結果
問題 |
No.1047 Zero (Novice)
|
ユーザー |
|
提出日時 | 2020-05-15 17:17:44 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 45 ms / 2,000 ms |
コード長 | 2,053 bytes |
コンパイル時間 | 1,565 ms |
コンパイル使用メモリ | 189,476 KB |
実行使用メモリ | 17,792 KB |
最終ジャッジ日時 | 2024-09-19 04:20:18 |
合計ジャッジ時間 | 2,913 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 17 |
ソースコード
//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops") //#pragma GCC target("avx,avx2") //#pragma GCC target("avx2") //#pragma GCC optimize("O3") //# include <x86intrin.h> # include <bits/stdc++.h> # include <ext/pb_ds/assoc_container.hpp> # include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; template<typename T> using ordered_set = tree <T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; #define _USE_MATH_DEFINES_ #define ll long long #define ld long double #define Accepted 0 #define pb push_back #define mp make_pair #define sz(x) (int)(x.size()) #define every(x) x.begin(),x.end() #define F first #define S second #define lb lower_bound #define ub upper_bound #define For(i,x,y) for (ll i = x; i <= y; i ++) #define FOr(i,x,y) for (ll i = x; i >= y; i --) #define SpeedForce ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0) // ROAD to... Red inline void Input_Output () { //freopen(".in", "r", stdin); //freopen(".out", "w", stdout); } const double eps = 0.000001; const ld pi = acos(-1); const int maxn = 1e7 + 9; const int mod = 1e9 + 7; const ll MOD = 1e18 + 9; const ll INF = 1e18 + 123; const int inf = 2e9 + 11; const int mxn = 1e6 + 9; const int N = 6e5 + 123; const int M = 22; const int pri = 997; const int Magic = 2101; const int dx[] = {-1, 0, 1, 0}; const int dy[] = {0, -1, 0, 1}; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); int n, m, k; int cnt[N]; string s; int a[N]; vector < int > g[N]; int u[N]; int ans, res; int cur; int main () { SpeedForce; ld n, a, b; a = n = b = 0; cin >> a >> b; for (int it = 1; it <= 101010; ++it) { n = n * a + b; if((ll)n == 0) { cout << it << '\n'; return 0; } } cout << -1 << '\n'; return Accepted; } // B...a