結果
問題 | No.1071 ベホマラー |
ユーザー | snuke |
提出日時 | 2020-06-05 21:30:29 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 55 ms / 2,000 ms |
コード長 | 2,628 bytes |
コンパイル時間 | 2,032 ms |
コンパイル使用メモリ | 199,496 KB |
最終ジャッジ日時 | 2025-01-10 22:09:20 |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 20 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:71:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 71 | scanf("%d%d%d%d",&n,&k,&x,&y); | ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h> #define fi first #define se second #define rep(i,n) for(int i = 0; i < (n); ++i) #define rrep(i,n) for(int i = 1; i <= (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) #define rng(a) a.begin(),a.end() #define rrng(a) a.rbegin(),a.rend() #define maxs(x,y) (x = max(x,y)) #define mins(x,y) (x = min(x,y)) #define isin(x,l,r) ((l) <= (x) && (x) < (r)) #define pb push_back #define eb emplace_back #define sz(x) (int)(x).size() #define pcnt __builtin_popcountll #define uni(x) x.erase(unique(rng(x)),x.end()) #define snuke srand((unsigned)clock()+(unsigned)time(NULL)); #define show(x) cout<<#x<<" = "<<x<<endl; #define PQ(T) priority_queue<T,v(T),greater<T> > #define bn(x) ((1<<x)-1) #define dup(x,y) (((x)+(y)-1)/(y)) #define newline puts("") #define v(T) vector<T> #define vv(T) v(v(T)) using namespace std; typedef long long int ll; typedef unsigned uint; typedef unsigned long long ull; typedef pair<int,int> P; typedef tuple<int,int,int> T; typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<ll> vl; typedef vector<P> vp; typedef vector<T> vt; inline int getInt() { int x; scanf("%d",&x); return x;} template<typename T>inline istream& operator>>(istream&i,v(T)&v) {rep(j,sz(v))i>>v[j];return i;} template<typename T>string join(const v(T)&v) {stringstream s;rep(i,sz(v))s<<' '<<v[i];return s.str().substr(1);} template<typename T>inline ostream& operator<<(ostream&o,const v(T)&v) {if(sz(v))o<<join(v);return o;} template<typename T1,typename T2>inline istream& operator>>(istream&i,pair<T1,T2>&v) {return i>>v.fi>>v.se;} template<typename T1,typename T2>inline ostream& operator<<(ostream&o,const pair<T1,T2>&v) {return o<<v.fi<<","<<v.se;} template<typename T>inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #define dame { puts("-1"); return 0;} #define yn {puts("Yes");}else{puts("No");} const int MX = 200005; typedef __int128_t l3; typedef __uint128_t ul3; std::ostream &operator<<(std::ostream &o, l3 x) { string s; bool sg = x < 0; ul3 ux = sg?-x:x; do {s += '0'+ux%10; ux /= 10;} while (ux); if (sg) s += '-'; reverse(rng(s)); return o<<s; } int main() { int n,k,x,y; scanf("%d%d%d%d",&n,&k,&x,&y); vi a(n); cin>>a; sort(rng(a)); rep(i,n) a[i] = dup(a[i]-1,k); ll s = suma(a); l3 ans = l3(s)*x; rep(i,n) { l3 now = l3(s-a[i]*ll(n-i))*x; now += (ll)y*a[i]; mins(ans,now); s -= a[i]; } cout<<ans<<endl; return 0; }