結果
問題 | No.526 フィボナッチ数列の第N項をMで割った余りを求める |
ユーザー | toyon |
提出日時 | 2020-05-05 19:28:20 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,573 bytes |
コンパイル時間 | 1,684 ms |
コンパイル使用メモリ | 177,880 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-06-27 01:22:40 |
合計ジャッジ時間 | 2,664 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | AC | 1 ms
6,944 KB |
testcase_02 | WA | - |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
ソースコード
#include <bits/stdc++.h> #define rep(i, n) for (int i = 0; i < (n); ++i) #define sz(x) int(x.size()) using namespace std; typedef long long ll; typedef pair<int, int> P; const ll INF = 1LL << 60; // matrix template<class T> struct Matrix { vector<vector<T> > val; Matrix(int n = 1, int m = 1, T v = 0) : val(n, vector<T>(m, v)) {} void init(int n, int m, T v = 0) {val.assign(n, vector<T>(m, v));} void resize(int n, int m) { val.resize(n); for (int i = 0; i < n; ++i) val[i].resize(m); } Matrix<T>& operator = (const Matrix<T> &A) { val = A.val; return *this; } size_t size() const {return val.size();} vector<T>& operator [] (int i) {return val[i];} const vector<T>& operator [] (int i) const {return val[i];} friend ostream& operator << (ostream& s, const Matrix<T>& M) { s << endl; for (int i = 0; i < (int)M.size(); ++i) s << M[i] << endl; return s; } }; template<class T> Matrix<T> operator * (const Matrix<T> &A, const Matrix<T> &B) { Matrix<T> R(A.size(), B[0].size()); for (int i = 0; i < A.size(); ++i) for (int j = 0; j < B[0].size(); ++j) for (int k = 0; k < B.size(); ++k) R[i][j] += A[i][k] * B[k][j]; return R; } template<class T> Matrix<T> pow(const Matrix<T> &A, long long n) { Matrix<T> R(A.size(), A.size()); auto B = A; for (int i = 0; i < A.size(); ++i) R[i][i] = 1; while (n > 0) { if (n & 1) R = R * B; B = B * B; n >>= 1; } return R; } template<class T> vector<T> operator * (const Matrix<T> &A, const vector<T> &B) { vector<T> v(A.size()); for (int i = 0; i < A.size(); ++i) for (int k = 0; k < B.size(); ++k) v[i] += A[i][k] * B[k]; return v; } template<class T> Matrix<T> operator + (const Matrix<T> &A, const Matrix<T> &B) { Matrix<T> R(A.size(), A[0].size()); for (int i = 0; i < A.size(); ++i) for (int j = 0; j < A[0].size(); ++j) R[i][j] = A[i][j] + B[i][j]; return R; } template<class T> Matrix<T> operator - (const Matrix<T> &A, const Matrix<T> &B) { Matrix<T> R(A.size(), A[0].size()); for (int i = 0; i < A.size(); ++i) for (int j = 0; j < A[0].size(); ++j) R[i][j] = A[i][j] - B[i][j]; return R; } // modint template<int MOD> struct Fp { long long val; constexpr Fp(long long v = 0) noexcept : val(v % MOD) { if (val < 0) val += MOD; } constexpr int getmod() { return MOD; } constexpr Fp operator - () const noexcept { return val ? MOD - val : 0; } constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; } constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; } constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; } constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; } constexpr Fp& operator += (const Fp& r) noexcept { val += r.val; if (val >= MOD) val -= MOD; return *this; } constexpr Fp& operator -= (const Fp& r) noexcept { val -= r.val; if (val < 0) val += MOD; return *this; } constexpr Fp& operator *= (const Fp& r) noexcept { val = val * r.val % MOD; return *this; } constexpr Fp& operator /= (const Fp& r) noexcept { long long a = r.val, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } val = val * u % MOD; if (val < 0) val += MOD; return *this; } constexpr bool operator == (const Fp& r) const noexcept { return this->val == r.val; } constexpr bool operator != (const Fp& r) const noexcept { return this->val != r.val; } friend constexpr ostream& operator << (ostream &os, const Fp<MOD>& x) noexcept { return os << x.val; } friend constexpr Fp<MOD> modpow(const Fp<MOD> &a, long long n) noexcept { if (n == 0) return 1; auto t = modpow(a, n / 2); t = t * t; if (n & 1) t = t * a; return t; } }; // const int MOD = 1000000007; ll N, M; int main() { cin >> N >> M; using mint = Fp<1000>; Matrix<mint> A(2, 2, 1); A[1][1] = 0; A = pow(A, N - 1); cout << A[1][0] << endl; // rep(i, 2) { // rep(j, 2) { // cout << A[i][j] << " "; // } // cout << endl; // } }