#482870 (C++14) No.1036 Make One With GCD 2

• 問題: No.1036 Make One With GCD 2
• ユーザー: otera
• 提出日時: 2020-05-16 19:19:29
• 言語: C++14 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 1,047 ms / 2,000 ms
• コード長: 3,204 bytes
• コンパイル時間: 1,243 ms
• コンパイル使用メモリ: 120,668 KB
• 実行使用メモリ: 15,396 KB
• 最終ジャッジ日時: 2024-09-16 14:22:16
• 合計ジャッジ時間: 18,935 ms
• ジャッジサーバーID （参考情報）: judge2 / judge3

ファイルパターン	結果
sample	AC * 4
other	AC * 41

ソースコード

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/**
 *    author:  otera    
**/
#include<iostream>
#include<string> 
#include<cstdio>
#include<cstring>
#include<vector>
#include<cmath>
#include<algorithm> 
#include<functional>
#include<iomanip>
#include<queue>
#include<deque>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<complex>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<utility>
#include<cassert>
using namespace std;
#define int long long
typedef long long ll;
typedef unsigned long long ul;
typedef unsigned int ui;
typedef long double ld;
const int inf=1e9+7;
const ll INF=1LL<<60 ;
const ll mod=1e9+7 ;
#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
typedef complex<ld> Point;
const ld eps = 1e-8;
const ld pi = acos(-1.0);
typedef pair<int, int> P;
typedef pair<ld, ld> LDP;
typedef pair<ll, ll> LP;
#define fr first
#define sc second
#define all(c) c.begin(),c.end()
#define pb push_back
#define debug(x)  cerr << #x << " = " << (x) << endl;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
int gcd(int x, int y) {
    if(y == 0) return x;
    return gcd(y, x % y);
}
template<typename T>
struct SegmentTree{
private:
    int n;
    T E;
    vector<T> node;
    inline void updatef(T& x,T& y){
        x = y;
        //x += y;
        //x = max(x,y);
        //x = min(x,y);
    }
    inline T queryf(T& x,T& y){
        return gcd(x, y);
        //return min(x,y);
        //return x+y;
        //return max(x,y);
    }
public:
    SegmentTree(int sz,T E_):E(E_){
        n=1;
        while(n<sz)n<<=1;
        node.resize(2*n-1,E);
    }
    SegmentTree(vector<T>& A,T E_):E(E_){
        int sz=A.size();
        n=1;
        while(n<sz)n<<=1;
        node.resize(2*n-1,E);
        rep(i,sz)node[i+n-1]=A[i];
        for(int i=n-2;i>=0;--i){
            node[i]=queryf(node[2*i+1], node[2*i+2]);
        }
    }
    void update(int k,T x){
        k+=n-1;
        updatef(node[k],x);
        while(k>0){
            k=(k-1)/2;
            node[k]=queryf(node[2*k+1], node[2*k+2]);
        }
    }
       //[a,b)での値を返す
    T get(int a,int b,int k=0,int l=0,int r=-1){
        if(r<0)r=n;
        if(r<=a||b<=l)return E;
        if(a<=l&&r<=b)return node[k];
        T xl=get(a,b,2*k+1,l,(l+r)/2);
        T xr=get(a,b,2*k+2,(l+r)/2,r);
        return queryf(xl, xr);
    }
};
void solve() {
    int n; cin >> n;
    vector<int> a(n);
    rep(i, n) {
        cin >> a[i];
    }
    SegmentTree<int> seg(a, 0);
    int right = 0;
    int ans = 0;
    for(int left = 0; left < n; ++ left) {
        while(right < n && seg.get(left, right + 1) != 1) {
            ++ right;
        }
        ans += n - right;
        if(right == left) ++ right;
    }
    cout << ans << endl;
}
signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    //cout << fixed << setprecision(10);
    //int t; cin >> t; rep(i, t)solve();
    solve();
    return 0;
}
 
 
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