結果

問題 No.43 野球の試合
ユーザー Coki628
提出日時 2020-06-04 00:29:35
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
AC  
実行時間 564 ms / 5,000 ms
コード長 1,732 bytes
コンパイル時間 72 ms
コンパイル使用メモリ 12,800 KB
実行使用メモリ 11,008 KB
最終ジャッジ日時 2024-11-26 11:20:05
合計ジャッジ時間 2,844 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 4
other AC * 7
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10 ** 9)
INF = 10 ** 19
MOD = 10 ** 9 + 7
EPS = 10 ** -10
N = INT()
grid = []
for i in range(N):
    grid += list(input())
def check(grid):
    win = [0] * N
    for i in range(N):
        for j in range(i+1, N):
            if grid[i*N+j] == 'o':
                win[i] += 1
            elif grid[i*N+j] == 'x':
                win[j] += 1
    win = [(a, i) for i, a in enumerate(win)]
    win.sort(reverse=1)
    rank = [0] * N
    cur = 1
    rank[win[0][1]] = cur
    for i in range(1, N):
        if win[i][0] != win[i-1][0]:
            cur += 1
        rank[win[i][1]] = cur
    return rank[0]
gtob = {}
b = 0
for i in range(N):
    for j in range(i+1, N):
        gtob[i*N+j] = b
        b += 1
ans = INF
for bit in range(1<<b):
    cur = grid[:]
    for i in range(N):
        for j in range(i+1, N):
            if cur[i*N+j] == '-':
                k = gtob[i*N+j]
                if bit>>k & 1:
                    cur[i*N+j] = 'o'
                    cur[j*N+i] = 'x'
                else:
                    cur[i*N+j] = 'x'
                    cur[j*N+i] = 'o'
    ans = min(ans, check(cur))
print(ans)
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0