結果
問題 | No.1075 木の上の山 |
ユーザー | kimiyuki |
提出日時 | 2020-06-06 00:06:29 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 20 ms / 2,000 ms |
コード長 | 5,281 bytes |
コンパイル時間 | 2,811 ms |
コンパイル使用メモリ | 209,632 KB |
実行使用メモリ | 11,392 KB |
最終ジャッジ日時 | 2024-05-10 00:39:09 |
合計ジャッジ時間 | 3,532 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 1 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 1 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 19 ms
11,392 KB |
testcase_18 | AC | 10 ms
5,376 KB |
testcase_19 | AC | 20 ms
9,700 KB |
testcase_20 | AC | 11 ms
5,376 KB |
testcase_21 | AC | 11 ms
5,376 KB |
testcase_22 | AC | 12 ms
5,376 KB |
testcase_23 | AC | 12 ms
5,376 KB |
testcase_24 | AC | 12 ms
5,376 KB |
testcase_25 | AC | 12 ms
5,376 KB |
testcase_26 | AC | 11 ms
5,376 KB |
testcase_27 | AC | 12 ms
5,376 KB |
testcase_28 | AC | 16 ms
6,508 KB |
testcase_29 | AC | 12 ms
5,376 KB |
testcase_30 | AC | 11 ms
5,376 KB |
testcase_31 | AC | 13 ms
5,376 KB |
ソースコード
#line 1 "main.cpp" #include <bits/stdc++.h> #line 2 "/home/user/GitHub/competitive-programming-library/utils/macros.hpp" #define REP(i, n) for (int i = 0; (i) < (int)(n); ++ (i)) #define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++ (i)) #define REP_R(i, n) for (int i = (int)(n) - 1; (i) >= 0; -- (i)) #define REP3R(i, m, n) for (int i = (int)(n) - 1; (i) >= (int)(m); -- (i)) #define ALL(x) std::begin(x), std::end(x) #line 3 "/home/user/GitHub/competitive-programming-library/modulus/modpow.hpp" inline int32_t modpow(uint_fast64_t x, uint64_t k, int32_t MOD) { assert (/* 0 <= x and */ x < (uint_fast64_t)MOD); uint_fast64_t y = 1; for (; k; k >>= 1) { if (k & 1) (y *= x) %= MOD; (x *= x) %= MOD; } assert (/* 0 <= y and */ y < (uint_fast64_t)MOD); return y; } #line 4 "/home/user/GitHub/competitive-programming-library/modulus/modinv.hpp" inline int32_t modinv_nocheck(int32_t value, int32_t MOD) { assert (0 <= value and value < MOD); if (value == 0) return -1; int64_t a = value, b = MOD; int64_t x = 0, y = 1; for (int64_t u = 1, v = 0; a; ) { int64_t q = b / a; x -= q * u; std::swap(x, u); y -= q * v; std::swap(y, v); b -= q * a; std::swap(b, a); } if (not (value * x + MOD * y == b and b == 1)) return -1; if (x < 0) x += MOD; assert (0 <= x and x < MOD); return x; } inline int32_t modinv(int32_t x, int32_t MOD) { int32_t y = modinv_nocheck(x, MOD); assert (y != -1); return y; } #line 7 "/home/user/GitHub/competitive-programming-library/modulus/mint.hpp" /** * @brief quotient ring / 剰余環 $\mathbb{Z}/n\mathbb{Z}$ */ template <int32_t MOD> struct mint { int32_t value; mint() : value() {} mint(int64_t value_) : value(value_ < 0 ? value_ % MOD + MOD : value_ >= MOD ? value_ % MOD : value_) {} mint(int32_t value_, std::nullptr_t) : value(value_) {} explicit operator bool() const { return value; } inline mint<MOD> operator + (mint<MOD> other) const { return mint<MOD>(*this) += other; } inline mint<MOD> operator - (mint<MOD> other) const { return mint<MOD>(*this) -= other; } inline mint<MOD> operator * (mint<MOD> other) const { return mint<MOD>(*this) *= other; } inline mint<MOD> & operator += (mint<MOD> other) { this->value += other.value; if (this->value >= MOD) this->value -= MOD; return *this; } inline mint<MOD> & operator -= (mint<MOD> other) { this->value -= other.value; if (this->value < 0) this->value += MOD; return *this; } inline mint<MOD> & operator *= (mint<MOD> other) { this->value = (uint_fast64_t)this->value * other.value % MOD; return *this; } inline mint<MOD> operator - () const { return mint<MOD>(this->value ? MOD - this->value : 0, nullptr); } inline mint<MOD> pow(uint64_t k) const { return mint<MOD>(modpow(value, k, MOD), nullptr); } inline mint<MOD> inv() const { return mint<MOD>(modinv(value, MOD), nullptr); } inline mint<MOD> operator / (mint<MOD> other) const { return *this * other.inv(); } inline mint<MOD> operator /= (mint<MOD> other) { return *this *= other.inv(); } inline bool operator == (mint<MOD> other) const { return value == other.value; } inline bool operator != (mint<MOD> other) const { return value != other.value; } }; template <int32_t MOD> mint<MOD> operator * (int64_t value, mint<MOD> n) { return mint<MOD>(value) * n; } template <int32_t MOD> std::istream & operator >> (std::istream & in, mint<MOD> & n) { int64_t value; in >> value; n = value; return in; } template <int32_t MOD> std::ostream & operator << (std::ostream & out, mint<MOD> n) { return out << n.value; } #line 4 "main.cpp" using namespace std; constexpr int MOD = 1000000007; mint<MOD> solve(int n, int k, const vector<vector<int> > & g) { auto go = [&](auto && go, int x, int parent) -> pair<vector<mint<MOD> >, vector<mint<MOD> > > { vector<mint<MOD> > dp1(k, 1); vector<mint<MOD> > dp2(k); bool is_leaf = true; for (int y : g[x]) if (y != parent) { is_leaf = false; auto [sub1, sub2] = go(go, y, x); vector<mint<MOD> > acc1(k + 1); vector<mint<MOD> > acc2(k + 1); partial_sum(ALL(sub1), acc1.begin() + 1); partial_sum(ALL(sub2), acc2.begin() + 1); REP (i, k) { dp2[i] = dp2[i] * acc1[i + 1] + dp1[i] * (acc2[k] - acc2[i]) + dp1[i] * (acc1[k] - acc1[i + 1]); dp1[i] *= acc1[i + 1]; } } return {dp1, dp2}; }; constexpr int root = 0; auto [dp1, dp2] = go(go, root, -1); mint<MOD> ans = 0; ans += accumulate(ALL(dp1), mint<MOD>()); ans += accumulate(ALL(dp2), mint<MOD>()); return ans; } // generated by online-judge-template-generator v4.1.1 (https://github.com/kmyk/online-judge-template-generator) int main() { std::ios::sync_with_stdio(false); std::cin.tie(nullptr); constexpr char endl = '\n'; int n; cin >> n; int k; cin >> k; vector<vector<int> > g(n); REP (i, n - 1) { int a, b; cin >> a >> b; -- a; -- b; g[a].push_back(b); g[b].push_back(a); } auto ans = solve(n, k, g); cout << ans << endl; return 0; }