結果

問題 No.1054 Union add query
ユーザー penguinshunyapenguinshunya
提出日時 2020-05-15 23:07:35
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 611 ms / 2,000 ms
コード長 5,457 bytes
コンパイル時間 2,536 ms
コンパイル使用メモリ 226,940 KB
実行使用メモリ 28,808 KB
最終ジャッジ日時 2024-09-19 13:07:25
合計ジャッジ時間 6,929 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,940 KB
testcase_02 AC 1 ms
6,940 KB
testcase_03 AC 366 ms
14,080 KB
testcase_04 AC 468 ms
28,808 KB
testcase_05 AC 333 ms
11,544 KB
testcase_06 AC 318 ms
19,436 KB
testcase_07 AC 278 ms
19,500 KB
testcase_08 AC 300 ms
19,312 KB
testcase_09 AC 611 ms
25,080 KB
testcase_10 AC 448 ms
25,160 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>

#define rep(i, n) for (int i = 0; i < int(n); i++)
#define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--)
#define reps(i, n) for (int i = 1; i <= int(n); i++)
#define rreps(i, n) for (int i = int(n); i >= 1; i--)
#define repc(i, n) for (int i = 0; i <= int(n); i++)
#define rrepc(i, n) for (int i = int(n); i >= 0; i--)
#define repi(i, a, b) for (int i = int(a); i < int(b); i++)
#define repic(i, a, b) for (int i = int(a); i <= int(b); i++)
#define all(a) (a).begin(), (a).end()
#define bit32(x) (1 << (x))
#define bit64(x) (1ll << (x))
#define sz(v) ((int) v.size())

using namespace std;

using i64 = long long;
using f80 = long double;
using vi32 = vector<int>;
using vi64 = vector<i64>;
using vf80 = vector<f80>;
using vstr = vector<string>;

inline void yes() { cout << "Yes" << endl; exit(0); }
inline void no() { cout << "No" << endl; exit(0); }
inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); }
inline i64 lcm(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); return a / gcd(a, b) * b; }
template <typename T> class pqasc : public priority_queue<T, vector<T>, greater<T>> {};
template <typename T> class pqdesc : public priority_queue<T, vector<T>, less<T>> {};
template <typename T> inline void amax(T &x, T y) { x = max(x, y); }
template <typename T> inline void amin(T &x, T y) { x = min(x, y); }
template <typename T> inline T exp(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; }
template <typename T> istream& operator>>(istream &is, vector<T> &v) { for (auto &x : v) is >> x; return is; }
template <typename T> ostream& operator<<(ostream &os, vector<T> &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; }
void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; }

struct UnionFind {
  vector<int> data;
  UnionFind(int n) {
    data.assign(n, -1);
  }
  int root(int k) {
    if (data[k] < 0) return k;
    return data[k] = root(data[k]);
  }
  void unite(int x, int y) {
    x = root(x);
    y = root(y);
    if (x == y) return;
    if (data[x] > data[y]) swap(x, y);
    data[x] += data[y];
    data[y] = x;
  }
  bool same(int x, int y) {
    return root(x) == root(y);
  }
  int size(int k) {
    return -data[root(k)];
  }
};

template <typename T, typename S>
struct LazySegmentTree {
  vector<T> v;
  vector<S> z;
  function<T(T, T)> f;
  function<T(T, S, int)> g;
  function<S(S, S)> h;
  T e;
  S d;
  int n;
  LazySegmentTree(
    int size,
    function<T(T, T)> f,
    function<T(T, S, int)> g,
    function<S(S, S)> h,
    T e, 
    S d
  ) : f(f), g(g), h(h), e(e), d(d) {
    n = 1;
    while (n < size) n <<= 1;
    v.resize(n * 2, e);
    z.resize(n * 2, d);
  }
  void set(int k, T x) {
    v[k + n] = x;
  }
  void build() {
    for (int i = n - 1; i >= 0; i--) {
      v[i] = f(v[i * 2 + 0], v[i * 2 + 1]);
    }
  }
  void propagate(int k, int l, int r) {
    v[k] = g(v[k], z[k], r - l);
    if (k < n) {
      z[k * 2 + 0] = h(z[k * 2 + 0], z[k]);
      z[k * 2 + 1] = h(z[k * 2 + 1], z[k]);
    }
    z[k] = d;
  }
  T update(int a, int b, S x, int k = 1, int l = 0, int r = -1) {
    if (r == -1) r = n;
    propagate(k, l, r);
    if (b <= l || r <= a) return v[k];
    if (a <= l && r <= b) { z[k] = x; propagate(k, l, r); return v[k]; }
    return v[k] = f(
      update(a, b, x, k * 2 + 0, l, (l + r) / 2),
      update(a, b, x, k * 2 + 1, (l + r) / 2, r)
    );
  }
  T query(int a, int b, int k = 1, int l = 0, int r = -1) {
    if (r == -1) r = n;
    propagate(k, l, r);
    if (b <= l || r <= a) return e;
    if (a <= l && r <= b) return v[k];
    return f(
      query(a, b, k * 2 + 0, l, (l + r) / 2),
      query(a, b, k * 2 + 1, (l + r) / 2, r)
    );
  }
};

void solve() {
  int n, q;
  cin >> n >> q;
  vi32 t(q), a(q), b(q);
  rep(i, q) {
    cin >> t[i] >> a[i] >> b[i];
    a[i]--, b[i]--;
  }
  using T = tuple<int, int, int, int>;
  vector<T> history;
  UnionFind uf(n);
  rep(i, q) if (t[i] == 1) {
    if (uf.same(a[i], b[i])) continue;
    history.emplace_back(uf.root(a[i]), uf.root(b[i]), uf.size(a[i]), uf.size(b[i]));
    uf.unite(a[i], b[i]);
  }
  reverse(all(history));
  int last = 0;
  vi32 indices(n, -1);
  rep(i, sz(history)) {
    int u, v, usize, vsize;
    tie(u, v, usize, vsize) = history[i];
    if (indices[u] == -1) {
      swap(u, v);
      swap(usize, vsize);
    }
    if (indices[u] == -1) {
      indices[u] = last;
      indices[v] = last + usize;
      last += usize + vsize;
    } else if (indices[v] == -1) {
      indices[v] = indices[u] + usize;
    }
  }
  rep(i, n) if (indices[i] == -1) {
    indices[i] = last++;
  }
  LazySegmentTree<int, int> lst(n,
    [](int a, int b) { return a + b; },
    [](int a, int b, int k) { return a + b * k; },
    [](int a, int b) { return a + b; },
    0, 0);
  UnionFind uf2(n);
  vi32 mins(n);
  rep(i, n) {
    mins[i] = indices[i];
  }
  rep(i, q) {
    if (t[i] == 1) {
      if (uf2.same(a[i], b[i])) continue;
      int mi = min(mins[uf2.root(a[i])], mins[uf2.root(b[i])]);
      uf2.unite(a[i], b[i]);
      mins[uf2.root(a[i])] = mi;
    } else if (t[i] == 2) {
      int l = mins[uf2.root(a[i])];
      int r = l + uf2.size(a[i]);
      lst.update(l, r, b[i] + 1);
    } else {
      int l = indices[a[i]];
      int ans = lst.query(l, l + 1);
      cout << ans << '\n';
    }
  }
}
0