結果
| 問題 | 
                            No.1078 I love Matrix Construction
                             | 
                    
| コンテスト | |
| ユーザー | 
                             Salmonize
                         | 
                    
| 提出日時 | 2020-06-12 22:16:17 | 
| 言語 | Python3  (3.13.1 + numpy 2.2.1 + scipy 1.14.1)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 1,674 bytes | 
| コンパイル時間 | 417 ms | 
| コンパイル使用メモリ | 12,928 KB | 
| 実行使用メモリ | 133,492 KB | 
| 最終ジャッジ日時 | 2024-06-24 05:10:52 | 
| 合計ジャッジ時間 | 15,260 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge5 / judge4 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 5 WA * 5 RE * 12 | 
ソースコード
import sys
readline = sys.stdin.readline
readall = sys.stdin.read
ns = lambda: readline().rstrip()
ni = lambda: int(readline().rstrip())
nm = lambda: map(int, readline().split())
nl = lambda: list(map(int, readline().split()))
prn = lambda x: print(*x, sep='\n')
def SCC(N, G, RG):
    order = []
    used = [0]*N
    group = [None]*N
    def dfs(s):
        used[s] = 1
        for t in G[s]:
            if not used[t]:
                dfs(t)
        order.append(s)
    def rdfs(s, col):
        group[s] = col
        used[s] = 1
        for t in RG[s]:
            if not used[t]:
                rdfs(t, col)
    for i in range(N):
        if not used[i]:
            dfs(i)
    used = [0]*N
    label = 0
    for s in reversed(order):
        if not used[s]:
            rdfs(s, label)
            label += 1
    return label, group
def solve():
    n = ni()
    s = [x-1 for x in nl()]
    t = [x-1 for x in nl()]
    u = nl()
    m = 2 * n ** 2
    G = [list() for _ in range(m)]
    rG = [list() for _ in range(m)]
    for i in range(n):
        cs, ct, cu = s[i], t[i], u[i]
        for j in range(n):
            x = [cs * n + j, cs * n + j + n**2]
            y = [j * n + ct, j * n + ct + n**2]
            G[x[cu & 1]].append(y[(cu >> 1) ^ 1])
            rG[y[(cu >> 1) ^ 1]].append(x[cu & 1])
            G[y[cu >> 1]].append(x[cu & 1 ^ 1])
            rG[x[cu & 1 ^ 1]].append(y[cu >> 1])
    _, gr = SCC(m, G, rG)
    ret = [0]*n**2
    for i in range(n**2):
        if gr[i] == gr[i+n**2]:
            print(-1)
            return
        ret[i] = int(gr[i] > gr[i+n**2])
    for i in range(n):
        print(*ret[i*n:(i+1)*n])
    return
solve()
            
            
            
        
            
Salmonize