結果
問題 | No.315 世界のなんとか3.5 |
ユーザー | maspy |
提出日時 | 2020-05-05 18:59:09 |
言語 | Python3 (3.12.2 + numpy 1.26.4 + scipy 1.12.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,537 bytes |
コンパイル時間 | 126 ms |
コンパイル使用メモリ | 12,800 KB |
実行使用メモリ | 15,816 KB |
最終ジャッジ日時 | 2024-06-27 00:39:41 |
合計ジャッジ時間 | 9,434 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 79 ms
10,880 KB |
testcase_01 | AC | 81 ms
10,880 KB |
testcase_02 | AC | 107 ms
10,752 KB |
testcase_03 | AC | 113 ms
10,752 KB |
testcase_04 | AC | 126 ms
10,880 KB |
testcase_05 | AC | 110 ms
10,624 KB |
testcase_06 | AC | 125 ms
10,752 KB |
testcase_07 | AC | 110 ms
10,880 KB |
testcase_08 | AC | 116 ms
10,624 KB |
testcase_09 | AC | 100 ms
10,752 KB |
testcase_10 | AC | 89 ms
10,624 KB |
testcase_11 | AC | 110 ms
10,752 KB |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | WA | - |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | AC | 374 ms
15,752 KB |
testcase_35 | AC | 444 ms
15,680 KB |
ソースコード
import sys read = sys.stdin.buffer.read readline = sys.stdin.buffer.readline readlines = sys.stdin.buffer.readlines MOD = 10**9 + 7 A, B, P = readline().split() P = int(P) A = [0, 0, 0, 0, 0] + [int(x) - ord('0') for x in A] B = [0, 0, 0, 0, 0] + [int(x) - ord('0') for x in B] def solve(A, P, include=True): total = 0 no_3 = 0 cnt = (0, 1, 2, 3, 3, 4, 5, 6, 7, 8) MOD3 = 3 * MOD for x in A[:-6]: total = (10 * total + x) % MOD3 no_3 = (9 * no_3 + cnt[x]) % MOD n = no_3 * 3 no_3 = [n, n, n] x = A[-6] full_use_3 = 3 in A[:-6] for d in range(x): if full_use_3 or d == 3: continue no_3[(total + d) % 3] += 1 total = (total * 10 + x) % MOD3 use_3 = (total - sum(no_3)) % MOD full_mod_3 = total % 3 full_use_3 = 3 in A[:-5] U = 0 for x in A[-5:]: U = 10 * U + x ret = 0 for x in range(10**5): if x % P == 0: continue if '3' in str(x): ret += total else: ret += use_3 + no_3[(-x) % 3] for x in range(U + include): if x % P == 0: continue if '3' in str(x) or full_use_3: ret += 1 else: ret += (full_mod_3 + x) % 3 == 0 return ret def solve_naive(A, P, include): N = A + include ret = 0 for x in range(N + 1): if x % P == 0: continue ret += '3' in str(x) or x % 3 == 0 return ret x = solve(B, P, True) - solve(A, P, False) print(x % MOD)