結果

問題 No.1043 直列大学
ユーザー rniyarniya
提出日時 2020-05-30 16:44:02
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 181 ms / 2,000 ms
コード長 3,864 bytes
コンパイル時間 1,670 ms
コンパイル使用メモリ 172,736 KB
実行使用メモリ 162,224 KB
最終ジャッジ日時 2024-12-22 20:07:59
合計ジャッジ時間 5,724 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
const long long MOD=1e9+7,MAX=1e5+10;

template<uint_fast64_t Modulus> class modint{
    using u64=uint_fast64_t;
    public:
    u64 a;
    constexpr modint(const u64 x=0) noexcept:a(((x%Modulus)+Modulus)%Modulus){}
    constexpr u64 &value() noexcept{return a;}
    constexpr const u64 &value() const noexcept{return a;}
    constexpr modint &operator+=(const modint &rhs) noexcept{
        a+=rhs.a;
        if (a>=Modulus) a-=Modulus;
        return *this;
    }
    constexpr modint operator+(const modint &rhs) const noexcept{
        return modint(*this)+=rhs;
    }
    constexpr modint &operator++() noexcept{
        return ++a,*this;
    }
    constexpr modint operator++(int) noexcept{
        modint t=*this; return ++a,t;
    }
    constexpr modint &operator-=(const modint &rhs) noexcept{
        if (a<rhs.a) a+=Modulus;
        a-=rhs.a;
        return *this;
    }
    constexpr modint operator-(const modint &rhs) const noexcept{
        return modint(*this)-=rhs;
    }
    constexpr modint &operator--() noexcept{
        return --a,*this;
    }
    constexpr modint operator--(int) noexcept{
        modint t=*this; return --a,t;
    }
    constexpr modint &operator*=(const modint &rhs) noexcept{
        a=a*rhs.a%Modulus;
        return *this;
    }
    constexpr modint operator*(const modint &rhs) const noexcept{
        return modint(*this)*=rhs;
    }
    constexpr modint &operator/=(modint rhs) noexcept{
        u64 exp=Modulus-2;
        while(exp){
            if (exp&1) *this*=rhs;
            rhs*=rhs; exp>>=1;
        }
        return *this;
    }
    constexpr modint operator/(const modint &rhs) const noexcept{
        return modint(*this)/=rhs;
    }
    constexpr modint operator-() const noexcept{
        return modint(Modulus-a);
    }
    constexpr bool operator==(const modint &rhs) const noexcept{
        return a==rhs.a;
    }
    constexpr bool operator!=(const modint &rhs) const noexcept{
        return a!=rhs.a;
    }
    constexpr bool operator!() const noexcept{return !a;}
    friend constexpr modint pow(modint rhs,long long exp) noexcept{
        modint res{1};
        while(exp){
            if (exp&1) res*=rhs;
            rhs*=rhs; exp>>=1;
        }
        return res;
    }
    template<class T> friend constexpr modint operator+(T x,modint y) noexcept{
        return modint(x)+y;
    }
    template<class T> friend constexpr modint operator-(T x,modint y) noexcept{
        return modint(x)-y;
    }
    template<class T> friend constexpr modint operator*(T x,modint y) noexcept{
        return modint(x)*y;
    }
    template<class T> friend constexpr modint operator/(T x,modint y) noexcept{
        return modint(x)/y;
    }
    friend ostream &operator<<(ostream &s,const modint &rhs) noexcept{
        return s << rhs.a;
    }
    friend istream &operator>>(istream &s,modint &rhs) noexcept{
        u64 a; rhs=modint{(s >> a,a)}; return s;
    }
};

using mint=modint<MOD>;

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    int N,M; cin >> N >> M;
    vector<vector<mint>> dpv(N+1,vector<mint>(MAX,0))
                        ,dpr(M+1,vector<mint>(MAX,0));
    dpv[0][0]=dpr[0][0]=1;
    for (int i=0;i<N;++i){
        int V; cin >> V;
        for (int j=0;j<MAX;++j){
            dpv[i+1][j]+=dpv[i][j];
            if (j+V<MAX) dpv[i+1][j+V]+=dpv[i][j];
        }
    }
    for (int i=0;i<M;++i){
        int C; cin >> C;
        for (int j=0;j<MAX;++j){
            dpr[i+1][j]+=dpr[i][j];
            if (j+C<MAX) dpr[i+1][j+C]+=dpr[i][j];
        }
    }
    int A,B; cin >> A >> B;
    mint ans=0;
    vector<mint> sum(MAX,0);
    for (int i=1;i<MAX;++i) sum[i]=sum[i-1]+dpv[N][i];
    for (long long i=1;i<MAX;++i){
        ans+=dpr[M][i]*(sum[min(MAX-1,i*B)]-sum[min(MAX-1,i*A-1)]);
    }
    cout << ans << '\n';
}
0