結果
問題 | No.1078 I love Matrix Construction |
ユーザー | hitonanode |
提出日時 | 2020-06-12 21:37:03 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 228 ms / 2,000 ms |
コード長 | 6,911 bytes |
コンパイル時間 | 2,781 ms |
コンパイル使用メモリ | 211,872 KB |
実行使用メモリ | 51,012 KB |
最終ジャッジ日時 | 2024-06-24 04:35:25 |
合計ジャッジ時間 | 6,872 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 24 ms
10,496 KB |
testcase_03 | AC | 71 ms
21,552 KB |
testcase_04 | AC | 101 ms
28,356 KB |
testcase_05 | AC | 87 ms
24,172 KB |
testcase_06 | AC | 22 ms
10,240 KB |
testcase_07 | AC | 8 ms
6,944 KB |
testcase_08 | AC | 88 ms
24,532 KB |
testcase_09 | AC | 5 ms
6,944 KB |
testcase_10 | AC | 228 ms
51,012 KB |
testcase_11 | AC | 114 ms
29,444 KB |
testcase_12 | AC | 179 ms
42,988 KB |
testcase_13 | AC | 206 ms
47,724 KB |
testcase_14 | AC | 139 ms
34,572 KB |
testcase_15 | AC | 196 ms
45,440 KB |
testcase_16 | AC | 7 ms
6,944 KB |
testcase_17 | AC | 2 ms
6,940 KB |
testcase_18 | AC | 14 ms
8,448 KB |
testcase_19 | AC | 38 ms
14,928 KB |
testcase_20 | AC | 33 ms
14,668 KB |
testcase_21 | AC | 3 ms
6,944 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; using lint = long long int; using pint = pair<int, int>; using plint = pair<lint, lint>; struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define ALL(x) (x).begin(), (x).end() #define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++) #define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--) #define REP(i, n) FOR(i,0,n) #define IREP(i, n) IFOR(i,0,n) template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); } template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); } template<typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; } template<typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; } template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); } template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); } template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; } template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } #define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl; /* #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/tag_and_trait.hpp> using namespace __gnu_pbds; // find_by_order(), order_of_key() template<typename TK> using pbds_set = tree<TK, null_type, less<TK>, rb_tree_tag, tree_order_statistics_node_update>; template<typename TK, typename TV> using pbds_map = tree<TK, TV, less<TK>, rb_tree_tag, tree_order_statistics_node_update>; */ // Directed graph library to find strongly connected components (強連結成分分解) // 0-indexed directed graph // Complexity: O(V + E) struct DirectedGraphSCC { int V; // # of Vertices std::vector<std::vector<int>> to, from; std::vector<int> used; // Only true/false std::vector<int> vs; std::vector<int> cmp; int scc_num = -1; DirectedGraphSCC(int V = 0) : V(V), to(V), from(V), cmp(V) {} void _dfs(int v) { used[v] = true; for (auto t : to[v]) if (!used[t]) _dfs(t); vs.push_back(v); } void _rdfs(int v, int k) { used[v] = true; cmp[v] = k; for (auto t : from[v]) if (!used[t]) _rdfs(t, k); } void add_edge(int from_, int to_) { assert(from_ >= 0 and from_ < V and to_ >= 0 and to_ < V); to[from_].push_back(to_); from[to_].push_back(from_); } // Detect strongly connected components and return # of them. // Also, assign each vertex `v` the scc id `cmp[v]` (0-indexed) int FindStronglyConnectedComponents() { used.assign(V, false); vs.clear(); for (int v = 0; v < V; v++) if (!used[v]) _dfs(v); used.assign(V, false); scc_num = 0; for (int i = (int)vs.size() - 1; i >= 0; i--) if (!used[vs[i]]) _rdfs(vs[i], scc_num++); return scc_num; } // After calling `FindStronglyConnectedComponents()`, generate a new graph by uniting all vertices // belonging to the same component(The resultant graph is DAG). DirectedGraphSCC GenerateTopologicalGraph() { DirectedGraphSCC newgraph(scc_num); for (int s = 0; s < V; s++) for (auto t : to[s]) { if (cmp[s] != cmp[t]) newgraph.add_edge(cmp[s], cmp[t]); } return newgraph; } }; // 2-SAT solver: Find a solution for `(Ai v Aj) ^ (Ak v Al) ^ ... = true` // - `nb_sat_vars`: Number of variables // - Considering a graph with `2 * nb_sat_vars` vertices // - Vertices [0, nb_sat_vars) means `Ai` // - vertices [nb_sat_vars, 2 * nb_sat_vars) means `not Ai` struct SATSolver : DirectedGraphSCC { int nb_sat_vars; std::vector<int> solution; SATSolver(int nb_variables = 0) : DirectedGraphSCC(nb_variables * 2), nb_sat_vars(nb_variables), solution(nb_sat_vars) {} void add_x_or_y_constraint(bool is_x_true, int x, bool is_y_true, int y) { assert(x >= 0 and x < nb_sat_vars); assert(y >= 0 and y < nb_sat_vars); if (!is_x_true) x += nb_sat_vars; if (!is_y_true) y += nb_sat_vars; add_edge((x + nb_sat_vars) % (nb_sat_vars * 2), y); add_edge((y + nb_sat_vars) % (nb_sat_vars * 2), x); } // Solve the 2-SAT problem. If no solution exists, return `false`. // Otherwise, dump one solution to `solution` and return `true`. bool run() { FindStronglyConnectedComponents(); for (int i = 0; i < nb_sat_vars; i++) { if (cmp[i] == cmp[i + nb_sat_vars]) return false; solution[i] = cmp[i] > cmp[i + nb_sat_vars]; } return true; } }; int main() { int N; cin >> N; vector<int> S(N), T(N), U(N); cin >> S >> T >> U; SATSolver sat(N * N); REP(i, N) { bool b1 = U[i] % 2; bool b2 = U[i] / 2; REP(j, N) sat.add_x_or_y_constraint(!b1, (S[i] - 1) * N + j, !b2, j * N + (T[i] - 1)); } if (!sat.run()) puts("-1"); else { REP(i, N) { REP(j, N) cout << sat.solution[i * N + j] << ' '; cout << '\n'; } } }