結果

問題 No.217 魔方陣を作ろう
ユーザー 👑 obakyan
提出日時 2020-05-04 15:40:18
言語 Lua
(LuaJit 2.1.1734355927)
結果
AC  
実行時間 3 ms / 5,000 ms
コード長 3,090 bytes
コンパイル時間 65 ms
コンパイル使用メモリ 6,944 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-24 10:21:06
合計ジャッジ時間 1,113 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

local n = io.read("*n")
local t = {}
for i = 1, n * n do t[i] = 0 end
if n % 2 == 1 then
local hn = math.floor(n / 2) + 1
local curh = 1
local curw = hn
for i = 1, n * n do
t[(curh - 1) * n + curw] = i
curh = curh - 1
if curh == 0 then curh = n end
curw = curw + 1
if curw == n + 1 then curw = 1 end
if 0 < t[(curh - 1) * n + curw] then
curh = curh + 2
if n < curh then curh = curh - n end
curw = curw - 1
if curw == 0 then curw = n end
end
end
elseif n % 4 == 0 then
local k1 = {0, 1, 0, 1, 2, 3, 2, 3}
local k2 = {0, 0, 1, 1, 2, 2, 3, 3}
for i = 1, n do
for j = 1, n do
local idx = (i - 1) * n + j
local ip4, jp4 = i % 4, j % 4
local f = false
for k = 1, 8 do
if ip4 == k1[k] and jp4 == k2[k] then
f = true break
end
end
if f then
t[idx] = idx
else
t[idx] = n * n + 1 - idx
end
end
end
else
local b = {}
local tn = math.floor(n / 2)
for i = 1, tn * tn do b[i] = 0 end
local hn = math.floor(tn / 2) + 1
local curh = 1
local curw = hn
for i = 1, tn * tn do
b[(curh - 1) * tn + curw] = i
curh = curh - 1
if curh == 0 then curh = tn end
curw = curw + 1
if curw == tn + 1 then curw = 1 end
if 0 < b[(curh - 1) * tn + curw] then
curh = curh + 2
if tn < curh then curh = curh - tn end
curw = curw - 1
if curw == 0 then curw = tn end
end
end
for i = 1, tn * tn do
b[i] = (b[i] - 1) * 4
end
for i = 1, tn do
for j = 1, tn do
if i < hn or (i == hn and j ~= hn) or (i == hn + 1 and j == hn) then
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 2
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 3
elseif i <= hn + 1 then
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 2
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 3
else
t[(i - 1) * 2 * n + j * 2 - 1] = b[(i - 1) * tn + j] + 1
t[(i - 1) * 2 * n + j * 2 - 0] = b[(i - 1) * tn + j] + 4
t[(i - 1) * 2 * n + n + j * 2 - 1] = b[(i - 1) * tn + j] + 3
t[(i - 1) * 2 * n + n + j * 2 - 0] = b[(i - 1) * tn + j] + 2
end
end
end
end
for i = 1, n do
for j = 1, n do
io.write(t[(i - 1) * n + j])
io.write(j == n and "\n" or " ")
end
end
local ast = math.floor(n * (n * n + 1) / 2)
for i = 1, n do
local c = 0
for j = 1, n do
c = c + t[(i - 1) * n + j]
end
assert(ast == c)
end
for j = 1, n do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + j]
end
assert(ast == c)
end
do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + i]
end
assert(ast == c)
end
do
local c = 0
for i = 1, n do
c = c + t[(i - 1) * n + n + 1 - i]
end
assert(ast == c)
end
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