結果

問題 No.922 東北きりきざむたん
ユーザー maspymaspy
提出日時 2020-05-16 13:19:30
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
AC  
実行時間 1,360 ms / 2,000 ms
コード長 2,131 bytes
コンパイル時間 301 ms
コンパイル使用メモリ 13,056 KB
実行使用メモリ 60,796 KB
最終ジャッジ日時 2024-09-22 06:45:25
合計ジャッジ時間 18,697 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 4
other AC * 26
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys

read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

N, M, Q = map(int, readline().split())

G = [[] for _ in range(N + 1)]
for _ in range(M):
    a, b = map(int, readline().split())
    G[a].append(b)
    G[b].append(a)

root = [0] * (N + 1)
parent = [0] * (N + 1)
depth = [0] * (N + 1)
stack = []
order = []
for r in range(1, N + 1):
    if root[r]:
        continue
    root[r] = 0
    depth[r] = 1
    stack = [r]
    while stack:
        v = stack.pop()
        root[v] = r
        order.append(v)
        for w in G[v]:
            if w == parent[v]:
                continue
            parent[w] = v
            depth[w] = depth[v] + 1
            stack.append(w)

def dist_func():
    K = 18
    P = [parent]
    for i in range(1, K):
        A = P[-1]
        P.append([A[v] for v in A])

    def LCA(u, v):
        du, dv = depth[u], depth[v]
        if du < dv:
            du, dv = dv, du
            u, v = v, u
        n = du - dv
        for i in range(K):
            if n & 1:
                u = P[i][u]
            n >>= 1
        if u == v:
            return u
        for i in range(K - 1, -1, -1):
            u1, v1 = P[i][u], P[i][v]
            if u1 == v1:
                continue
            u, v = u1, v1
        return parent[u]

    def dist(u, v):
        w = LCA(u, v)
        return depth[u] + depth[v] - 2 * depth[w]

    return dist

dist = dist_func()

dp_size = [0] * (N + 1)
dp_sum = [0] * (N + 1)
m = map(int, read().split())
answer = 0
for a, b in zip(m, m):
    if root[a] == root[b]:
        answer += dist(a, b)
    else:
        dp_size[a] += 1
        dp_size[b] += 1

for v in order[::-1]:
    p = parent[v]
    dp_sum[p] += dp_sum[v] + dp_size[v]
    dp_size[p] += dp_size[v]

comp_cost = [0] * (N + 1)
for v in order:
    r, p = root[v], parent[v]
    if v == r:
        comp_cost[v] = dp_sum[v]
        continue
    lower, upper = dp_size[v], dp_size[r] - dp_size[v]
    dp_sum[v] = dp_sum[p] + upper - lower
    if comp_cost[r] > dp_sum[v]:
        comp_cost[r] = dp_sum[v]

answer += sum(comp_cost)
print(answer)
0