * n + 1) / 2)
for i = 1, n do
local c = 0
for j = 1, n do
c = c + t[(i - 1) * n + j]
end
assert(ast == c)
end
for j = 1, n do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + j]
end
assert(ast == c)
end
do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + i]
end
assert(ast == c)
end
do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + n + 1 - i]
end
assert(ast == c)
end