結果
問題 | No.1084 積の積 |
ユーザー |
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提出日時 | 2020-06-19 21:40:34 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 406 ms / 2,000 ms |
コード長 | 6,137 bytes |
コンパイル時間 | 2,090 ms |
コンパイル使用メモリ | 179,388 KB |
実行使用メモリ | 16,668 KB |
最終ジャッジ日時 | 2024-07-03 14:09:25 |
合計ジャッジ時間 | 8,414 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 27 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define DEBUG(x) cerr<<#x<<": "<<x<<endl;#define DEBUG_VEC(v) cerr<<#v<<":";for(int i=0;i<v.size();i++) cerr<<" "<<v[i]; cerr<<endl;#define DEBUG_MAT(v) cerr<<#v<<endl;for(int i=0;i<v.size();i++){for(int j=0;j<v[i].size();j++) {cerr<<v[i][j]<<" ";}cerr<<endl;}typedef long long ll;#define int ll#define vi vector<int>#define vl vector<ll>#define vii vector< vector<int> >#define vll vector< vector<ll> >#define vs vector<string>#define pii pair<int,int>#define pis pair<int,string>#define psi pair<string,int>#define pll pair<ll,ll>template<class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first + t.first, s.second + t.second); }template<class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first - t.first, s.second - t.second); }template<class S, class T> ostream& operator<<(ostream& os, pair<S, T> p) { os << "(" << p.first << ", " << p.second << ")"; return os; }#define X first#define Y second#define rep(i,n) for(int i=0;i<(int)(n);i++)#define rep1(i,n) for(int i=1;i<=(int)(n);i++)#define rrep(i,n) for(int i=(int)(n)-1;i>=0;i--)#define rrep1(i,n) for(int i=(int)(n);i>0;i--)#define REP(i,a,b) for(int i=a;i<b;i++)#define in(x, a, b) (a <= x && x < b)#define all(c) c.begin(),c.end()template<class T> bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }template<class T> bool chmin(T &a, const T &b) { if (a>b) { a = b; return 1; } return 0; }#define UNIQUE(v) v.erase(std::unique(v.begin(), v.end()), v.end());const ll inf = 1000000001;const ll INF = (ll)1e18 + 1;const long double pi = 3.1415926535897932384626433832795028841971L;#define Sp(p) cout<<setprecision(25)<< fixed<<p<<endl;int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 };// vi dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};// vi dx2 = { 1,1,0,-1,-1,-1,0,1 }, dy2 = { 0,1,1,1,0,-1,-1,-1 };#define fio() cin.tie(0); ios::sync_with_stdio(false);const ll MOD = 1000000007;// const ll MOD = 998244353;// #define mp make_pair//#define endl '\n'const int MAXN = 555555;vl fact(MAXN);vl rfact(MAXN);ll mod_pow(ll x, ll p, ll M = MOD) {if (p < 0) {x = mod_pow(x, M - 2, M);p = -p;}ll a = 1;while (p) {if (p % 2)a = a*x%M;x = x*x%M;p /= 2;}return a;}ll mod_inverse(ll a, ll M = MOD) {return mod_pow(a, M - 2, M);}void set_fact(ll n, ll M = MOD) {fact[0] = fact[1] = rfact[0] = rfact[1] = 1;for (ll i = 2; i <= n; i++) {fact[i] = i * fact[i - 1] % M;// rfact[i] = mod_inverse(fact[i], M);}}//http://drken1215.hatenablog.com/entry/2018/06/08/210000//n���傫��fact���v�Z�ł��Ȃ��Ƃ��̂ق��̌v�Z���@�ɂ·��ď����Ă���ll nCr(ll n, ll r, ll M = MOD) {if (r > n) return 0;assert(fact[2] == 2);ll ret = fact[n];if (rfact[r] == 0) {rfact[r] = mod_inverse(fact[r], M);}ret = (ret*rfact[r]) % M;if (rfact[n - r] == 0) {rfact[n - r] = mod_inverse(fact[n - r], M);}ret = (ret*rfact[n - r]) % M;return ret;}ll nHr(ll n, ll r) {return nCr(n+r-1, r);}template <typename T>class SegmentTree {public:using F = function<T(T&, T&)>;int n;vector<T > dat;T e; // �P�ʌ�F query_func;F update_func;SegmentTree(vector<T> a, F query_func, F update_func, T e) :n(a.size()), query_func(query_func), update_func(update_func), e(e) {dat.resize(4 * n);init(0, 0, n, a);}void init(int k, int l, int r, vector<T> &a) {if (r - l == 1) {dat[k] = a[l];}else {int lch = 2 * k + 1, rch = 2 * k + 2;init(lch, l, (l + r) / 2, a);init(rch, (l + r) / 2, r, a);dat[k] = query_func(dat[lch], dat[rch]);}}//k�Ԗڂ̒l��a�ɕύXvoid update(int k, T a, int v, int l, int r) {if (r - l == 1) {dat[v] = update_func(dat[v], a);}else {if (k < (l + r) / 2)update(k, a, 2 * v + 1, l, (l + r) / 2);else {update(k, a, 2 * v + 2, (l + r) / 2, r);}dat[v] = query_func(dat[v * 2 + 1], dat[v * 2 + 2]);}}//[a,b)�̍ŏ��l�����߂�//���̂ق��̈����͌v�Z�̊ȒP�̂��߂̈���//k�͐ړ_�̔ԍ�,l,r�͂��̐ړ_��[l,r)�ɑΉ����Ă��邱�Ƃ�\��//�]���āA�O�����query(a,b,0,0,n)�Ƃ��Ă��T query(int a, int b, int k, int l, int r) {if (r <= a || b <= l) {return e;}if (a <= l && r <= b) {return dat[k];}else {T ul = query(a, b, k * 2 + 1, l, (l + r) / 2);T ur = query(a, b, k * 2 + 2, (l + r) / 2, r);return query_func(ul, ur);}}// ���������ĉE��T��int find(int a, int b, int k, int l, int r, int x) {// ������if (dat[k] < x || r <= a || b <= l) return -1;if (l + 1 == r) {// ������if (dat[k] >= x) return l;else return -1;}int rv = find(a, b, 2 * k + 2, (l + r) / 2, r, x);if (rv != -1) return rv;return find(a, b, 2 * k + 1, l, (l + r) / 2, x);}};ll f(ll a, ll b) {ll temp = 1e9;if (max(a, b) == temp) return temp;ll res = a * b;return min(res, temp);}ll g(ll a, ll b) {return b;}signed main() {fio();int n;cin >> n;vl a(n);bool zero = false;rep (i, n) {cin >> a[i];if (a[i] == 0) zero = true;}if (zero) {cout << 0 << endl;return 0;}SegmentTree<ll> seg(a, f, g, 1);ll mm = 1e9;vl temp(n);rep (i, n) {int ng = n + 1, ok = i + 1;while (ok + 1 < ng) {int mid = (ng + ok) / 2;if (seg.query(i, mid, 0, 0, seg.n) < mm) ok = mid;else ng = mid;}temp[ok - 1]++;if (i - 1 >= 0) {temp[i - 1]--;temp[i - 1] -= ok - i;if (i - 2 >= 0) {temp[i - 2] += ok - i;}}}for (int i = n - 2; i >= 0; i--) {temp[i] += temp[i + 1];}for (int i = n - 2; i >= 0; i--) {temp[i] += temp[i + 1];}ll ans = 1;for (int i = 0; i < n; i++) {ans *= mod_pow(a[i], temp[i]);ans %= MOD;}cout << ans << endl;}