結果

問題 No.1067 #いろいろな色 / Red and Blue and more various colors (Middle)
ユーザー veqccveqcc
提出日時 2020-05-29 23:48:28
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 420 ms / 2,000 ms
コード長 3,057 bytes
コンパイル時間 1,143 ms
コンパイル使用メモリ 114,800 KB
実行使用メモリ 284,928 KB
最終ジャッジ日時 2024-11-06 08:58:33
合計ジャッジ時間 5,126 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,820 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 2 ms
6,820 KB
testcase_06 AC 2 ms
6,816 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 2 ms
6,816 KB
testcase_09 AC 2 ms
6,816 KB
testcase_10 AC 2 ms
6,820 KB
testcase_11 AC 263 ms
179,712 KB
testcase_12 AC 164 ms
108,672 KB
testcase_13 AC 378 ms
251,136 KB
testcase_14 AC 201 ms
139,392 KB
testcase_15 AC 83 ms
55,296 KB
testcase_16 AC 72 ms
43,136 KB
testcase_17 AC 14 ms
10,752 KB
testcase_18 AC 207 ms
145,280 KB
testcase_19 AC 215 ms
154,112 KB
testcase_20 AC 101 ms
59,392 KB
testcase_21 AC 420 ms
284,928 KB
testcase_22 AC 414 ms
284,928 KB
testcase_23 AC 415 ms
284,928 KB
testcase_24 AC 2 ms
6,820 KB
testcase_25 AC 2 ms
6,820 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <functional>
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <string>
#include <vector>
#include <random>
#include <bitset>
#include <queue>
#include <cmath>
#include <stack>
#include <set>
#include <map>
typedef long long ll;
using namespace std;
const ll MOD = 998244353;

template <ll mod> class ModInt {
    ll a;
public:
    constexpr ModInt(const ll a = 0) noexcept : a((a % mod + mod) % mod) {}
    constexpr ll &value() noexcept { return a; }
    constexpr ModInt operator + (const ModInt &rhs) const noexcept { return ModInt(*this) += rhs; }
    constexpr ModInt operator - (const ModInt &rhs) const noexcept { return ModInt(*this) -= rhs; }
    constexpr ModInt operator * (const ModInt &rhs) const noexcept { return ModInt(*this) *= rhs; }
    constexpr ModInt operator / (const ModInt &rhs) const noexcept { return ModInt(*this) /= rhs; }
    constexpr ModInt &operator += (const ModInt &rhs) noexcept {
        a += rhs.a;
        if (a >= mod) a -= mod;
        return *this;
    }
    constexpr ModInt &operator -= (const ModInt &rhs) noexcept {
        a += mod - rhs.a;
        if (a >= mod) a -= mod;
        return *this;
    }
    constexpr ModInt &operator *= (const ModInt &rhs) noexcept {
        a = a * rhs.a % mod;
        return *this;
    }
    constexpr ModInt pow(ll t) const noexcept {
        if (t == 0) return 1;
        auto ret = pow(t >> 1);
        ret *= ret;
        if (t & 1) ret *= *this;
        return ret;
    }
    constexpr ModInt inv() const noexcept { return pow(mod - 2); }
    constexpr ModInt operator /=(const ModInt &rhs) { return (*this) *= rhs.inv(); }
    constexpr bool operator == (const ModInt &rhs) const noexcept { return this->a == rhs.a; }
    constexpr bool operator != (const ModInt &rhs) const noexcept { return this->a != rhs.a; }
    friend constexpr ostream &operator << (ostream &os, const ModInt &rhs) noexcept { return os << rhs.a; }
    friend constexpr istream &operator >> (istream &is, ModInt &rhs) {
        is >> rhs.a;
        return is;
    }
};
using mint = ModInt<MOD>;

typedef pair<int, int> P;
int main() {
    int n, q;
    cin >> n >> q;

    vector<ll> a(n);
    for (int i = 0; i < n; i++) cin >> a[i];

    sort(a.begin(), a.end());

    vector<mint> as(n + 1, 1);
    for (int i = 0; i < n; i++) as[i + 1] = as[i] * a[i];

    reverse(a.begin(), a.end());

    vector<vector<mint>> dp(n + 1, vector<mint>(n + 1, 0));
    dp[0][0] = 1;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j <= n; j++) {
            dp[i + 1][j] = dp[i][j] * (a[i] - 1);
            if (j) dp[i + 1][j] += dp[i][j - 1];
        }
    }

    reverse(a.begin(), a.end());

    for (int i = 0; i < q; i++) {
        int l, r, p;
        cin >> l >> r >> p;

        ll ret = 0;
        for (int j = l; j <= r; j++) {
            int idx = lower_bound(a.begin(), a.end(), j) - a.begin();
            mint x = as[idx] * dp[n - idx][p];
            ret ^= x.value();
        }
        cout << ret % MOD << endl;
    }

    return 0;
}
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