結果

問題 No.1085 桁和の桁和
ユーザー firiexp
提出日時 2020-06-19 21:41:25
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 94 ms / 2,000 ms
コード長 2,943 bytes
コンパイル時間 1,302 ms
コンパイル使用メモリ 105,124 KB
最終ジャッジ日時 2025-01-11 05:59:01
ジャッジサーバーID
（参考情報） 		judge5 / judge5
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ファイルパターン 結果
sample AC * 4
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <numeric>
#include <bitset>
#include <cmath>
static const int MOD = 1000000007;
using ll = long long;
using u32 = unsigned;
using u64 = unsigned long long;
using namespace std;
template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;
template <class T, class U>
vector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }
template<class... Ts, class U>
auto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }
template<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }
template<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }
template<u32 M = 1000000007>
struct modint{
    u32 val;
    modint(): val(0){}
    template<typename T>
    modint(T t){t %= (T)M; if(t < 0) t += (T)M; val = t;}
    modint pow(ll k) const {
        modint res(1), x(val);
        while(k){
            if(k&1) res *= x;
            x *= x;
            k >>= 1;
        }
        return res;
    }
    template<typename T>
    modint& operator=(T t){t %= (T)M; if(t < 0) t += (T)M; val = t; return *this;}
    modint inv() const {return pow(M-2);}
    modint& operator+=(modint a){val += a.val; if(val >= M) val -= M; return *this;}
    modint& operator-=(modint a){if(val < a.val) val += M-a.val; else val -= a.val; return *this;}
    modint& operator*=(modint a){val = (u64)val*a.val%M; return *this;}
    modint& operator/=(modint a){return (*this) *= a.inv();}
    modint operator+(modint a) const {return modint(val) +=a;}
    modint operator-(modint a) const {return modint(val) -=a;}
    modint operator*(modint a) const {return modint(val) *=a;}
    modint operator/(modint a) const {return modint(val) /=a;}
    modint operator-(){return modint(M-val);}
    bool operator==(const modint a) const {return val == a.val;}
    bool operator!=(const modint a) const {return val != a.val;}
    bool operator<(const modint a) const {return val < a.val;}
};
using mint = modint<MOD>;
int main() {
    int d;
    string s;
    cin >> s >> d;
    int n = s.size();
    auto dp = make_v(n+1, 2, 9, mint(0));
    dp[0][1][0] = 1;
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < 2; ++j) {
            for (int k = 0; k < 9; ++k) {
                if(s[i] == '?'){
                    for (int l = 0; l < 10; ++l) {
                        dp[i+1][j&(l == 0)][(k+l)%9] += dp[i][j][k];
                    }
                }else {
                    int l = (s[i]-'0')%10;
                    dp[i+1][j&(l == 0)][(k+l)%9] += dp[i][j][k];
                }
            }
        }
    }
    if(d == 0){
        printf("%d\n", dp.back()[1][0].val);
    }else if(d == 9) {
        printf("%d\n", dp.back()[0][0].val);
    }else {
        printf("%d\n", dp.back()[0][d].val);
    }
    return 0;
}
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