結果
問題 | No.898 tri-βutree |
ユーザー | iiljj |
提出日時 | 2020-06-11 23:56:49 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 223 ms / 4,000 ms |
コード長 | 9,781 bytes |
コンパイル時間 | 2,881 ms |
コンパイル使用メモリ | 218,648 KB |
実行使用メモリ | 30,648 KB |
最終ジャッジ日時 | 2024-11-08 23:44:54 |
合計ジャッジ時間 | 8,343 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 87 ms
30,648 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 2 ms
5,248 KB |
testcase_04 | AC | 2 ms
5,248 KB |
testcase_05 | AC | 2 ms
5,248 KB |
testcase_06 | AC | 2 ms
5,248 KB |
testcase_07 | AC | 205 ms
27,660 KB |
testcase_08 | AC | 214 ms
27,796 KB |
testcase_09 | AC | 217 ms
27,648 KB |
testcase_10 | AC | 218 ms
27,660 KB |
testcase_11 | AC | 209 ms
27,780 KB |
testcase_12 | AC | 218 ms
27,648 KB |
testcase_13 | AC | 220 ms
27,776 KB |
testcase_14 | AC | 220 ms
27,788 KB |
testcase_15 | AC | 212 ms
27,664 KB |
testcase_16 | AC | 214 ms
27,780 KB |
testcase_17 | AC | 214 ms
27,780 KB |
testcase_18 | AC | 218 ms
27,784 KB |
testcase_19 | AC | 220 ms
27,660 KB |
testcase_20 | AC | 213 ms
27,664 KB |
testcase_21 | AC | 223 ms
27,704 KB |
ソースコード
/* #region Head */ #include <bits/stdc++.h> using namespace std; using ll = long long; using ull = unsigned long long; using ld = long double; using pll = pair<ll, ll>; template <class T> using vc = vector<T>; template <class T> using vvc = vc<vc<T>>; using vll = vc<ll>; using vvll = vvc<ll>; using vld = vc<ld>; using vvld = vvc<ld>; using vs = vc<string>; using vvs = vvc<string>; template <class T, class U> using um = unordered_map<T, U>; template <class T> using pq = priority_queue<T>; template <class T> using pqa = priority_queue<T, vc<T>, greater<T>>; template <class T> using us = unordered_set<T>; #define REP(i, m, n) for (ll i = (m), i##_len = (ll)(n); i < i##_len; ++(i)) #define REPM(i, m, n) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; ++(i)) #define REPR(i, m, n) for (ll i = (m), i##_min = (ll)(n); i >= i##_min; --(i)) #define REPD(i, m, n, d) for (ll i = (m), i##_len = (ll)(n); i < i##_len; i += (d)) #define REPMD(i, m, n, d) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; i += (d)) #define REPI(itr, ds) for (auto itr = ds.begin(); itr != ds.end(); itr++) #define ALL(x) begin(x), end(x) #define SIZE(x) ((ll)(x).size()) #define PERM(c) \ sort(ALL(c)); \ for (bool c##p = 1; c##p; c##p = next_permutation(ALL(c))) #define UNIQ(v) v.erase(unique(ALL(v)), v.end()); #define endl '\n' #define sqrt sqrtl #define floor floorl #define log2 log2l constexpr ll INF = 1'010'000'000'000'000'017LL; constexpr ll MOD = 1'000'000'007LL; // 1e9 + 7 constexpr ld EPS = 1e-12; constexpr ld PI = 3.14159265358979323846; template <typename T> istream &operator>>(istream &is, vc<T> &vec) { // vector 入力 for (T &x : vec) is >> x; return is; } template <typename T> ostream &operator<<(ostream &os, vc<T> &vec) { // vector 出力 (for dump) os << "{"; REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "" : ", "); os << "}"; return os; } template <typename T> ostream &operator>>(ostream &os, vc<T> &vec) { // vector 出力 (inline) REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "\n" : " "); return os; } template <typename T, typename U> istream &operator>>(istream &is, pair<T, U> &pair_var) { // pair 入力 is >> pair_var.first >> pair_var.second; return is; } template <typename T, typename U> ostream &operator<<(ostream &os, pair<T, U> &pair_var) { // pair 出力 os << "(" << pair_var.first << ", " << pair_var.second << ")"; return os; } // map, um, set, us 出力 template <class T> ostream &out_iter(ostream &os, T &map_var) { os << "{"; REPI(itr, map_var) { os << *itr; auto itrcp = itr; if (++itrcp != map_var.end()) os << ", "; } return os << "}"; } template <typename T, typename U> ostream &operator<<(ostream &os, map<T, U> &map_var) { return out_iter(os, map_var); } template <typename T, typename U> ostream &operator<<(ostream &os, um<T, U> &map_var) { os << "{"; REPI(itr, map_var) { auto [key, value] = *itr; os << "(" << key << ", " << value << ")"; auto itrcp = itr; if (++itrcp != map_var.end()) os << ", "; } os << "}"; return os; } template <typename T> ostream &operator<<(ostream &os, set<T> &set_var) { return out_iter(os, set_var); } template <typename T> ostream &operator<<(ostream &os, us<T> &set_var) { return out_iter(os, set_var); } template <typename T> ostream &operator<<(ostream &os, pq<T> &pq_var) { pq<T> pq_cp(pq_var); os << "{"; if (!pq_cp.empty()) { os << pq_cp.top(), pq_cp.pop(); while (!pq_cp.empty()) os << ", " << pq_cp.top(), pq_cp.pop(); } return os << "}"; } // dump #define DUMPOUT cerr void dump_func() { DUMPOUT << endl; } template <class Head, class... Tail> void dump_func(Head &&head, Tail &&... tail) { DUMPOUT << head; if (sizeof...(Tail) > 0) DUMPOUT << ", "; dump_func(move(tail)...); } // chmax (更新「される」かもしれない値が前) template <typename T, typename U, typename Comp = less<>> bool chmax(T &xmax, const U &x, Comp comp = {}) { if (comp(xmax, x)) { xmax = x; return true; } return false; } // chmin (更新「される」かもしれない値が前) template <typename T, typename U, typename Comp = less<>> bool chmin(T &xmin, const U &x, Comp comp = {}) { if (comp(x, xmin)) { xmin = x; return true; } return false; } // ローカル用 #define DEBUG_ #ifdef DEBUG_ #define DEB #define dump(...) \ DUMPOUT << " " << string(#__VA_ARGS__) << ": " \ << "[" << to_string(__LINE__) << ":" << __FUNCTION__ << "]" << endl \ << " ", \ dump_func(__VA_ARGS__) #else #define DEB if (false) #define dump(...) #endif struct AtCoderInitialize { static constexpr int IOS_PREC = 15; static constexpr bool AUTOFLUSH = false; AtCoderInitialize() { ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr); cout << fixed << setprecision(IOS_PREC); if (AUTOFLUSH) cout << unitbuf; } } ATCODER_INITIALIZE; string yes = "Yes", no = "No"; // string yes = "YES", no = "NO"; void yn(bool p) { cout << (p ? yes : no) << endl; } /* #endregion */ /* #region Graph */ // エッジ(本来エッジは双方向だが,ここでは単方向で管理) template <class weight_t, class flow_t> struct Edge { ll src; // エッジ始点となる頂点 ll dst; // エッジ終点となる頂点 weight_t weight; // 重み flow_t cap; Edge() : src(0), dst(0), weight(0) {} Edge(ll src, ll dst, weight_t weight) : src(src), dst(dst), weight(weight) {} Edge(ll src, ll dst, weight_t weight, flow_t cap) : src(src), dst(dst), weight(weight), cap(cap) {} // Edge 標準出力 friend ostream &operator<<(ostream &os, Edge &edge) { os << "(" << edge.src << " -> " << edge.dst << ", " << edge.weight << ")"; return os; } }; // 同じ頂点を始点とするエッジ集合 template <class weight_t, class flow_t> class Node : public vc<Edge<weight_t, flow_t>> { public: ll idx; Node() : vc<Edge<weight_t, flow_t>>() {} // void add(int a, int b, weight_t w, flow_t cap) { this->emplace_back(a, b, w, cap); }; }; // graph[i] := 頂点 i を始点とするエッジ集合 template <class weight_t, class flow_t> class Graph : public vc<Node<weight_t, flow_t>> { public: Graph() : vc<Node<weight_t, flow_t>>() {} Graph(int n) : vc<Node<weight_t, flow_t>>(n) { REP(i, 0, n)(*this)[i].idx = i; } // 単方向 void add_arc(int a, int b, weight_t w = 1, flow_t cap = 1) { (*this)[a].emplace_back(a, b, w, cap); } // 双方向 void add_edge(int a, int b, weight_t w = 1, flow_t cap = 1) { add_arc(a, b, w, cap), add_arc(b, a, w, cap); } }; // using Array = vc<Weight>; // using Matrix = vc<Array>; /* #endregion */ template <class weight_t, class flow_t> class LCA { public: const int n = 0; const int log2_n = 0; vc<vc<int>> parent; vc<int> depth; using G = Graph<weight_t, flow_t>; LCA() {} LCA(const G &g, int root) : n(g.size()), log2_n(log2(n) + 1), parent(log2_n, vc<int>(n)), depth(n) { dfs(g, root, -1, 0); for (int k = 0; k + 1 < log2_n; k++) { for (int v = 0; v < (int)g.size(); v++) { if (parent[k][v] < 0) parent[k + 1][v] = -1; else parent[k + 1][v] = parent[k][parent[k][v]]; } } } // 根からの距離と1つ先の頂点を求める void dfs(const G &g, int v, int p, int d) { parent[0][v] = p; depth[v] = d; for (auto &e : g[v]) { if (e.dst != p) dfs(g, e.dst, v, d + 1); } } int get(int u, int v) { if (depth[u] > depth[v]) std::swap(u, v); // LCA までの距離を同じにする for (int k = 0; k < log2_n; k++) { if ((depth[v] - depth[u]) >> k & 1) { v = parent[k][v]; } } if (u == v) return u; // 二分探索で LCA を求める for (int k = log2_n - 1; k >= 0; k--) { if (parent[k][u] != parent[k][v]) { u = parent[k][u]; v = parent[k][v]; } } return parent[0][u]; } }; // Problem void solve() { ll n; cin >> n; vll u(n - 1), v(n - 1), w(n - 1); REP(i, 0, n - 1) cin >> u[i] >> v[i] >> w[i]; ll q; cin >> q; vll x(q), y(q), z(q); REP(i, 0, q) cin >> x[i] >> y[i] >> z[i]; Graph<ll, ll> graph(n); REP(i, 0, n - 1) graph.add_edge(u[i], v[i], w[i]); vll depth(n); auto dfs_depth = [&](auto &&dfs_depth, int idx, int par, ll d) -> void { depth[idx] = d; for (Edge<ll, ll> &e : graph[idx]) { if (e.dst != par) dfs_depth(dfs_depth, e.dst, idx, d + e.weight); } }; dfs_depth(dfs_depth, 0, -1, 0); LCA<ll, ll> lca(graph, 0); auto f = [&](ll a, ll b) -> ll { ll lcaidx = lca.get(a, b); return depth[a] + depth[b] - 2 * depth[lcaidx]; }; REP(i, 0, q) { cout << ((f(x[i], y[i]) + f(y[i], z[i]) + f(z[i], x[i])) / 2) << endl; } } // entry point int main() { solve(); return 0; }