結果
問題 | No.1066 #いろいろな色 / Red and Blue and more various colors (Easy) |
ユーザー | penguinshunya |
提出日時 | 2020-05-29 22:19:10 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 143 ms / 2,000 ms |
コード長 | 2,997 bytes |
コンパイル時間 | 2,124 ms |
コンパイル使用メモリ | 205,708 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-11-06 05:24:26 |
合計ジャッジ時間 | 3,954 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,820 KB |
testcase_01 | AC | 2 ms
6,816 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 2 ms
6,816 KB |
testcase_04 | AC | 2 ms
6,820 KB |
testcase_05 | AC | 2 ms
6,820 KB |
testcase_06 | AC | 2 ms
6,816 KB |
testcase_07 | AC | 2 ms
6,820 KB |
testcase_08 | AC | 55 ms
6,816 KB |
testcase_09 | AC | 2 ms
6,820 KB |
testcase_10 | AC | 138 ms
6,816 KB |
testcase_11 | AC | 33 ms
6,816 KB |
testcase_12 | AC | 25 ms
6,820 KB |
testcase_13 | AC | 32 ms
6,820 KB |
testcase_14 | AC | 35 ms
6,820 KB |
testcase_15 | AC | 93 ms
6,816 KB |
testcase_16 | AC | 15 ms
6,820 KB |
testcase_17 | AC | 18 ms
6,816 KB |
testcase_18 | AC | 82 ms
6,816 KB |
testcase_19 | AC | 32 ms
6,816 KB |
testcase_20 | AC | 1 ms
6,820 KB |
testcase_21 | AC | 67 ms
6,816 KB |
testcase_22 | AC | 2 ms
6,816 KB |
testcase_23 | AC | 2 ms
6,816 KB |
testcase_24 | AC | 2 ms
6,816 KB |
testcase_25 | AC | 142 ms
6,816 KB |
testcase_26 | AC | 143 ms
6,816 KB |
ソースコード
#include <bits/stdc++.h> #define rep(i, n) for (int i = 0; i < int(n); i++) #define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--) #define reps(i, n) for (int i = 1; i <= int(n); i++) #define rreps(i, n) for (int i = int(n); i >= 1; i--) #define repc(i, n) for (int i = 0; i <= int(n); i++) #define rrepc(i, n) for (int i = int(n); i >= 0; i--) #define repi(i, a, b) for (int i = int(a); i < int(b); i++) #define repic(i, a, b) for (int i = int(a); i <= int(b); i++) #define all(a) (a).begin(), (a).end() #define bit32(x) (1 << (x)) #define bit64(x) (1ll << (x)) #define sz(v) ((int) v.size()) using namespace std; using i64 = long long; using f80 = long double; using vi32 = vector<int>; using vi64 = vector<i64>; using vf80 = vector<f80>; using vstr = vector<string>; void yes() { cout << "Yes" << endl; exit(0); } void no() { cout << "No" << endl; exit(0); } template <typename T> class pqasc : public priority_queue<T, vector<T>, greater<T>> {}; template <typename T> class pqdesc : public priority_queue<T, vector<T>, less<T>> {}; template <typename T> void amax(T &x, T y) { x = max(x, y); } template <typename T> void amin(T &x, T y) { x = min(x, y); } template <typename T> T exp(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } template <typename T> istream& operator>>(istream &is, vector<T> &v) { for (auto &x : v) is >> x; return is; } template <typename T> ostream& operator<<(ostream &os, vector<T> &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; } void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; } const int INF = 1001001001; const int dx[] = {1, 0, -1, 0}; const int dy[] = {0, 1, 0, -1}; template <int mod> struct ModInt { int x; ModInt(): x(0) {} ModInt(long long a) { x = a % mod; if (x < 0) x += mod; } ModInt &operator+=(ModInt that) { x = (x + that.x) % mod; return *this; } ModInt &operator-=(ModInt that) { x = (x + mod - that.x) % mod; return *this; } ModInt &operator*=(ModInt that) { x = (long long) x * that.x % mod; return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt inverse() { int a = x, b = mod, u = 1, v = 0; while (b) { int t = a / b; a -= t * b; u -= t * v; swap(a, b); swap(u, v); } return ModInt(u); } #define op(o, p) ModInt operator o(ModInt that) { return ModInt(*this) p that; } op(+, +=) op(-, -=) op(*, *=) op(/, /=) #undef op friend ostream& operator<<(ostream &os, ModInt m) { return os << m.x; } }; using mint = ModInt<998244353>; mint dp[2][6001]; void solve() { int n, q; cin >> n >> q; vi32 a(n); vi32 b(q); cin >> a >> b; dp[0][0] = 1; rep(i, n) { int ci = (i + 0) % 2; int ni = (i + 1) % 2; repc(j, n) { dp[ni][j] = 0; } repc(j, n) { dp[ni][j] += dp[ci][j] * (a[i] - 1); dp[ni][j+1] += dp[ci][j]; } } rep(i, q) { cout << dp[n % 2][b[i]] << endl; } }