結果

問題 No.1050 Zero (Maximum)
ユーザー merom686
提出日時 2020-05-09 10:19:56
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 17 ms / 2,000 ms
コード長 3,387 bytes
コンパイル時間 1,148 ms
コンパイル使用メモリ 96,060 KB
最終ジャッジ日時 2025-01-10 09:43:11
ジャッジサーバーID
（参考情報） 		judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;
using ll = long long;
struct ModInt {
    ModInt() : i(0) {}
    ModInt(ll k) : i(k % Mod) {}
    ModInt operator+(ModInt m) const {
        ModInt r;
        r.i = i + m.i;
        if (r.i >= Mod) r.i -= Mod;
        return r;
    }
    ModInt operator-(ModInt m) const {
        ModInt r;
        r.i = i - m.i;
        if (r.i < 0) r.i += Mod;
        return r;
    }
    ModInt operator*(ModInt m) const {
        ModInt r;
        r.i = (ll)i * m.i % Mod;
        return r;
    }
    ModInt &operator+=(ModInt m) {
        i += m.i;
        if (i >= Mod) i -= Mod;
        return *this;
    }
    ModInt &operator-=(ModInt m) {
        i -= m.i;
        if (i < 0) i += Mod;
        return *this;
    }
    ModInt &operator*=(ModInt m) {
        i = (ll)i * m.i % Mod;
        return *this;
    }
    ModInt operator-() const {
        ModInt r;
        r.i = i == 0 ? 0 : Mod - i;
        return r;
    }
    ModInt pow(ll k) const {
        ModInt r = 1, t = *this;
        for (; k != 0; k /= 2) {
            if (k & 1) r *= t;
            t *= t;
        }
        return r;
    }
    ////Modが素数のときのみ
    //ModInt inv() const {
    //    return pow(Mod - 2);
    //}
    //ModInt operator/(ModInt m) const {
    //    return *this * m.inv();
    //}
    //ModInt &operator/=(ModInt m) {
    //    return *this *= m.inv();
    //}
    constexpr static inline int Mod = 1000000007;
    int i;
};
ostream &operator<<(ostream &os, const ModInt &m) {
    os << m.i;
    return os;
}
template <class T>
struct Matrix {
    Matrix(int n, int m) : a(n * m), n(n), m(m) {}
    static Matrix E(int n) {
        Matrix r(n, n);
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                r[i][j] = i == j;
            }
        }
        return r;
    }
    Matrix pow(ll k) const {
        Matrix r = E(n), t = *this;
        for (; k != 0; k /= 2) {
            if (k & 1) r = r * t;
            t = t * t;
        }
        return r;
    }
    Matrix operator*(const Matrix &x) const {
        if (m != x.n) throw;
        Matrix r(n, x.m);
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < x.m; j++) {
                T t = 0;
                for (int k = 0; k < m; k++) {
                    t += (*this)[i][k] * x[k][j];
                }
                r[i][j] = t;
            }
        }
        return r;
    }
    const T *operator[](int i) const {
        return &a[i * m];
    }
    T *operator[](int i) {
        return &a[i * m];
    }
    vector<T> a;
    int n, m;
};
using Mat = Matrix<ModInt>;
ostream &operator<<(ostream &os, const Mat &x) {
    for (int i = 0; i < x.n; i++) {
        for (int j = 0; j < x.m; j++) {
            cout << x[i][j] << " \n"[j == x.m - 1];
        }
    }
    return os;
}
int main() {
    int m, k;
    cin >> m >> k;
    Mat v(m, 1);
    for (int i = 0; i < m; i++) {
        v[i][0] = i == 0;
    }
    Mat x(m, m);
    for (int i = 0; i < m; i++) {
        int p[50] = {};
        for (int j = 0; j < m; j++) {
            p[i * j % m]++;
        }
        for (int j = 0; j < m; j++) {
            x[i][j] = 1 + p[j];
        }
    }
    v = x.pow(k) * v;
    cout << v[0][0] << endl;
    return 0;
}
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