結果

問題 No.1065 電柱 / Pole (Easy)
ユーザー fairy_lettuce
提出日時 2020-05-29 22:49:11
言語 C#(csc)
(csc 3.9.0)
結果
RE  
実行時間 -
コード長 9,627 bytes
コンパイル時間 4,602 ms
コンパイル使用メモリ 116,248 KB
実行使用メモリ 63,248 KB
最終ジャッジ日時 2024-11-06 06:56:40
合計ジャッジ時間 16,896 ms
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 39 RE * 7
権限があれば一括ダウンロードができます
コンパイルメッセージ
Microsoft (R) Visual C# Compiler version 3.9.0-6.21124.20 (db94f4cc)
Copyright (C) Microsoft Corporation. All rights reserved.

ソースコード

diff #
プレゼンテーションモードにする

using System;
using System.IO;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace AtCoder.Contest.C
{
static class Program
{
public static void Main(string[] args)
{
var sw = new StreamWriter(Console.OpenStandardOutput()) { AutoFlush = false };
Console.SetOut(sw);
var cin = new Scanner();
int n = cin.NextInt();
int m = cin.NextInt();
int x = cin.NextInt() - 1;
int y = cin.NextInt() - 1;
var dijk = new Dijkstra(n);
var p = new List<int>();
var q = new List<int>();
for (int i = 0; i < n; i++)
{
p.Add(cin.NextInt());
q.Add(cin.NextInt());
}
for (int i = 0; i < m; i++)
{
var pp = cin.NextInt() - 1;
var qq = cin.NextInt() - 1;
dijk.Add(pp, qq,
Math.Sqrt((p[pp] - p[qq]) * (p[pp] - p[qq]) + (q[pp] - q[qq]) * (q[pp] - q[qq])));
}
if (p[x] == p[y] && q[x] == q[y]) Console.WriteLine(0);
else Console.WriteLine(dijk.GetMinCost(x)[y]);
Console.Out.Flush();
}
}
class Dijkstra
{
public int N { get; set; }
public List<Edge>[] G { get; set; }
public Dijkstra(int n)
{
this.N = n;
this.G = new List<Edge>[N];
for (int i = 0; i < N; i++)
{
this.G[i] = new List<Edge>();
}
}
// a b
public void Add(int a, int b, double cost = 1)
{
this.G[a].Add(new Edge(b, cost));
this.G[b].Add(new Edge(a, cost));
}
//
public double[] GetMinCost(int start)
{
// ()(INF)
var cost = new double[N];
for (int i = 0; i < N; i++) cost[i] = double.MaxValue;
cost[start] = 0;
// ()
var q = new PriorityQueue<P>(this.N, false);
q.Enqueue(new P(start, 0));
//
while (q.Count > 0)
{
var p = q.Dequeue();
// ()
if (p.Cost != cost[p.A]) continue;
//
//
foreach (var e in this.G[p.A])
{
//
if (cost[e.To] > p.Cost + e.Cost)
{
//
cost[e.To] = p.Cost + e.Cost;
q.Enqueue(new P(e.To, cost[e.To]));
}
}
}
return cost;
}
//
public struct Edge
{
public int To;
public double Cost;
public Edge(int to, double cost)
{
this.To = to;
this.Cost = cost;
}
}
//
public struct P : IComparable<P>
{
public int A;
public double Cost;
public P(int a, double cost)
{
this.A = a;
this.Cost = cost;
}
public int CompareTo(P other)
{
return this.Cost.CompareTo(other.Cost);
}
}
}
public class Pair<T, U> : IComparable, IEquatable<Pair<T, U>> where T : IComparable<T>, IEquatable<T> where U : IComparable<U>, IEquatable<U>
{
public T First { get; set; }
public U Second { get; set; }
public Pair(T first, U second)
{
First = first;
Second = second;
}
public int CompareTo(object obj)
{
Pair<T, U> castedObj = (Pair<T, U>)obj;
int x = First.CompareTo(castedObj.First);
if (x != 0) return x;
else return Second.CompareTo(castedObj.Second);
}
public static bool operator ==(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) == 0;
public static bool operator !=(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) != 0;
public static bool operator <(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) == 1;
public static bool operator >(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) == -1;
public static bool operator <=(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) > 0;
public static bool operator >=(Pair<T, U> x, Pair<T, U> y) => x.CompareTo(y) < 0;
public bool Equals(Pair<T, U> x) => First.Equals(x.First) && Second.Equals(x.Second);
public override bool Equals(object obj)
{
return obj is Pair<T, U> pair &&
EqualityComparer<T>.Default.Equals(First, pair.First) &&
EqualityComparer<U>.Default.Equals(Second, pair.Second);
}
public override int GetHashCode()
{
unchecked
{
var hashCode = 405212230;
hashCode = hashCode * -1521134295 + EqualityComparer<T>.Default.GetHashCode(First);
hashCode = hashCode * -1521134295 + EqualityComparer<U>.Default.GetHashCode(Second);
return hashCode;
}
}
}
class PriorityQueue<T> where T : IComparable<T>
{
public readonly T[] Array;
public readonly bool Greater;
public int Count { get; private set; } = 0;
public PriorityQueue(int capacity, bool greater = true)
{
this.Array = new T[capacity];
this.Greater = greater;
}
public void Enqueue(T item)
{
this.Array[this.Count] = item;
this.Count += 1;
this.UpHeap();
}
public T Dequeue()
{
//
this.Swap(0, this.Count - 1);
this.Count -= 1;
this.DownHeap();
return this.Array[this.Count];
}
private void UpHeap()
{
var n = this.Count - 1;
while (n != 0)
{
//
var parent = (n - 1) / 2;
if (this.Compare(this.Array[n], this.Array[parent]) > 0)
{
this.Swap(n, parent);
n = parent;
}
else
{
break;
}
}
}
private void DownHeap()
{
var parent = 0;
while (true)
{
var child = 2 * parent + 1;
if (child > this.Count - 1) break;
if (child < this.Count - 1 && this.Compare(this.Array[child], this.Array[child + 1]) < 0)
{
//
child += 1;
}
if (this.Compare(this.Array[parent], this.Array[child]) < 0)
{
this.Swap(parent, child);
parent = child;
}
else
{
break;
}
}
}
private int Compare(T a, T b)
{
var c = a.CompareTo(b);
if (!this.Greater)
{
c = -c;
}
return c;
}
private void Swap(int a, int b)
{
var tmp = this.Array[a];
this.Array[a] = this.Array[b];
this.Array[b] = tmp;
}
}
class Scanner
{
string[] s;
int i;
char[] cs = new char[] { ' ' };
public Scanner()
{
s = new string[0];
i = 0;
}
public string Next()
{
if (i < s.Length) return s[i++];
string st = Console.ReadLine();
while (st == "") st = Console.ReadLine();
s = st.Split(cs, StringSplitOptions.RemoveEmptyEntries);
if (s.Length == 0) return Next();
i = 0;
return s[i++];
}
public int NextInt()
{
return int.Parse(Next());
}
public int[] ArrayInt(int N, int add = 0)
{
int[] Array = new int[N];
for (int i = 0; i < N; i++)
{
Array[i] = NextInt() + add;
}
return Array;
}
public long NextLong()
{
return long.Parse(Next());
}
public long[] ArrayLong(int N, long add = 0)
{
long[] Array = new long[N];
for (int i = 0; i < N; i++)
{
Array[i] = NextLong() + add;
}
return Array;
}
public double NextDouble()
{
return double.Parse(Next());
}
public double[] ArrayDouble(int N, double add = 0)
{
double[] Array = new double[N];
for (int i = 0; i < N; i++)
{
Array[i] = NextDouble() + add;
}
return Array;
}
}
}
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